PHP Count Generated Results From Loop - php

Question

I have this for loop that generates 10 results:
<?php
include "dbconnect.php";
$table = "SELECT id FROM players ORDER BY RAND()* ( 1 / percentage)";
for ($i = 0; $i < 10; $i++){
$result[0] = mysql_fetch_array(mysql_query($table));
foreach ($result as $winner){
echo $winner[0] . " ";
}
}
?>
It generates a result like:
10 10 11 9 13 11 10 12 8 12
My question is how do I count the generation? For the above example it would be:
8's = 1, 9's = 1, 10's = 3, 11's = 2, 12's = 2, 13's = 1.
I basically want to count the amount of specific results generated. Sorry if i'm not making much sense.

Answer 1

You need to get off of MySQL functions and check out PDO or MySQLI at a minimum. But for the meat of the question:
Don't run a query, full or limited in the loop
Look at the LIMIT clause in the query
array_count_values will count the values. You can loop it and echo or whatever
Example:
$table = "SELECT id FROM players ORDER BY RAND()*(1/percentage) LIMIT 10";
$result = mysql_query($table);
while($row = mysql_fetch_array($result)) {
$winner[] = $row[0];
}
echo implode(' ', $winner);
foreach(array_count_values($winner) as $number => $count) {
$output = "$number's = $count";
}
echo implode(', ', $output);
You're existing code to make the random choice work would look like (LIMIT 1):
$table = "SELECT id FROM players ORDER BY RAND()*(1/percentage) LIMIT 1";
for($i = 0; $i < 10; $i++){
$result = mysql_fetch_array(mysql_query($table));
$winner[] = $row[0];
}
echo implode(' ', $winner);

Answer 2

if you check the php manual:
http://php.net/manual/en/function.mysql-query.php
then try something like this:
while ($row = mysql_fetch_assoc($table)) {
echo $row['column_name'];
echo $row['column_name'];
//.. you get the idea
}
The id is usually the first column in a database table. This is why you are just getting the id. You need to access each row in the same way you access arrays.
I should point out that the mysql library is deprecated. So you should consider using something like PDO instead.