Insert values with if condition with mysqli - php

Question

I am trying to make register member page. If a new member insert an email which has been already exist, then there will be a notification saying that the email is exist. But if the email has not been exist, the values they insert in the form will be send to database.
I don't know what is wrong with my code bellow. It just blank and doesn't send anything to databse. I need a help.
<?php
//conection:
$link = mysqli_connect(".com","klaudia","intheclaud","elektro") or die("Error " . mysqli_error($link));
//consultation:
$member_id=$_GET['member_id'];
$member_name=ucwords(htmlspecialchars($_POST['member_name']));
$member_email=$_POST['member_email'];
$member_password=htmlspecialchars($_POST['member_password']);
$member_phone=$_POST['member_phone'];
$member_address_satu=ucwords(htmlspecialchars($_POST['member_address_satu']));
$member_address_dua=ucwords(htmlspecialchars($_POST['member_address_dua']));
$member_reference=$_POST['member_reference'];
$query = "SELECT * FROM member_registry WHERE member_email='$member_email '" or die("Error in the consult.." . mysqli_error($link));
//execute the query.
$result = $link->query($query);
if (mysqli_num_rows($result) > 0) {
echo "This email you are using has been registered before";
}
else {
mysqli_query($link, "INSERT INTO member_registry (
'member_id',
'member_name',
'member_email',
'member_password',
'member_phone',
'member_address_satu',
'member_address_dua',
'member_reference')
VALUES (0,1,2,3,4,5,6,7,8)";
?>
I have tried to check the connection and the database. Everything works fine here. When I insert someone name which has been in the table of the database, it will echo that the email already exist. and vice versa.
$query = "SELECT * FROM member_registry WHERE member_name='Klaudia '" or die("Error in the consult.." . mysqli_error($link));
//execute the query.
$result = $link->query($query);
if (mysqli_num_rows($result) > 0) {
echo "This email you are using has been registered before";
}
else {
echo "This email you are using has NOT been registered before";
}
[UPDATE]
mysqli_query($link, "INSERT INTO member_registry (
'member_id',
'member_name',
'member_email',
'member_password',
'member_phone',
'member_address_satu',
'member_address_dua',
'member_reference')
VALUES (0,1,2,3,4,5,6,7,8)");
}
?>

Answer 1

You shouldn't handle this by two separate queries (at least without a transaction).
Instead create a unique index that doesn't allow the same email address twice in the table and check for the specific ER_DUP_ENTRY error code to detect doublets.
sscce:
<?php
define('MYSQL_ER_DUP_ENTRY', 1062);
$mysqli = new mysqli('localhost', 'localonly', 'localonly', 'test');
if ($mysqli->connect_errno) {
trigger_error('connection failed', E_USER_ERROR);
}
$result = $mysqli->query('
CREATE TEMPORARY TABLE soFoo (
id int auto_increment,
email varchar(128),
primary key(id),
unique key(email)
)'
);
if ( !$result) {
trigger_error('create table failed', E_USER_ERROR);
}
$stmt = $mysqli->prepare('INSERT INTO soFoo (email) VALUES (?)');
if (!$stmt) {
trigger_error('prepare failed', E_USER_ERROR);
}
$result = $stmt->bind_param("s", $email);
if ( !$result) {
trigger_error('bind_param failed', E_USER_ERROR);
}
foreach( array('email1', 'email2', 'email1') as $n=>$email ) {
echo $n, ' ', $email;
$result = $stmt->execute();
if ( $result ) {
echo " ok\r\n";
}
else {
if ( MYSQL_ER_DUP_ENTRY==$stmt->errno ) { // <-- here's the test for the duplicate entry
echo " duplicate\r\n";
}
else {
var_dump($stmt->errno, $stmt->error);
}
}
}
prints
0 email1 ok
1 email2 ok
2 email1 duplicate

Answer 2

You have an error in your syntax. You don't close your function.
Also you shouldn't use single quotes around your coumn names.
mysqli_query($link, "INSERT INTO member_registry (
`member_id`,
`member_name`,
`member_email`,
`member_password`,
`member_phone`,
`member_address_satu`,
`member_address_dua`,
`member_reference`)
VALUES (0,1,2,3,4,5,6,7,8)");