I'm using the following code to see if a date falls between 2 other dates.
public function dateCompare($date1, $date2)
{
$interimDate = date('d/m/Y');
$StartDate = DateTime::createFromFormat('d/m/Y', $date1);
$EndDate = DateTime::createFromFormat('d/m/Y', $date2);
if ($interimDate > $StartDate && $interimDate < $EndDate)
{
echo 'Falls during given period';
}
else {
echo 'Does not fall during given period';
}
The two dates passed as follows
dateCompare('01/08/14', '30/12/14');
For some reason I continually get the message that todays date does not fall between the given period. I have checked the servers datetime and it is correct. Is anyone able to point out what exactly is causing the error?
You have a 2 letter years, so it should be lower case y for your format: d/m/y.
Also, make $interimDate equal to a new DateTime() object so you can compare properly.
Related
I have a code in PHP 5.5.11 where I am trying to do the following:
Get today's date in a variable --> $today
Calculate the end of month from a date in a form --> $st_dt_eom
if difference between these 2 dates is more than 5 days then execute a code. The code in the if condition below does not execute.
$today= date();
if($_POST['Submit']=='SAVE')
{
$st_dt=YYYYMMDD($_POST['st_dt'],"-");
$st_dt_eom= datetime::createfromformat('YYYYMMDD',$st_dt);;
$st_dt_eom->modify('last day of this month');
$diff = $today->diff($st_dt_eom);
$diffDays= intval($diff->format("%d")); //to get integer number of days
if($diffDays>5){
redirect("index.php");
}
}
An example:
// 2022-12-19
$today = date('Y-m-d');
// $_POST['st_dt']
$st_dt = '2022-12-31';
function dateDiffDays($today, $st_dt)
{
$today_obj= DateTime::createfromformat('Y-m-d', $today);
$st_dt_eom= DateTime::createfromformat('Y-m-d', $st_dt);
$diff = $today_obj->diff($st_dt_eom);
return $diff->days;
}
// int(12)
$res = dateDiffDays($today, $st_dt);
use var_dump to locate your bug.
A few suggestions to improve your code and produce something workable:
<?php
// Instead of using date(), use a DateTime() then you're comparing two DateTimes later on
$today = new DateTime();
// I'm assuming that your YYYYMMDD function removes "-" from the $_POST['st_dt']
// to provide a date in the format YYYYMMDD (or Ymd in PHP).
// Unfortunately, DateTime doesn't understand that format.
// So I'd change this for keeping Y-m-d (YYYY-MM-DD).
// Or modify your code to return that format!
$st_dt = $_POST['st_dt'];
// Watch out for your cAsE when using PHP functions!
$st_dt_eom = DateTime::createFromFormat('Y-m-d',$st_dt);
$st_dt_eom->modify('last day of this month');
$diff = $today->diff($st_dt_eom);
$diffDays= intval($diff->format("%d"));
if($diffDays > 5){
redirect("index.php");
}
I have to output this information but I am not used to work with PHP, don´t know what I am doing wrong.
I query woocommerce order date like this:
$order = wc_get_order(456);
$orderdate = $order->date_created;
That seems to be working ok, it returns a date in this format:
2020-10-15T17:38:37-03:00
For current date, I create a variable like this:
$date = date('d-m-y h:i:s');
But when I try to output the difference in days between order date and current, it always give me 0
This is how I tried to calculate the difference:
function dateDiff($date1, $date2)
{
$date1_ts = strtotime($date);
$date2_ts = strtotime($orderdate);
$diff = $date2_ts - $date1_ts;
return round($diff / 86400);
}
$dateDiff = dateDiff($date1, $date2);
echo ("day difference is: " . $dateDiff );
Thanks a lot for reading, hope you can help me.
Short explanation of what is wrong with your code:
$dateDiff = dateDiff($date1, $date2);
In your case dateDiff is a function which expects two parameters $date1 and $date2. But you are passing non existing variables to the function. They do not exist out of the function scope, because you didn't declare them.
Then you are trying to get timestamps from dates which are in parent scope and probably getting NULL as a result from both cases :)
$date1_ts = strtotime($date);
$date2_ts = strtotime($orderdate);
Small improvements:
Its better to use DateTime class when you are working with dates. DateTime class has powerful method called format that allows you to output date in suitable format for you.
