I have this code on my view,
<div class="text-id-box">
<?php echo CHtml::textField($model,'id'); ?>
</div>
<div class="submit-box">
<?php echo CHtml::button('Search', array(
'submit' => array('SiteController/actionSearch',
array('id'=>$id)))); ?>
</div>
and my database:
id: varchar(8)
name: varchar(20)
location: varchar(50)
i wanna search id in my database, then return name, and location value. how to build its model and controller.
any help would be appreciated, thanks.
first generate the model using gii ref (http://www.yiiframework.com/doc/guide/1.1/en/topics.gii)
then you can add following function in your controller
public function actionSearch($id)
{
$model= new Yourmodel;
$model=Yourmodel::model()->findByPk($id);
//you will get the row for particular id
// and you can access it by $model->name $model->location
// render the required page and access to model object to get the name and location.
}
Related
Im new to Yii, and would appreciate any help.
I need to create a page with multiple choice poll. My models look like this:
PollQuestion:
id int
title varchar
PollAnswer
id char //one letter - answer option
title
question_id //FK pool_question(id)
PollResult
user_id int
question_id int //FK poll_question(id)
answers //will be stored like A,B,C
indicated_answer //alternaive answer specified by user
Sample question looks like:
What do you think about us?
(checkbox)A. Good
(checkbox)B.Bad
(checkbox)C.Other (indicate) (textbox goes here)
Im not sure if Im doing it right, my controller:
public function actionSurvey($user_id)
{
$model = [new PollResult];
foreach($model as $model_item){
$model_item->user_id= $user_id;
if ($model_item->load(Yii::$app->request->post())) {
//only one item received, why??
}
}
return $this->render('survey', ['model' => $model]);
}
View:
<?php $form = ActiveForm::begin(); ?>
<?php foreach(PollQuestion::find()->all() as $question) {?>
<?php foreach($model as $model_item) { ?>
<p><?=$question->title?></p>
<?= Html::activeHiddenInput($model_item , "user_id"); ?>
<?= $form->field($model_item, 'answers')->checkboxList(ArrayHelper::map($question->pollAnswers, 'id', 'title')?>
<?= $form->field($model_item, 'indicated_answer') ->textInput()?>
<?php } }?>
<div class="form-group">
<?= Html::submitButton(Yii::t('app', 'Send'), ['class' => 'btn btn-success' ]) ?> </div>
<?php ActiveForm::end(); ?>
The problem is that in controller i receive only one item in array. Im not sure what am I doing wrong.
My suggestion, you need an extra form model to do that.
You can see how to create form model on http://www.yiiframework.com/doc-2.0/guide-input-forms.html.
The form model you create at least has this attributes:
answers[]
indicated_answer[]
and you can save input from user to that attributes and save them into your ActiveRecord model.
It is correct that one model entry is returned. In your form, you are creating a single model and passing that to the form.
public function actionSurvey($user_id)
{
$model = [new PollResult];
// ...
return $this->render('survey', ['model' => $model]);
}
You can then expect a single model back.
Have a look at this related issue on how you can solve this.
Utilising Yii2.0 checkboxlist for Parent-child relation models
I have several tables and corresponding models, that is to say, Staffs, Dpmembers, Subjects and Positions tables.
In my Staff model I create hasOne on Department because I want to retrieve data from Department table which is working.
But I have also created more associations of hasMany on Dpmember, Subject and Position models because I want to save the corresponding staff records.
