I have a xml rss feed that I'm using on my website, with this code I'm generating html from xml file:
$html = "";
$url = "http://books.com/new_bookss/?format=xml";
$xml = simplexml_load_file($url);
for($i = 0; $i < 10; $i++){
$link = $xml->resource[$i]->book_link;
$title = $xml->resource[$i]->book_title;
$img = $xml->resource[$i]->image_url;
$html .= "<img src=\"$img\"><br>$title";
}
echo $html;
Generated $link and $img looks like this:
http://books.com/new_books/booktitle/ /*this is for $link*/
http://images.books.com/img/booktitle.jpg /* this is for $img*/
I have to change these urls that way:
http://books.com/new_books/booktitle/ to http://mywebsite/new_books/booktitle/
http://images.books.com/img/booktitle.jpg to http://mywebsite//img/booktitle.jpg
URLs structure looks same every time:
http://books.com/new_books/booktitle/
http://books.com/new_books/something/
http://books.com/new_books/else/
Stricture on my website is same:
http://mywebsite.com/new_books/booktitle/
http://mywebsite.com/new_books/something/
http://mywebsite.com/new_books/else/
Same for $img, so the only thing I have to change is books.com to mywebsite.com
This is how I did it:
$link = str_replace("books.com","mywebsite.com",$link);
Added after:
$link = $xml->resource[$i]->book_link;
Related
Like always, I am having issues doing this. So, I have been able to extract images from folders using php, but since it was taking too long to do that, I decided to just extract the names from a text file and then do a while loop and echo the list of results. For example I have a file called, "cats.txt" and inside the data looks like this.
Kitten1.jpg
Kitten2.jpg
Kitten3.jpg
I could easily use an sql or json table to do this, but I am not allowed. So, I only have this.
Now, I have tried doing this, but I get an error.
--- PHP CODE ---
$data = file ("path/to/the/file/cats.txt");
for ($i = 0; $i < count ($data); i++){
$images = '<img src="/kittens/t/$i">';
}
$CatLife = '
Images of our kittens:<br>
'.$images.'
';
I would really appreciate the help. I am not sure of what the error is, since the page doesn't tell me anything. It just doesn't load.
You can try something like this:
$fp = fopen('path/to/the/file/cats.txt', 'r');
$images = '';
while(!feof($fp)) {
$row = fgets($fp);
$images .= '<img src="/kittens/t/'.$row.'">';
}
fclose($fp);
$CatLife = "Images of our kittens:<br>$images";
Maybe you should use the glob php function instead of parsing your txt file.
foreach (glob("path/to/the/file/Kitten*.jpg") as $filename) {
echo "$filename\n";
}
Get used to foreach(). Much easier. Also note that variables like $file in your img tag don't get interpreted in single quotes. I use an array and then implode it:
$data = file ("path/to/the/file/cats.txt");
foreach($data as $file) {
$images[] = '<img src="/kittens/t/'.$file.'">';
}
$CatLife = '
Images of our kittens:<br>
'.implode($images).'
';
You could also just use $images .= '<img src="/kittens/t/$file">'; to concatenate and not need to implode.
$data = file ("path/to/the/file/cats.txt");
$images = '';
for ($i = 0; $i < count ($data); i++){
$images .= '<img src="/kittens/t/$i">');
}
$CatLife = 'Images of our kittens:<br>'.$images.'';
echo $CatLife;
Try this, it stores each image tag into a string and echos it to the page.
My client requested that I implement an affiliate feed with which has the format of XML. However, the file is huge with 650k lines! I tried parsing it using a simpleXML, it worked, but it's extremely slow. As a result, the website sometimes does not load.
<?php
$html = "";
$url = "http://www.digitick.com/rss/distributeur/fluxAffiliation195_815.xml";
$xml = simplexml_load_file($url);
for($i = 0; $i < 10; $i++){
$title = $xml->content->eventList->event[$i]->eventName;
$link = $xml->content->eventList->event[$i]->eventUrl;
$description = $xml->content->eventList->event[$i]->eventPresentation;
$dateStart = $xml->content->eventList->event[$i]->dateStart;
$img = $xml->content->eventList->event[$i]->pictureUrl;
$html .= "<a href='$link'><h3>$title</h3></a>";
$html .= "<img src=$img>";
$html .= "$description";
$html .= "<br />$dateStart<hr />";
}
echo $html;
?>
What can I do to handle the this dynamic file (which updates every morning at 5am?
Thank you in advance!
I would import the file into a SQLite database file with a cron job. Then use SQL to request parts of it in your application. As an alternative cache the generated output and only read the large file once a day.
Is it possible to find and replace a direct video link with PHP? I keep trying to use str_replace to find the link and replace it with an already specified one.
But is just leaves the text blank without the link there or anything.
