I want to extract the numbers from some strings and enclose them into ... It's something like this:
$string1 = "Up to 3 bedrooms";
$string2 = "With 2 and 3 (wathever)";
echo myMagicFunction($string1); // Up to <span>3</span> bedrooms.
echo myMagicFunction($string2); // With <span>2</span> and <span>3</span> (wathever).
I think I could use preg_replace, but i dont know how...
Tks...
function myMagicFunction($str)
{
return preg_replace('/\d+/', '<span>$0</span>', $str);
}
\d+ to match successive digits, $0 to put match in the replacement string
function myMagicFunction($string) {
return preg_replace('/\d+/', '<span>$0</span>', $string);
}
EDIT: Exactly the same function got posted 1 minute before. I guess there is a definite answer here.
Try this...
$tok = strtok($string1, ' ');
$result = "";
while ($tok !== false) {
if ( is_numeric($tok) )
$result .= "<span>" . $tok . "</span>";
else
$result .= $tok;
$tok = strtok(" \n\t");
}
Related
I am trying to check if word is occur in a string but not to be the first and last word, if its true then remove the space after and before of the word and replace with a underscore.
Input:
$str = 'This is a cool area";
Output:
$str = 'This is a_cool_area";
I want to check that the word 'cool' is inside the string but not a first and last word. if yes the remove the space & replace with '_'
You can use preg_replace to do this job, using this regex:
/(?<=\w)\s+(' . $word . ')\s+(?=\w)/i
which looks for the word, surrounded by at least one word character on either side (to prevent matching at the beginning or ending of the sentence). Usage in PHP:
$str = 'This is a cool area';
$word = 'cool';
$str = preg_replace('/(?<=\w)\s+(' . $word . ')\s+(?=\w)/i', '_$1_', $str);
echo $str . "\n";
$str = ' Cool areas are cool ';
$str = preg_replace('/(?<=\w)\s+(' . $word . ')\s+(?=\w)/i', '_$1_', $str);
echo $str . "\n";
Output:
This is a_cool_area
Cool areas are cool
Demo on 3v4l.org
function checkWord($str, $word)
{
$arr = explode(" ", $str);
$newArr = array_slice($arr, 1, -1);
$key = array_search($word, $newArr);
if($key !== false)
{
return implode('_',array_slice($arr, $key, 3));
}
else
{
return $str;
}
}
echo checkWord('This is a cool area', 'cool');
Objective: strings with ' should match the string without it.
Example:
$first_string = "alex ern o'brian";
$second_string = "alex-ern o brian";
$pattern = array("/(-|\.| )/", "/(')/");
$replace = array(' ', '(\s|)');
$first_string = preg_replace($pattern, $replace, $first_string);
$second_string = preg_replace($pattern, $replace, $second_string);
$first_string_split = preg_split("/(-|\.| )/", $first_string);
$first_string_split[] = $first_string;
$second_string_split = preg_split("/(-|\.| )/", $second_string);
$second_string_split[] = $second_string;
$first_string = array_slice($first_string_split, -1)[0];
$second_string = array_slice($second_string_split, -1)[0];
if(in_array($first_string, $second_string_split) || in_array($second_string, $first_string_split))
{
echo 'true';
} else {
echo 'false';
}
I think you are expecting this.
Solution 1: Try this code snippet here
Regex: (\s|) this will match either space or null.
<?php
ini_set('display_errors', 1);
$string = "o'brian";
$string=str_replace("'", "(\s|)",$string);
$list = array("o'neal", "o brian", "obrian");
$result=array();
foreach($list as $value)
{
if(preg_match("/$string/", $value))
{
$result[]=$value;
}
}
print_r($result);
Solution 2:
Regex: [a-z]+ will match character from a to z.
$string1="o brian";
$string2="obrian";
if(preg_match("/".implode(" ", $matches[0])."/", $string1))
{
echo "matched";
}
if( preg_match("/".implode("", $matches[0])."/", $string2))
{
echo "matched";
}
I'm not sure if I got your question right, but this should do it:
(?<=\w)'(?=\w)
It matches every ' character, which is followed and preceded by a word character. The word character \w is equal to [a-zA-Z0-9_].
Here is a live example to test the regex
Here is a live PHP example
I need to find out if there are any redundant words in string or not .Is there any function that can provide me result in true/false.
Example:
$str = "Hey! How are you";
$result = redundant($str);
echo $result ; //result should be 0 or false
But for :
$str = "Hey! How are are you";
$result = redundant($str);
echo $result ; //result should be 1 or true
Thank you
You could use explode to generate an array containing all words in your string:
$array = explode(" ", $str);
Than you could prove if the arrays contains duplicates with the function provided in this answer:
https://stackoverflow.com/a/3145660/5420511
I think this is what you are trying to do, this splits on punctuation marks or whitespaces. The commented out lines can be used if you want the duplicated words:
$str = "Hey! How are are you?";
$output = redundant($str);
echo $output;
function redundant($string){
$words = preg_split('/[[:punct:]\s]+/', $string);
if(max(array_count_values($words)) > 1) {
return 1;
} else {
return 0;
}
//foreach(array_count_values($words) as $word => $count) {
// if($count > 1) {
// echo '"' . $word . '" is in the string more than once';
// }
//}
}
References:
http://php.net/manual/en/function.array-count-values.php
http://php.net/manual/en/function.max.php
http://php.net/manual/en/function.preg-split.php
Regex Demo: https://regex101.com/r/iH0eA6/1
In JS you can do:
var chs = "[](){}";
var str = "hello[asd]}";
if (str.indexOf(chs) != -1) {
alert("The string can't contain the following characters: " + chs.split("").join(", "));
}
How can you do this in PHP (replacing alert with echo)?