The view newstaff.ctp looks like this
<div class="staff form">
<?php echo $this->Form->create('Staff');?>
<h3><?php echo __('Add a new staff member'); ?></h3>
<?php
echo $this->Form->input('name');
echo $this->Form->input('marital',array('label'=>'Marital status','options'=>array('empty'=>'Choose status','Single'=>'Single','Divorced'=>'Divorced','Married'=>'Married')));
echo $this->Form->input('Children');
echo $this->Form->input('nationality');
echo $this->Form->input('location');
echo $this->Form->input('email');
echo $this->Form->input('phone',array('label'=>'Phone number'));
echo $this->Form->input('nextofkeen',array('label'=>'Next of keen'));
echo $this->Form->input('keenrelation',array('label'=>'Next of keen relationship','options'=>array('Choose option'=>'Choose option','Husband'=>'Husband','Wife'=>'Wife','Guardian'=>'Gaurdian','Child'=>'Child')));
echo $this->Form->input('school');
echo $this->Form->input('award');
echo $this->Form->input('schoolperiod');
echo $this->Form->input('workplace',array('label'=>'Workplace'));
echo $this->Form->input('workposition');
echo $this->Form->input('workperiod');
echo $this->Form->input('dpmember.department.',array('options'=>$department,'empty'=>'Choose Department','label'=>'Department'));
echo $this->Form->input('subject.subjcet',array('options'=>array('Choose option'=>'Choose option','Science'=>'Science','Social Studies'=>'Social studies','English'=>'English','Mathematics'=>'Mathematics'),'label'=>'Subject'));
echo $this->Form->input('position.role',array('options'=>array('Choose option'=>'Choose option','Class teacher'=>'Class teacher','Bursar'=>'Bursar','Cook'=>'Cook'),'label'=>'Position'));
echo $this->Form->submit('Save staff', array('class' => 'btn btn-success', 'title' => 'Click here to add the user') );
?>
<?php echo $this->Form->end(); ?>
</div>
My Staff Model Staff.php like this
<?php
class Staff extends AppModel{
public $hasOne = array(
'Department'=>array(
'className'=>'Department'
));
public $hasMany = array(
'Dpmember'=>array(
'className'=>'Dpmember',
'foreign_key'=>'Dpmember.staff_id'
),
'Subject'=>array(
'className'=>'Subject',
'foreign_key'=>'Subject.staff_id'
),
'Position'=>array(
'className'=>'Position',
'foreign_key'=>'Position.staff_id'
)
);
}
?>
In my StaffsController.php I have a function newstaff() with the code below
public function newstaff() {
/*Create a select form field for departments */
$department = $this->Staff->Department->find('list',array('fields'=>array('Department.title','Department.title')));
$this->set('department', $department);
/*End creation of a select form field for departments */
if (!empty($this->request->data)) {
debug($this->request->data); // returns all data
debug($this->Staff->Subject->subject); // has returned null
debug($this->Staff->Position->position); // has returned null
debug($this->Staff->Dpmember->departement); // has returned null
}
}
I don't know why but for some reason, I have not been able to found out. Running debug($this->request->data) returns expected data.
But accessing individual associated form fields returns null values not the expected data. Please help me.
Thank you
You seem to be using CakePHP 3.0 syntax, while using CakePHP 2.3. The data returned is an array in Cake 2, not an object. So the data is under array keys, like:
$this->request->data['Staff']['Subject']['subject'];
$this->request->data['Staff']['Position']['position'];
$this->request->data['Staff']['Dpmember']['departement'];
Well I think finally I have got the values which are not null. Since I created relationships or rather associations among the models and am using CakePHP 2.3 the right way is
$this->request->data['associateModel']['FormField'];
Therefore I was supposed to do.
$this->request['Subject']['subject'];
$this->request['Subject']['position'];
$this->request['Subject']['department'];
Thank you very much #Oldskool
I am a bit new to the Yii Framework. I am making a product selling website, which has 3 basic models
1. Users model containing the primary key id
2. Products model containing the primary key id
3. Orders model which is basically a mapping between the products and orders. It contains the fields product_id and user_id as foreign keys.
I have made a page where all the products are populated and the logged in user can click on a button on product box to order a particular product.
the code of the link is like this
<?php echo CHtml::link('Order Now',array('order',
'product_id'=>$model->id,
'user_id'=>Yii::app()->user->id)); ?>
(Q1) This is sending a GET request but I want to sent the details as post request. How to do this?
