take special lines from txt database PHP - php

Question

I have text database
0,Apple,Green
1,Banana,Yellow
2,Cherry,Red
and when I call getdata.php?row=2 I need get data which is 2,cherry,red
I am a bachelor in PHP and I have only one example ,
please help me for this problem.
thanks
$file_handle = fopen("./news.txt", "rb");
while (!feof($file_handle) ) {
$line_of_text = fgets($file_handle);
$parts = explode(',', $line_of_text);
print $parts[0] . $parts[1] . $parts[2];
}
fclose($file_handle);

Answer 1

This would work and would also stop reading as soon as it found the right line (unlike the other answers who read the whole no file matter what)
if (isset($_GET['row']))
{
$file_handle = fopen("./news.txt", "rb");
$i = 0;
while (!feof($file_handle))
{
if ($i == $_GET['row'])
{
$line_of_text = fgets($file_handle);
$parts = explode(',', $line_of_text);
print $parts[0] . $parts[1] . $parts[2];
break;
}
$i++;
}
fclose($file_handle);
}

Answer 2

You first have to explode by rule with explode("/n", $txt) than you've an array of each rule. After you stored this explode in to a variable than you should explode a specific value again by ,.

Answer 3

A straightforward way to do this: if record number 2 is always on line number 3.
if (!isset($_GET['row']) || !is_int($_GET['row'])) {
echo "please supply a row number";
die;
}
$lines = file('news.txt');
// assumes record number 2 is on line 3
$row = $_GET['row'] + 1;
$parts = explode(',', $lines[$row]);
print $parts[0] . $parts[1] . $parts[2];
If record number 2 is not guaranteed to be on line 3
$row = $_GET['row'];
foreach ($lines as $line) {
if (strpos($line, $row) === 0) {
$parts = explode(',', $lines[$row]);
print $parts[0] . $parts[1] . $parts[2];
break;
}
}
If the file is extremely large you will want to read line by line from a buffer.
$row = $_GET['row'];
if ($fp = fopen('news.txt', 'r')) {
while ($line = fgets($fp)) {
if (strpos($line, $row) === 0) {
$parts = explode(',', $line);
print $parts[0] . $parts[1] . $parts[2];
break;
}
}
fclose($fp);
}