If we combine what you did into one piece of code with some changes, then we will get this:
$order = wc_get_order(456);
$order_date = new DateTime($order->date_created);
$current_date = new DateTime();
function dateDiff($date1, $date2)
{
// check if diff is not equal to zero in order to avoid division be zero exception
if ($diff = abs(strtotime($date2) - strtotime($date1))) {
return round($diff / 86400);
}
return 0;
}
echo ("day difference is: " . dateDiff(
$current_date->format('d-m-Y h:i:s'),
$order_date->format('d-m-Y h:i:s')
) . " days");
I have problem, I can't get time from personal identity number under 1970, I need to solve that, but using time. My function looks like. I don't know which way I can go. Thanks!
function getBirthDayFromRd($rd){
$day = substr($rd,4,2);
$month = substr($rd, 2,2);
$year = substr($rd, 0,2);
if($month>=51 and $month<=62){
$month = $month - 50;
}
$time = strtotime($day.".".$month.".".$year);
return date("d.m.Y", $time);
}
strtotime() fails due to its being tied to the Unix epoch which does not support dates prior to 1970. Just use DateTime which can handle pre-1970 dates and convert dates easily:
function getBirthDayFromRd($rd){
$date = DateTime::createFromFormat('ymd',$rd);
if($date->format('Y') > date("Y")) {
$date->modify('-100 years');
}
return $date->format('d.m.Y');
}
DateTime::createFromFormat() parses your date and creates the DateTime object. Then we just call DateTime::format() to format it in the desired format.
update
Just fixed a bug where pre-1970 dates were shown 100 years in the future.
Demo
I solve it another way, but u started me up.
if($year < 70){
$year = $year+1900;
$time = date_create_from_format("d.m.Y", $day.".".$month.".".$year);
return date_format($time, "d.m.Y");
}else{
$time = strtotime($day.".".$month.".".$year);
return date("d.m.Y", $time);
}
$todaysDate = date("Y-m-d");
$maxBookingDate=strtotime('+2 weeks', $todaysDate);
$dateEntered = DateTime::createFromFormat('d/m/Y', $_POST["Date"]);
$tableDate =$dateEntered->format('Y-m-d');
if ($tableDate < $todaysDate){
echo "Date must be in the future";
}
if ($tabledate > $maxBookingDate){
echo "Date must be no more than 2 weeks in advance";
}
Date comparison to make sure that the date a user enters is no more than two weeks in advance isn't working, what have I done wrong?
You can just use DateTime classes all through out so that its easier to compare:
$todaysDate = new DateTime();
$maxBookingDate = new DateTime('+2 weeks');
$dateEntered = DateTime::createFromFormat('d/m/Y', $_POST['Date']);
if ($dateEntered < $todaysDate){
echo "Date must be in the future";
} elseif ($dateEntered > $maxBookingDate){
echo "Date must be no more than 2 weeks in advance";
}
In your code:
$todaysDate is a string, and you fed it inside strtotime() as your second parameter which is incorrect usage. The second parameter requires numeric value (timestamp).
Inside your if else statement, you're comparing strings. You should be comparing them as timestamps or DateTime objects instead, like the answer above.
i am struggling for a long time to set a specific date but i am not getting correct out put.
i want to get date from user and compare that date with the date 15 days older then today. if it is older than 15 days then convert to today else print what it is.
$todaydate= $_GET['date'];// getting date as 201013 ddmmyy submitted by user
$todaydate=preg_replace("/[^0-9,.]/", "", $todaydate);
$today =date("dmy"); //today ddmmyy
$older= date("dmy",strtotime("-15 day")); // before 15 days 051013
if ($todaydate <= $older){
$todaydate= $today;}
problem is, it is taking date as number and giving wrong result.
Comparing date strings is a bit hacky and prone to failure. Try comparing actual date objects
$userDate = DateTime::createFromFormat('dmy', $_GET['date']);
if ($userDate === false) {
throw new InvalidArgumentException('Invalid date string');
}
$cmp = new DateTime('15 days ago');
if ($userDate <= $cmp) {
$userDate = new DateTime();
}
Also, strtotime has some severe limitations (see http://php.net/manual/function.strtotime.php#refsect1-function.strtotime-notesand) and is not useful in non-US locales. The DateTime class is much more flexible and up-to-date.
try this one:
<?php
$todaydate = date(d-m-Y,strtotime($_GET['date']));
$today = date("d-m-Y");
$older= date("d-m-Y",strtotime("-15 day"));
if (strtotime($todaydate) <= strtotime($older))
{
$todaydate= $today;
}
?>
$previousDate = "2012-09-30";
if (strtotime($previousDate) <= strtotime("-15 days")) {
//the date in $previousDate is earlier or is equal to the date 15 days before from today
}