I do not want to use a regex for the simplicity of what I think.
EDIT:
What I've tried:
<?php
$chs = /[\[\]\(\)\{\}]/;
$str = "hella[asd]}";
if (preg_match(chs, str)) {
echo ("The string can't contain the following characters: " . $chs);
}
?>
Which obviously doesn't work and idk how to do it without regex.
In php you should do this:
$string = "Sometring[inside]";
if(preg_match("/(?:\[|\]|\(|\)|\{|\})+/", $string) === FALSE)
{
echo "it does not contain.";
}
else
{
echo "it contains";
}
The regex says check to see any of the characters are inside the string. you can read more about it here:
http://en.wikipedia.org/wiki/Regular_expression
And about PHP preg_match() :
http://php.net/manual/en/function.preg-match.php
Update:
I have written an updated regex for this, which captures the letters inside:
$rule = "/(?:(?:\[([\s\da-zA-Z]+)\])|\{([\d\sa-zA-Z]+)\})|\(([\d\sa-zA-Z]+)\)+/"
$matches = array();
if(preg_match($rule, $string, $matches) === true)
{
echo "It contains: " . $matches[0];
}
It returnes something like this:
It contains: [inside]
I have changed the regex only which becomes:
$rule = "/(?:(?:(\[)(?:[\s\da-zA-Z]+)(\]))|(\{)(?:[\d\sa-zA-Z]+)(\}))|(\()(?:[\d\sa-zA-Z]+)(\))+/";
// it returns an array of occurred illegal characters
It now returns [] for this "I am [good]"
Why not you try str_replace.
<?php
$search = array('[',']','{','}','(',')');
$replace = array('');
$content = 'hella[asd]}';
echo str_replace($search, $replace, $content);
//Output => hellaasd
?>
Instead of regex we can use string replace for this case.
here is a simple solution without using regex:
$chs = array("[", "]", "(", ")", "{", "}");
$string = "hello[asd]}";
$err = array();
foreach($chs AS $key => $val)
{
if(strpos($string, $val) !== false) $err[]= $val;
}
if(count($err) > 0)
{
echo "The string can't contain the following characters: " . implode(", ", $err);
}
I need some help i have this code that Uppercase the first character of each word in a string with exceptions i need the function to ignore the exception if it's at the beginning of the string:
function ucwordss($str, $exceptions) {
$out = "";
foreach (explode(" ", $str) as $word) {
$out .= (!in_array($word, $exceptions)) ? strtoupper($word{0}) . substr($word, 1) . " " : $word . " ";
}
return rtrim($out);
}
$string = "my cat is going to the vet";
$ignore = array("is", "to", "the");
echo ucwordss($string, $ignore);
// Prints: My Cat is Going to the Vet
this is what im doing:
$string = "my cat is going to the vet";
$ignore = array("my", "is", "to", "the");
echo ucwordss($string, $ignore);
// Prints: my Cat is Going to the Vet
// NEED TO PRINT: My Cat is Going to the Vet
- return rtrim($out);
+ return ucfirst(rtrim($out));
Something like this:
function ucwordss($str, $exceptions) {
$out = "";
foreach (explode(" ", $str) as $key => $word) {
$out .= (!in_array($word, $exceptions) || $key == 0) ? strtoupper($word{0}) . substr($word, 1) . " " : $word . " ";
}
return rtrim($out);
}
Or even easier, before return in your function make strtoupper first letter
Do this really cheaply by just always uppercasing your first word:
function ucword($word){
return strtoupper($word{0}) . substr($word, 1) . " ";
}
function ucwordss($str, $exceptions) {
$out = "";
$words = explode(" ", $str);
$words[0] = ucword($words[0]);
foreach ($words as $word) {
$out .= (!in_array($word, $exceptions)) ? ucword($word) : $word . " ";
}
return rtrim($out);
}
what about you make the first letter in the string upper case so no matter your mix you will still come through
$string = "my cat is going to the vet";
$string = ucfirst($string);
$ignore = array("is", "to", "the");
echo ucwordss($string, $ignore);
this way you first letter of the string will always be upper case
preg_replace_callback() will allow you to express your conditional replacement logic in a loopless and dynamic fashion. Consider this approach that will suitably modify your sample data:
Code: (PHP Demo) (Pattern Demo)
$string = "my cat is going to the vet";
$ignore = array("my", "is", "to", "the");
$pattern = "~^[a-z]+|\b(?|" . implode("|", $ignore) . ")\b(*SKIP)(*FAIL)|[a-z]+~";
echo "$pattern\n---\n";
echo preg_replace_callback($pattern, function($m) {return ucfirst($m[0]);}, $string);
Output:
~^[a-z]+|\b(?|my|is|to|the)\b(*SKIP)(*FAIL)|[a-z]+~
---
My Cat is Going to the Vet
You see, the three piped portions of the pattern (in order) make these demands:
If the start of the string is a word, capitalize the first letter.
If a "whole word" (leveraging the \b word boundary metacharacter) is found in the "blacklist", disqualify the match and keep traversing the input string.
Else capitalize the first letter of every word.
Now, if you want to get particular about contractions and hyphenated words, then you only need to add ' and - to the [a-z] character classes like this: [a-z'-] (Pattern Demo)
If anyone has a fringe cases that will break my snippet (like "words" with special characters that need to be escaped by preg_quote()), you can offer them and I can offer a patch, but my original solution will adequately serve the posted question.