Then it becomes <source src=""> With nothing inside of the src
INDEX.HTML (Video thing)
<source src="##LINK##">
INDEX.PHP
<?php
$title = htmlspecialchars($_POST['title']);
$link = htmlspecialchars($_POST['link']);
$desc = htmlspecialchars($_POST['desc']);
$pgname = htmlspecialchars($_POST['pagename']);
copy('index.html', $pgname . '.html');
$myFile = $pgname . '.html';
$ch = curl_init($myFile);
$output = curl_exec($ch);
$data = file_get_contents($myFile);
$replaceables = array("##TITLE##", "##PGNAME##", "##DESC##", "##LINK##");
$new = array($title, $pgname, $desc, $link);
$data = str_replace($replaceables, $new, $data);
file_put_contents($myFile, $data);
?>
say i have
» Download MP4 « - <b>144p (Video Only)</b> - <span> 19.1</span> MB<br />
html page like this i wanna parse it with simple dom php parser and i wanna get download mp4 114p 19.1 as out put while i tried this code
foreach($displaybody->find('a ') as $element) {
// echo $element->innertext . '<br/>';
it returned me download mp4 only how do i parse remaining values download mp4 114p 19.1 please help me out
You can't use the <a> tag anymore since some of the text you're trying to access isn't inside it anymore, target the document itself and then use ->plaintext:
$html = <<<EOT
» Download MP4 « - <b>144p (Video Only)</b> - <span> 19.1</span> MB<br />
EOT;
$displaybody = str_get_html($html);
echo $displaybody->plaintext;
Here is another way of accessing each row thru DOMDocument with xpath:
// load the sites html page in DOMDocument
$dom = new DOMDocument();
libxml_use_internal_errors(true);
$html_page = file_get_contents('http://www.mohammediatechnologies.in/download/downloadtest.php?name=8KPEiGqDQHg');
$dom->loadHTML(mb_convert_encoding($html_page, 'HTML-ENTITIES', 'UTF-8'));
libxml_clear_errors();
$xpath = new DOMXpath($dom);
$data = array();
// target elements which is inside an anchor and a line break (treat them as each row)
$links = $xpath->query('//*[following-sibling::a and preceding-sibling::br]');
$temp = '';
foreach($links as $link) { // for each rows of the link
$temp .= $link->textContent . ' '; // get all text contents
if($link->tagName == 'br') {
$unit = $xpath->evaluate('string(./preceding-sibling::text()[1])', $link);
$data[] = $temp . $unit; // push them inside an array
$temp = '';
}
}
echo '<pre>';
print_r($data);
Sample Output
I'm trying to load a remote xml file using php.
This is my code:
$doc = new DOMDocument();
$doc->load($this->xml_file);
$file = $doc->getElementsByTagName('file');
$totalFiles = $file->length;
echo $totalFiles;
The remote xml file link is:
http://localhost/script/index.php?act=xml
This is the code in index.php:
$xml = '<?xml version="1.0"?><MultimediaGallery>';
$query = mysql_query('SELECT `id`,`image`,`desc` FROM `'
.confitem('database','prefix').'table` ORDER BY `id` DESC LIMIT '
.$start.','.$limit);
while($result = mysql_fetch_array($query))
{
$img = unserialize($result['image']);
$desc = unserialize($result['desc']);
$xml .= '<file type="photo"><thumb>'
.settings('site','url').'/'.OPATH_APPFOLDER.'/'
.OPATH_UPFOLDER.'/wallpapers/thumbs/'.$img[0].'</thumb><source>'
.settings('site','url')
.'/'.OPATH_APPFOLDER.'/'.OPATH_UPFOLDER
.'/wallpapers/'.$img[0].'</source><description>'
.$desc[$_SESSION['languagecode']].'</description></file>';
}
$xml .= '</MultimediaGallery>';
header("content-type: text/xml");
echo $xml;
When I visit this xml file link direct in the browser .. it's output to me xml file with this style :
<?xml version="1.0"?><MultimediaGallery><file type="photo"><thumb>http://localhost/script/application/data/wallpapers/thumbs/1116205566_42ce0841ab_s.jpg</thumb><source>http://localhost/script/application/data/wallpapers/1116205566_42ce0841ab_s.jpg</source><description>dfdfdfdf</description></file></MultimediaGallery>
When I execute the xml function which uses the dom to load the xml file I get this error:
Warning: DOMDocument::load()
[domdocument.load]: Extra content at
the end of the document in
http://localhost/script/index.php,
line: 2 in
C:\AppServ\www\script\application\libraries\wallpapers\multimedia.class.php
on line 46
Why is this happening?
Update:
I used dom to create the xml instead:
$xml = new DOMDocument('1.0');
$root = $xml->createElement('MultimediaGallery');
$xml->appendChild($root);
$query = mysql_query('SELECT `id`,`image`,`desc` FROM `'.confitem('database','prefix').'backgrounds` ORDER BY `id` DESC LIMIT '.$start.','.$limit);
while($result = mysql_fetch_array($query))
{
$img = unserialize($result['image']);
$desc = unserialize($result['desc']);
$element = $xml->createElement('file');
$root->appendChild($element);
$attr = $xml->createAttribute('type');
$element->appendChild($attr);
$attr_text = $xml->createTextNode('photo');
$attr->appendChild($attr_text);
$thumb = $xml->createElement('thumb');
$element->appendChild($thumb);
$thumb_text = $xml->createTextNode(settings('site','url').'/'.OPATH_APPFOLDER.'/'.OPATH_UPFOLDER.'/wallpapers/thumbs/'.$img[0]);
$thumb->appendChild($thumb_text);
$source = $xml->createElement('source');
$element->appendChild($source);
$source_text = $xml->createTextNode(settings('site','url').'/'.OPATH_APPFOLDER.'/'.OPATH_UPFOLDER.'/wallpapers/'.$img[0]);
$source->appendChild($source_text);
$description = $xml->createElement('description');
$element->appendChild($description);
$description_text = $xml->createTextNode($desc[$_SESSION['languagecode']]);
$description->appendChild($description_text);
}
header("content-type: text/xml");
echo $xml->saveXML();
But it still gives me the same error. I noticed some thing though, I tried to copy my output xml and save it in a file and read it using the dom parser and the result was that it's read successfully.
But when I try parsing the xml output by the php file then it throws an error.
Your XML is not well-formed. E.g there is something wrong with it.
Try to avoid making XML by concatenating strings because this will happen. You can use DomDocument you make XML as well as read it and manipulate it.
Make sure you have no leading or trailing white space in your XML generating script.
You should also be using CDATA