Prevent data from the same id to appear - php

Question

I want to prevent amaun_caj , amaun_pelbagai , amaun_penalti , amaun_tunggakan from being repeated so if the id_akaun is the same the data will not appear, my code only works on amaun_caj, and for the rest, not a single data appear, what's the problem?
<?php
$i = 0; $id_akaun_old ="";
while($output = mysql_fetch_array($result)) {
$i++;
$id_akaun = $output["id_akaun"];
$lokasi = $output["lokasi"];
$amaun_caj = $output["amaun_caj"];
$amaun_tunggakan = $output["amaun_tunggakan"];
$amaun_penalti = $output["amaun_penalti"];
$amaun_pelbagai = $output["amaun_pelbagai"];
$jumlah_bayaran = $output["jumlah_bayaran"];
?>
<tr>
<td>
<?php echo $i; ?>
</td>
<td>
<?php echo $jenis; ?>
</td>
<td>
<?php echo $id_akaun;
?>
</td>
<td>
<?php echo $no_telefon; ?>
</td>
<td>
<?php echo $lokasi; ?>
</td>
<td align="center">
<?php
if($id_akaun != $id_akaun_old):
echo $amaun_caj;
$id_akaun_old = $id_akaun;
else: echo '';
endif;?>
</td>
<td align="center">
<?php
if($id_akaun != $id_akaun_old):
echo $amaun_pelbagai;
$id_akaun_old = $id_akaun;
else: echo '';
endif;?>
</td>
<td align="center">
<?php
if($id_akaun != $id_akaun_old):
echo $amaun_penalti;
$id_akaun_old = $id_akaun;
else: echo '';
endif;?>
</td>
<td align="center">
<?php
if($id_akaun != $id_akaun_old):
echo $amaun_tunggakan;
$id_akaun_old = $id_akaun;
else: echo '';
endif;?>
</td>
<td align="center">
<?php
if($id_akaun != $id_akaun_old):
echo $jumlah_bayaran;
$id_akaun_old = $id_akaun;
else: echo '';
endif;?>
</td>
<?php
}
?>

Answer 1

Using temporary variable $old_id_akaun might not be the best practice. If you still want to do it like that, i suggest you user ORDER BY id_akaun in your SQL syntax.
In my oppinion, you might get rid of temporary variable and follow these steps,
1. Create empty array outside your while loop. For the sake of easy
understanding, let's called it $list_id_akaun.
2. Inside your while loop, after you get $id_akaun, check whether $id_akaun
is inside $list_id_akaun
3. If not exists, insert it to $list_id_akaun and continue echoing your
table row
4. If exists, skip to the next row.

Answer 2

I don't know why you don't want to use a select distinct clause in this case, but just put them inside a container then check inside the loop:
<?php
$temp = array();
$i = 1;
while($output = mysql_fetch_array($result)):
$id_akaun = $output["id_akaun"];
$lokasi = $output["lokasi"];
$amaun_caj = $output["amaun_caj"];
$amaun_tunggakan = $output["amaun_tunggakan"];
$amaun_penalti = $output["amaun_penalti"];
$amaun_pelbagai = $output["amaun_pelbagai"];
$jumlah_bayaran = $output["jumlah_bayaran"];
?>
<tr>
<td><?php echo $i; $i++; ?></td>
<td><?php echo $jenis; ?></td>
<td><?php echo $id_akaun; ?></td>
<td><?php echo $no_telefon; ?></td>
<td><?php echo $lokasi; ?></td>
<?php if(!in_array($id_akaun, $temp)): ?>
<td><?php echo $amaun_penalti; ?></td>
<td><?php echo $amaun_tunggakan; ?></td>
<td><?php echo $jumlah_bayaran; ?></td>
<?php $temp[] = $id_akaun; ?>
<?php else : ?>
<td></td><td></td><td></td>
<?php endif; ?>
</tr>
<?php endhile; ?>