My default controller is the site controller. I have made an actionOrder method in this controller.
The code is:
if(Yii::app()->user->isGuest){
$this->redirect('login');
}else{
$model=new Orders;
if(isset($_POST['products_id']))
{
$model->attributes->products_id=$_POST['product_id'];
$model->attributes->users_id=Yii::app()->user->id;
if($model->save())
$this->redirect(array('index'));
}
$this->render('index');
}
But this code is showing bunch of errors. Also, (Q2) how can I put both products_id and users_id in a single array Orders so that I just have to write $_POST['orders']
Also, (Q3) how can I display a flash message after the save is successful?
Kindly help me to solve my 3 problems and sorry if you feel that the questions are too stupid.
Q1: If you want to use POST request, you're going to have to use a form of sorts, in this case the CActiveForm.
Controller:
public function actionOrder()
{
if(Yii::app()->user->isGuest)
$this->redirect('login');
else
{
$model=new Orders;
if(isset($_POST['Orders']))
{
$model->product_id=$_POST['Orders']['products_id'];
$model->users_id = Yii::app()->user->id;
if($model->save())
{
// Q3: set the flashmessage
Yii::app()->user->setFlash('ordered','The product has been ordered!');
$this->redirect(array('index'));
}
}
$this->render('index', array('model'=>$model)); //send the orders model to the view
}
}
View:
<!-- Q3: show the flash message if it's set -->
<?php if (Yii::app()->user->hasFlash('ordered')): ?>
<?php echo Yii::app()->user->getFlash('ordered'); ?>
<?php endif ?>
...
<?php $form=$this->beginWidget('CActiveForm', array('id'=>'order-form')); ?>
<?php echo $form->hiddenField($model,'products_id',array('value'=>$product->id)); ?> // please note the change of variable name
<?php echo CHtml::submitButton('Order Now'); ?>
<?php $this->endWidget(); ?>
Please note that I have changed the name of the product model variable $model to $product, because we will be using $model for the Orders model for the form.
Q2: In this case I set the users_id value in the controller, so $_POST['Orders'] only contains the value for products_id. In yii you can also mass assign your attributes with:
$model->attributes = $_POST['Orders']
Which basicly means $_POST['Orders'] is already an associative array containing the attribute names and values that are in your form.
Q3: The code shows you how to set and show a flash message after an order is succesfull.
First you have to declare forms send method, if you're using bootsrap it'll be like mine:
<?php $form = $this->beginWidget('bootstrap.widgets.TbActiveForm', array(
'action' => Yii::app()->createUrl($this->route),
'method' => 'post',
'id' => 'activity_timeRpt',
));
?>
Second if you want to send custom inputs, you have to specify, otherwise it'll be like
i'll be back to finish this
For your questions 1 and 2 I'd recomend you to use a CActiveForm class. For example
<?php $form = $this->beginWidget('CActiveForm', array(
'action' => 'you_action_here'
'method'=>'post' // this is optinal parameter, as 'post' is default value
)); ?>
<?php echo $form->textField($model,'product_id'); ?>
<?php echo $form->hiddenField($model,'user_id', array('value'=>Yii::app()->user->id)); ?>
<?php $this->endWidget(); ?>
where $model is instance of Orders class, passed by variables thru controller, or set in view file. After that you can use it in way you wanted $model->attributes = $_POST['orders'] in your action method.
For flash message you can use Yii->app()->user->setFlash('orderStatus', 'Successful'), before redirect( or render ) in your actionOrder. To show it:
<?php if(Yii::app()->user->hasFlash('orderStatus')):?>
<div class="info">
<?php echo Yii::app()->user->getFlash('orderStatus'); ?>
</div>
<?php endif; ?>
I am just newbie to the yii framework. Currently I have two tables
one for sales and other for stores
Sales table is looking like this
==============
sales
==============
id
store_id
store table is looking like this
==============
Stores
==============
id
store_name
store_location
Now in sales view form(_form.php) I have rendered both sales and stores.
