php mysql print list with db data - php

Question

I'm trying to improve a php script that prints a list with db values and I need to make some complex (for me) operations to achieve what I want:
A list that prints the months and if they are paid or not, a bonus value with an extra bonus value for the first 3 ids and if the user already received it.
if ($stmt = $mysqli->prepare(" SELECT members.*, account_type.*, friends.*, friendsCount.friendID,
COUNT(friendsCount.friendID) AS num_f
FROM members
INNER JOIN account_type ON account_type.id = ?
INNER JOIN friends ON friends.friendID = ?
INNER JOIN friends AS friendsCount ON friendsCount.userID = ?
WHERE members.id = ?")) {
$stmt->bind_param('iiii', $_SESSION['acc_type'], $_GET['id'], $_SESSION['user_id'], $_GET['id']);
$stmt->execute();
$result = $stmt->get_result();
$row = $result->fetch_array();
$monthNames = array("Enero", "Febrero", "Marzo", "Abril", "Mayo", "Junio", "Julio", "Agosto", "Septiembre", "Octubre", "Noviembre", "Diciembre");
$paid = array(); //Placeholder for paid months.
for ($i = 1; $i < 13; $i++) {
$month = 'month' . $i;
$bonus_month = 'bonus_month' . $i;
// check if the user received the monthly bonus
if ($row[$bonus_month] == 0) {
// check if the friend's member account is active
if ($row['status'] == 1) {
// check if the friend paid the month
if ($row[$month] == 1) {
$paid[] = 'Pagado';
// check the user account type
if ($row['type'] == 'Base') {
// TODO: check if the friend is one of the three first (special promotion)
// (user gets double bonus for the first three invited friends)
if ($row['extra'] == 1) {
$extra = $row['bonus'] + 5;
$bonus[] = $extra . '€';
}
else {
$bonus[] = $row['bonus'] . '€';
}
}
else {
$bonus[] = $row['bonus'] . '€';
}
$cashed[] = 'No';
$non_cashed[] = $bonus[];
}
else {
$paid[] = 'No Pagado';
$bonus[] = 'n/a';
$cashed[] = 'n/a';
}
}
else {
$paid[] = 'n/a';
$bonus[] = 'n/a';
$cashed[] = 'n/a';
}
}
else {
$paid[] = 'Pagado';
$bonus[] = $row[$bonus_month] . '€';
// TODO: find a way to check if user already received the bonus
// 12 new columns? (bonus_received_month1-12)
if (1 == 0) {
$cashed[] = 'Si';
$total_cashed[] = $row[$bonus_month];
}
else {
$cashed[] = 'No';
$non_cashed[] = $row[$bonus_month];
}
}
}
//Now make the HTML list
foreach ($monthNames as $key => $month) {
echo '
<div class="list">
<ul>
<li><a class="month">' . $month . '</a></li>
<li><a class="status">' . $paid[$key] .'</a></li>
<li><a class="bonus">' . $bonus[$key] . '</a></li>
<li><a class="cashed">' . $cashed[$key] . '</a></li>
</ul>
</div>';
}
} else echo $mysqli->error;
Actually it's working quite well but somethings are not implemented yet:
1º The extra bonus value for the first 3 ids (not including the status 0 accounts).
2º A way to check if the user already received the bonus so can be displayed the balance and the total received:
First of, I'd like to improve the method that adds the extra bonus:
// this column contains 1 for the first 3 friendIDs
if ($row['extra'] == 1) {
$extra = $row['bonus'] + 5;
$bonus[] = $extra . '€';
} else $bonus[] = $row['bonus'] . '€';
To achieve this: I have to check for the first 3 friendIDs (where userID = $_SESSION[user_id]) and compare if one of those match the current $_GET['id'].
// the number of friends
$count = $row['num_f'];
// the current friendID
$f_id = $_GET['id'];
$match = 'the first 3 ids (with acc status 1)';
if ($count > 2 && $f_id == $match) {
$extra = $row['bonus'] + 5;
$bonus[] = $extra . '€';
} else $bonus[] = $row['bonus'] . '€';
And statistics info:
// not received
echo '<p>Total acumulado: ' . array_sum($non_cashed[]) . '€</p>';
// total received
echo '<p>Total recibido: ' . array_sum($total_cashed[]) . '€</p>';
The big problem that I'm facing here is: If one of the three first accounts is inactive (status 0) how to "take" the next one that is active...
If account 1 is inactive but 2 and 3 are not, the account number 4 should be eligible for the extra bonus. The numbers are just the order that come from "select friendID from friends where userID = ?"
I presume that I can use array_key_exists to check if the $f_id exist inside the array that contains the first 3 ids...
How can I make that? Sorry if I made some mistakes, I'm working for several hours.
The tables are:
1º members: get the friend info -> "id", "status" (0 or 1; inactive/active), "name" and "month1-12" (12 columns: 0 or 1; not paid / paid month)
2º account_type: get the user acc type and the bonus value -> "id" (members.acc_type), "type" (the type name) and "bonus" (5, 10, 15 etc...)
3º friends: get the user info related to his friend -> "friendID" (members.id, the invited user), "userID" (members.id, the user that invited a friend), "extra" (1 for the first 3 invited users and 0 for the rest; 1 is double bonus, 0 is normal bonus. This column is going to be deleted), "bonus_month1-12" (12 columns; 0 is for the current month or a future month, 1+ is the bonus the user gained this month)
And to check if the user already received the bonus, I'm thinking to add 12 more columns to know it. It'll be 0 for non-received and 1 for received, unless a better method is suggested :)