I am requesting my output look like this:
Response
{
error_num: 0
error_details:
[
{
"zipcode": 98119
},
{
"zipcode": 98101
}
]
}
The values are irrelevant for this example.
My code looks like this:
$returndata = array('error_num' => $error_code);
$returndata['error_details'] = $error_msg;
$temp_data = array();
$temp_value = '';
foreach ($zipcodes_array as $value) {
//$temp_data['zipcode'] = $value;
//$temp_value .= json_encode($temp_data);
$temp_value .= '{"zipcode":$value},';
}
//$returndata['test'] = $temp_value;
$returndata['zipcodes'] = $temp_value;
echo json_encode($returndata);
My output varies depending on my different attempts (which you can see with the commented out things) but basically, I don't understand how the 3rd part (the part with the zipcodes) doesn't have a key or a definition before the first open bracket "["
Here is the output for the code above:
{"error_num":0,"error_details":"","zipcodes":"{\"zipcode\":11111},{\"zipcode\":11112},{\"zipcode\":11113},{\"zipcode\":22222},{\"zipcode\":33333},{\"zipcode\":77325},{\"zipcode\":77338},{\"zipcode\":77339},{\"zipcode\":77345},{\"zipcode\":77346},{\"zipcode\":77347},{\"zipcode\":77396},{\"zipcode\":81501},{\"zipcode\":81502},{\"zipcode\":81503},{\"zipcode\":81504},{\"zipcode\":81505},{\"zipcode\":81506},{\"zipcode\":81507},{\"zipcode\":81508},{\"zipcode\":81509},"}
Obviously i did not show the variables being filled/created because its through MySQL. The values are irrelevant. Its the format of the output i'm trying to get down. I don't understand how they have the "zipcode": part in between {} brackets inside another section which appears to be using JSON_ENCODE
It is close but see how it still has the "zipcodes": part in there defining what key those values are on? My question is, is the "response" above being requested by a partner actually in JSON_ENCODE format?? or is it in some custom format which I'll just have to make w/out using any json features of PHP? I can easily write that but based on the way it looks in the example above (the response) I was thinking it was JSON_ENCODE being used.
Also, it keeps putting the \'s in front of the " which isn't right either. I know it's probably doing that because i'm json_encode'ing a string. Hopefully you see what i'm trying to do.
If this is just custom stuff made to resemble JSON, I apologize. I've tried to ask the partner but I guess i'm not asking the right questions (or the right person). They can never seem to give me answers.
EDIT: notice my output also doesn't have any [ or ] in it. but some of my test JSON_ENCODE stuff has had those in it. I'm sure its just me failing here i just cant figure it out.
If you want your output to look like the JSON output at the very top of your question, write the code like this:
$returndata = array('error_num' => $error_code);
$returndata['error_details'] = array();
foreach ($zipcodes_array as $value) {
$returndata['error_details'][] = array('zipcode' => (int)$value);
}
echo 'Response ' . json_encode($returndata);
This will return JSON formatted like you requested above.
Response
{
error_num: 0
error_details:
[
{
"zipcode": 98119
},
{
"zipcode": 98101
}
]
}
Can you just use single ZipCode object as associative array, push all your small ZipCode objects to the ZipCodes array and encode whole data structure. Here is the code example:
$returndata = array(
'error_num' => $error_code,
'error_details' => array()
);
foreach ($zipcodes_array as $value) {
$returndata['error_details'][] = array('zipcode' => $value);
}
echo json_encode($returndata);
Related
Not sure what issue was with first pastebin code, here is another attempt.
I am connecting to Vimeo Live API, in doing so the response is huge > 500kb in total - I have an example with only one object here -> there are over 20 it returns. I have a better idea of what Im doing in JS than PHP, but returning the huge array or json to the browser doesn't seem like a good idea and its use of repeated ajax calls isn't good either. So this question is two fold, both in theory and practice. Is this a good design and how do I filter the result in PHP and only send what I need back to browser.
Here is the design, or at least what I think is best:
page loads, sends ajax request to PHP script
PHP script connects to API and gets response in an array (example of one object)
Search through the array for 'metadata->connections->live_video' for one that has an associated array containing [status] => streaming'
If one (there will only be one at a time) is found, return that whole object and that object only, not the entire array.