In sales controller the code for action create is like this
public function actionCreate()
{
$model=new Sales;
$stores = new Stores;
// Uncomment the following line if AJAX validation is needed
// $this->performAjaxValidation($model);
if(isset($_POST['Sales']$_POST['Stores']))
{
$model->attributes=$_POST['Sales'];
$stores->attributes = $_POST['Stores'];
$valid = $model->validate();
$valid = $stores->validate();
if($valid)
{
$stores->save(false);
$model->store_id = $stores->getPrimaryKey();
$model->save(false);
$this->redirect(array('view','id'=>$model->id));
}
}
$this->render('create',array(
'model'=>$model,
'stores' => $stores,
));
}
To get all the stores name in dropdown list I made my code like this
<div class="row">
<?php echo $form->labelEx($stores,'store_name'); ?>
<?php echo $form->dropDownList($stores,'store_name', CHtml::listData(Stores::model()->findAll(), 'store_name', 'store_name'), array('empty'=>'--Select--')) ?>
<?php echo $form->error($stores,'store_name'); ?>
</div>
But here I want the cjuiautocomplete field so that when someone will press any key then it will start to show the suggesions stores name. For that I just came through this link
and just like the docs I made the EAutoCompleteAction.php under protected/extension directory
Then I just made my controller code like this in sales controller
public function actions()
{
return array(
'aclist'=>array(
'class'=>'application.extensions.EAutoCompleteAction',
'model'=>'Stores', //My model's class name
'attribute'=>'store_name', //The attribute of the model i will search
),
);
}
and in view file of sales(_form.php) I made the code like this
<div class="row">
<?php echo $form->labelEx($stores,'store_name'); ?>
<?php
$this->widget('zii.widgets.jui.CJuiAutoComplete', array(
'attribute'=>'store_name',
'model'=>$stores,
'sourceUrl'=>array('stores/store_name'),
'name'=>'store_name',
'options'=>array(
'minLength'=>'3',
),
'htmlOptions'=>array(
'size'=>45,
'maxlength'=>45,
),
)); ?>
After all when I am doing the search by keywords it is showing 404 error in console panel of firebug.
The requested search url in firebug was like this (ads was my search query in store name field)
http://localhost/WebApp/index.php?r=stores/store_name&term=ads
any one here for help?
You forgot to change action name from sample aclist into store_name:
public function actions()
{
return array(
'store_name'=>array( // << Array key is action name
'class'=>'application.extensions.EAutoCompleteAction',
'model'=>'Stores', //My model's class name
'attribute'=>'store_name', //The attribute of the model i will search
),
);
}
For the following database:
TABLES:
user: [id,username]
project: [id,name]
project_user_assignment: [user_id,project_id,role]
When a new project is being created I'd like to show a dropdown with the available users to manage the project and when saving it insert into project_user_assignment the row
[user_id,project_id,'manager']
I'm starter with yii and don't know where (class,method) I must do the insert and how to return an error if in the moment of the insert the query fails
To display a drop down list in the you can use the foliowing code:
<?php echo CHtml::dropDownList(null,
'type',
CHtml::listData(
User::model()->findAll(),
'id',
'username',
),
array('empty' => 'Select a manager from the list ... ', 'id'=>'manager_list')
);?>
to update the corresponding field of the project_user_assignment model use the following:
<?php
<div class="row">
<?php echo $form->labelEx($model,'user_id'); ?> // Here I assume you have the $model variable set to Project_user_assignemenet ... if not (which probably is the case since you are creating a new project, set a new $model2 variable in the controller and use $model2 instead of $model)
<?php echo $form->textArea($model,'user_id'); ?>
<?php echo $form->error($model,'user_id'); ?>
</div>
?>
<script>
$('#manager_list').on('change', function(e) {
$('#Project_user_assignemenet_user_id').val($(this).val()); // Here id maybe wrong! Check them.
return true;
});
</script>
and finally in the controller you just save the model.