PHP echo statement IF parse error [closed] - php

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if ((isset($_GET['Menu']) && $_GET['Menu'] == "1" && $_GET['Overview']==1)
{
echo '$_GET['Overview']'
}
if statement to receive parameter from the URL

Because you cannot use if the way you do. Split up the echo, then it should work:
echo "<li><a " ;
if($_GET['Menu']==1) { echo 'class="select"'; }
echo " href=javascript:setParam('Menu',1);>Networks</a></li>";

$x="";
if($_GET['Menu']==1)
$x= 'class="select"';
echo "<li><a>".$x." href=javascript:setParam('Menu',1);>Networks</a></li>";

Im partial to sprintf for concatenation, but thats just me:
echo sprintf('<li><a %s href=javascript:setParam(\'Menu\',1);>Networks</a></li>',
$_GET['Menu']==1 ? 'class="select"' : '');

You need to echo every part of your code:
echo "<li><a ";
if($_GET['Menu']==1) { echo 'class="select"'; }
echo " href=javascript:setParam('Menu',1);>Networks</a></li>";

Related

How to do inline styling in html/php? [closed]

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I am working on a website in which I want to do inline styling inside php tags.
<?php
if($data['item']->hello_world!=null)
{
echo "policy:";
echo strtolower($data['item']->hello_world->name);
echo "<br>";
echo strtolower($data['item']->hello_world->description);
}
?><?php
if($data['item']->hello_world!=null)
{
echo "policy:";
echo strtolower($data['item']->hello_world->name);
echo "<br>";
echo "<br>";
echo strtolower($data['item']->hello_world->description);
}
?>
The data which I want to style coming from the php code is:
echo strtolower($data['item']->hello_world->name);
Problem Statement:
I am wondering what changes I should make in the php code so that I am able to do styling for the above mentioned line.
To inline style the element:
echo '<span style="color: red">' . strtolower($data['item']->hello_world->name) . '</span>';

Trying to make this entire line of code into a hyperlink [closed]

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echo <a href = 'test.php'> "CategoryID: " . $row["CategoryID"]. " - Category Name: ".$row["CategoryName"]. </a> "<br>";
This is what i have an is not working properly.
This:
echo "<a href = 'test.php'>CategoryID: {$row['CategoryID']} - Category Name: {$row['CategoryName']}</a><br />";
I am using the { and } as they allow you to include an array in a string and ignore the concatenation which I find harder to read.
I find it funny that you can loop through a MySQL array but can't echo a simple string :P
Some links (teach a man to fish...):
W3Schools
PHP documentation
Codecademy
Tutorials Point
Try this:
<?php
$link = "";
$link = sprintf("<a href = 'test.php'>CategoryID: %d - Category Name: %s </a><br />", $row['CategoryID'], $row['CategoryName']);
echo $link;
?>
Assuming that $row['CategoryID'] is an integer and $row['CategoryName'] is a string.

What is the right way to put HTML in PHP [closed]

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I'm programming in PHP, but I don't think its the right way.
I'm programming something like this:
<?php
$apple = 10
if(apple >= 4){
?>
<img src="Bladieblabla">
Biep
<?php
}else{
print "Awhh we don't have 4 apples";
}
?>
You can use echo, or print like this
if($apple > 5) {
echo '<img src="Bladieblabla">';
echo 'Biep';
} else {
print "Awhh we don't have 4 apples";
}
Update: Using echo only one time:
echo '<img src="Bladieblabla">
Biep';
<?php
$apple = 10;
if(apple > 5){
echo '<img src="Bladieblabla">';
echo 'Biep';
}else{
print "Awhh we don't have 4 apples";
}
?>

single quotes vs double quotes, how to arrange? [closed]

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Please let me know how to writte the below code so as to work because as it is it doesn't work
echo "<a href='$row['url']'>$row['link_text']</a>";
Write so you can read it next time. Also syntax highlight is better this way:
echo '' . $row['link_text'] . '';
You are using ' twice, so you need to escape them or just remove them in this case:
echo "<a href='$row[url]'>$row[link_text]</a>";
When you have to insert complex variables like array values inside strings, usually printf or sprintf is more clear and less error-prone.:
printf("<a href='%s'>%s</a>", $row['url'], $row['link_text']);
This will work:
echo "<a href='".$row['url']."'>".$row['link_text']."</a>";
Also this:
echo "<a href='{$row['url']}'>{$row['link_text']}</a>";
It's personal preference.
It's because you've put a ' inside another '.
echo "<a href='{$row['url']}'>{$row['link_text']}</a>";
or
echo "<a href='" . $row['url'] . "'>" . $row['link_text'] . "</a>";
Choose the one more to your liking.
You can try with.
echo "<a href='".$row['url']."'>".$row['link_text']."</a>";
Or
echo "<a href='{$row['url']}'>{$row['link_text']}</a>";
Or
echo ''.$row["link_text"].'';

PHP json_parse trakt API [closed]

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<?php
$response = file_get_contents("http://api.trakt.tv/shows/trending.json/5d7588c188eeea0074b8d2664d12fffc");
$result = json_decode($response, true);
echo $result['title'][0];
echo "<br>";
echo $result['network'][0];
echo "<br>";
echo $result['air_day'][0];
echo "<br><img style='width:200px;' src='";
echo $result['images'][0]['poster'];
echo "'>";
?>
Ain't working. I don't know why.
I use the the trakt.tv shows API.
Write
echo $result[0]['title'];
instead of
echo $result['title'][0];
Besides, PHP's echo function will print integers and strings, but will fail with array-alike structures. You could use var_dump or var_export instead. Thanks to them, you could scan the structure and you wouldn't ask this question ;)

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