At this time I do not have a complete understanding of how this data should be returned or formatted for ease of sifting through. Ive tried using json_encode on the array, which gets nicely formatted JSON but I can't iterate through it and can only get single objects like data[0]->metadata->connections->live_video. Ive tried json_encode, then json_decode and Im back to a similar array structure of what is originally sent.
However, in the browser I am able to return the whole array and in the success function of the ajax call sift through it via JS like so:
let live_stream = json.data.filter(function(value, key) {
let connection = value.metadata.connections['live_video'];
return connection && connection.status === 'streaming';
});
I know this isn't the right way, I know I need to sift through the array, find the object / key Im looking for and only return that. Any advice is appreciated, once I get this figured out, I can apply it in a range of ways for this project.
The closest I can get in PHP is:
function live_event() {
global xxx;
$lib = xxx;
$response = xxx;
$body = $response['body'];
header('Content-Type: application/json');
$jsonstr = json_encode($body);
$json = json_decode($jsonstr);
foreach ($json->data as $item) {
if ($item->uri == "/live_events/2354796") {
echo"one";
}
}
}
and this:
function live_event() {
$global xxx;
$lib = xxx;
$response = xxx;
$body = $response['body'];
header('Content-Type: application/json');
$jsonstr = json_encode($body);
$json = json_decode($jsonstr,true);
$results = array_filter($json['data'], function($item) {
return $item['metadata']['connections']['live_video']['status'] == "streaming";
});
var_dump($results);
}
last one gets me this error "Warning: Trying to access array offset on value of type null in /var/www/vhosts/mysite.com/httpdocs/SSI/Vimeo.php on line 31" is there something similar to optional chaining in PHP? if its null I don't want it to log an error.
This at least output "one" as there is only one object with [uri]=>"/live_events/2354796". I can't get it to return that entire object or search one more nested array deeper.
There are a few things that come to mind.
OBJECTS:
If you're using PHP 8 you could use the safe access operator
function live_event() {
//...
$results = []
foreach ($json->data as $item) {
if($item?->metadata?->connections?->live_video?->status == 'streaming'){
$results[] = $item;
}
}
return $results;
}
ARRAYS:
For lower versions of PHP it's better to work with arrays when dealing with keys that may or may not exists.
Generally speaking whatever fetch library you're working with will allow you set the output to either array or object. If Object is your only option then yes doing the old json_decode(json_encode($data), true) is the way to go.
checking first isset(). Assuming that's it's desired to filter out results without that key.
function live_event() {
//...
$results = array_filter($json['data'], function($item) {
if(!isset($item['metadata']['connections']['live_video']['status']))
return false;
return $item['metadata']['connections']['live_video']['status'] == "streaming";
});
header('Content-Type: application/json');
echo json_encode([
"status" => true,
"data" => $results
]);
}
or you can always just use the age old trick of suppressing the error with the # symbol. TBH i'm not sure where the # symbol would go to suppress the error, perhaps in front of the filter function definition.
function live_event() {
//...
$results = array_filter($json['data'], function($item) {
return #$item['metadata']['connections']['live_video']['status'] == "streaming";
});
return $results;
}
I am wondering how to filter through a result like this properly. What I am doing results in problems. Obviously using a foreach on an array with a single item is not ideal but I don't know exactly how to do it any other way.
// connect with the static file
$json = file_get_contents('resources/assets/datafeeds/brewery_single.json');
$obj = json_decode($json, true);
// create brewery info
foreach($obj['pages'] as $brewery) {
foreach($brewery['results'] as $brewery) {
}
}
I've tried doing something like:
foreach($obj['pages']['results'] as $brewery) {
}
But I get an Undefined index: result errror like this.
