Get time before noon - php

Question

I am practicing with dates in php. I a bit of a newbie so bear my ignorance
I am trying to see when a time is before noon.
So I have a variable coming in with this format 2014-03-07 13:28:00.000
I get the time like this
$submissonTime = date('H:i:s', strtotime($value['job_submission_date']));
then I want to set another variable as $noon and i am doing this:
$noon = date('H:i:s', '12:00:00.000');
However the value of noon is 12:00:12
what i want to do is basically:
if($submissionTime <= $noon){
//do my stuff
}
NB I want to enter the if statement when even when it is 12:00:00 and stop entering when it is 12:00:01
Any help please?

Answer 1

Try
$noon = date('Y-m-d 12:00:00'); // today noon with date
$submissonTime = date('Y-m-d H:i:s', strtotime($value['job_submission_date']));
if(strtotime($submissonTime) <= strtotime($noon)){
//do my stuff
}
if you want to compare only time use both format
$noon = date('12:00:00');
$submissonTime = date('H:i:s', strtotime($value['job_submission_date']));

Answer 2

if (date("A") == "AM")
{
// AM-Code
} else {
// PM-Code
}

Answer 3

Why don't you go with only one string of code getting the hour?
$Hour = date("G"); //24-hour format of an hour without leading zeros
if($Hour < 12) {
// do the code
}
Or in your case
$Hour = date("G", strtotime($value['job_submission_date']));
update
If you need 12:00:00 and not 12:00:01 and later on, you will need to define minutes and seconds:
$Hour = date("G"); //24-hour format of an hour without leading zeros
$Minute = intval(date("i")); // will give minutes without leading zeroes
$Second = intval(date("s"));
if(($Hour < 12) || ($Hour == 12 && $Minute == 0 && Second == 0)) {
// do the code
}