Example data with only one result block, my data has multiple:
{
"apiName": "brewery_single",
"apiGuid": "d74e8aa2-4064-44b9-81de-2ceb150882c0",
"generatedAt": 1452761620,
"pages": [
{
"pageUrl": "http://www.brewery-website.com",
"results": [
{
"website": "www.brewery.com/",
"plaats": "Place",
"latlong": [
"53.657856",
"5.032597"
],
"naam": "Brouwerij title",
"provincie": "Noord Brabant",
"afbeelding": "http://www.brewery.com/images/brewery/brewer.jpg",
"actief": "Yes",
"land": "Netherlands",
"adres": "<p><b>Adres:</b><br />Street 40 <br />2388 GP<br /> Province, Netherlands </p>",
"opgericht": "1990"
}
]
},
]
}
Hopefully somebody can help me out so I can properly get my data from an api.
It seems like pages is an array of potentially multiple pages, each of which contains a results array of potentially multiple results. So indeed, two loops are in order:
foreach ($obj['pages'] as $page) {
foreach ($page['results'] as $brewery) {
...
}
}
If you're only ever interested in the first result, you can try to directly access it:
if (isset($obj['pages'][0]['results'][0])) {
echo $obj['pages'][0]['results'][0]['plaats'];
}
But again, the point of this data structure appears to be to account for multiple results, so you may be missing out on some information if you only ever consider the first.
Consult the documentation (which hopefully exists) of that API for exact details on the returned data.
Add an extra check to see if the data that you want is in the array:
if (isset($obj['pages'])) {
foreach($obj['pages'] as $brewery) {
if (isset($brewery['results'])) {
foreach($brewery['results'] as $brewery) {
}
}
}
}
There is syntax error in your code near ['results]
Change from
foreach($obj['pages']['results] as $brewery) {
into
foreach($obj['pages']['results'] as $brewery) {
There is no multiple arrays in results array. So why you need foreach there?
Anyways you can get value of results by providing exact INDEX.
For example: echo $obj['pages']['results]['website'];
I have sent a JSON object to PHP to query my database and return a resultset, however I am getting some unusual behaviour - my JSON object arrives in my script as:
{ "username": "Bobby", "dob": "2015-02-12T00:00:00.000Z" }
Which looks fine too me, in order to perform operations on that data I know I need to use json_decode so that PHP receives it as an array, however when I perform json_decode($request) the output array is:
{ undefined: 24, Bobby: ["dob"]}
I have never had this happen before, and can't quite get my head around exactly why this is happening
EDIT: My complete operation looks like:
if(isset($request)) {
var_dump($request);
$json = json_decode($request, true);
var_dump($json);
}
The first dump is correct, once decoded I get the skewed output
EDIT: I am sending the JSON object from Angular, but I don't think this should cause any problems, however its the only thing I have done differently to what I have in previous apps:
if (!(userName === undefined) && !(userDob === undefined))
{
var json = { "name" : userName, "dob" : userDob };
// Create POST request to the file in the url, send it to PHP in JSON format
var callback = $http.post($scope.url, json );
callback.success(function(data, status) {
...
});
}
EDIT I don't quite understand why, but using print_f or var_dump was delivering skewed results, however if I simply did:
$json = json_decode($request);
$name = $json->name;
$dob = $json->dob;
echo $name;
echo $dob;
It returns the results I would expect.
I believe you may need quotes around the keys:
{ "username": "Bobby", "dob": "2015-02-12T00:00:00.000Z" }
Give that a try.
That's a JavaScript object. Try:
var json = { "name" : userName, "dob" : userDob };
JSON.stringify(json);
I have a php code that reads JSON files. Part of the JSON sample below:
"Main": [{
"count": 7,
"coordinates": [89,77],
"description": "Office",
},{
"count": 8,
"coordinates": [123,111],
"description": "Warehouse",
}]
and I am trying to code PHP to only get the info (count, coordinates, description) of those who's description is included in the criteria like Warehouse. PHP Sample below
$validcriteria = array("Warehouse", "Parking_lot");
How do I do an if-statement to check first if "description" is included in the valid criteria. I tried the code below but it doesn't seem to work right.
$JSONFile = json_decode($uploadedJSONFile, false);
foreach ($JSONFile as $key => $value)
{
if (in_array($key['description'] , $validcriteria))
{
#more codes here
}
}
My code in PHP has been working except when I try to add $key['description'] to try and check the description first if it's valid. My code above is reconstructed to remove sensitive information but I hope you got some idea of what I was trying to do.
When attempting to understand the structure of a parsed JSON string, start with a print_r($JSONFile); to examine its contents. In your case, you will find that there is an outer key 'Main' which holds an array of sub-arrays. You will need to iterate over that outer array.
// Set $assoc to TRUE rather than FALSE
// otherwise, you'll get an object back
$JSONFile = json_decode($uploadedJSONFile, TRUE);
foreach ($JSONFile['Main'] as $value)
{
// The sub-array $value is where to look for the 'description' key
if (in_array($value['description'], $validcriteria))
{
// Do what you need to with it...
}
}
Note: if you prefer to continue setting the $assoc parameter to false in json_decode(), examine the structure to understand how the objects lay out, and use the -> operator instead of array keys.
$JSONFile = json_decode($uploadedJSONFile, FALSE);
foreach ($JSONFile->Main as $value)
{
// The sub-array $value is where to look for the 'description' key
if (in_array($value->description, $validcriteria))
{
// Do what you need to with it...
}
}
You might also consider using array_filter() to do the test:
$included_subarrays = array_filter($JSONFile['Main'], function($a) use ($validcriteria) {
return in_array($a['description'], $validcriteria);
});
// $included_subarrays is now an array of only those from the JSON structure
// which were in $validcriteria
Given your JSON structure, you probably want
foreach($decoded_json['Main'] as $sub_array) {
if (in_array($sub_array['description'], $validation)) {
... it's there ...
}
}
Because you set false to second argument of json_decode function, it's returned as an object,
if you change it to TRUE, the code would work.
http://php.net/manual/en/function.json-decode.php
and you have to change key to value;
foreach ($JSONFile->Main as $key => $value)
{
if (in_array($value->description, $validcriteria))
{
#more codes here
}
}
this code assume your json file has one more depth greater than your example. that's why $JSONFile->Main in the foreach loop.
Try to use that :
if ( array_key_exists('description', $key) )
I've been searching everywhere for a definitive answer to what seems to be a really simple task - unfortunately all the solutions I can find (and there are a lot) use mysql_fetch_assoc which is deprecated.
All I'm trying to do is to take a two column set of results from a database and echo in JSON format - I've managed everything fine except for one bit - I can't work how to get the values in to a two dimensional array (two column array) using array_push. I just end up with my two column values merged in to one array. Here's a stripped version of what I've done:
header('Content-Type: application/json');
$mostPopularStm = $sparklyGenericPdoObj->prepare("SELECT views, thing FROM X");
$mostPopularStm->execute();
$mostPopularRS = $mostPopularStm->fetchAll();
echo '{data:';
$mostPopularJson = array();
foreach ($mostPopularRS as $mostPopularItem)
{
array_push($mostPopularJson, $mostPopularItem["views"], $mostPopularItem["thing"]);
}
echo json_encode($mostPopularJson);
echo '}';
This is producing output like this:
{data:["Monkeyface","43","Giblets","25","Svelte","22","Biriani","21","Mandibles","20"]}
But what I need is this:
{data:["Monkeyface":"43","Giblets":"25","Svelte":"22","Biriani":"21","Mandibles":"20"]}
I know I can create something manually to do this, using json_encode to format the string on each loop but it seems inefficient.
Any pointers would be hugely appreciated!
Your current array is like
array(0 => 'Monkeyface', 1 => 43, /* ... */);
but you need like
array('Monkeyface' => 43, /* ... */);
Replace
array_push($mostPopularJson, $mostPopularItem["views"], $mostPopularItem["thing"])
By
$mostPopularJson[$mostPopularItem["thing"]] = $mostPopularItem["views"];
And
echo '{data:';
echo json_encode($mostPopularJson)
echo '}';
Better to use:
echo json_encode(array('data' => $mostPopularJson));
As kingkero said, you will never get your expected result because it is invalid:
{data:["Monkeyface":"43" ...
Correct:
{ "data": { "Monkeyface": "43" ...
Compose your array like so:
$mostPopularJson [$mostPopularItem["thing"]] = $mostPopularItem["views"];