I have a date, in the format yyyy-mm-dd that has been pulled from a MySQL database. This date is saved to a variable $myDate.
I want to save the date, three weeks before this variable's date, to a new variable called $otherDate. How can I do this (and ideally, change the format of the date at the same time)?
I tried:
$otherDate = date("l d F", strtotime("-3 weeks", $myDate));
but to no avail.
The best way to get your head around strtotime is to look at the doc page for it:
The format expected is int strtotime ( string $time [, int $now = time() ] )
And the parameters are defined as:
time
A date/time string. Valid formats are explained in Date and Time Formats.
now
The timestamp which is used as a base for the calculation of relative dates.
Therefore $otherDate = date("l d F", strtotime("-3 weeks", $myDate)); is not correct since $myDate is not an integer but a string in yyyy-mm-dd format.
You must pass the $myDate into the string with the -3 weeks modifier:
$otherDate = date("l d F", strtotime("$myDate -3 weeks"));
Or if you want to redefine $now within the strtotime parameters:
$otherDate = date("l d F", strtotime("-3 weeks", strtotime($myDate)));
I would however recommend using a DateTime object:
$otherDate = new DateTime($myDate);
$otherDate->sub(new DateInterval('P3W'));
echo $otherDate->format('l d F');
The second argument to strtotime() must be a timestamp, not a string, so
$otherDate = date("l d F", strtotime("-3 weeks", strtotime($myDate)));
But look at using DateTime objects instead
$date = new \DateTime( $myDate );
$otherDate = clone $date;
$otherDate->sub( new \DateInterval('P3W') );
echo $otherDate->format( 'l d F' );
Since I find procedural date manipulation ugly and constrictive, I'm going to suggest using PHP's awesome DateTime class.
$dt = new DateTime('2014-11-28');
$dt->modify('-3 weeks');
echo $dt->format('l d F');
Because you are using the strtotime wrong way.
Check this:
$otherDate = date("l d F", strtotime("2014-11-28 -3 weeks"));
echo $otherDate;
Output:
Friday 07 November
Related
In php I have time like this
$time = '2015-06-29T16:00:00Z';
I want to convert that time like this format Tuesday, December 16, 2015 3:00 PM
For that I tried
echo date( 'jS F Y', strtotime( $time) );
but it is showing time like 1st January 1970
So can someone help me to get the actual time format as I want.
A simple DateTime class usage should suffice, just feed it into the constructor, the just use ->format and provide the desired output format:
$time = '2015-06-29T16:00:00Z';
$date = new DateTime($time);
echo $date->format('jS F Y');
Sample Output
You can use the DateTime class for better handling of dates
$time = '2015-06-29T16:00:00Z';
$dateTime = new DateTime($time);
echo $dateTime->format('l, F d, Y g:i A');
$time = '2015-06-29T16:00:00Z';
echo date( 'l, F j, Y H:i A',strtotime($time));
l, F j, Y H:i A can be re-ordered to change the output.
About date function, http://php.net/manual/en/function.date.php
Just pass proper format parameters to it.
$time = '2015-06-29T16:00:00Z';
echo date( 'l, F j, Y g:i A', strtotime( $time) );
Use preg_split:
$parts = preg_plit("/Z/",$time);
$parts = preg_split("/T/",$parts[0]);
$theDate=$parts[0];
$theTime=$parts[1];
$what_you_want=date(strtotime($theDate." ".$theTime);
Note that you can still change the format of the output.
I have $date = $run['at'];, which gives me 2013-06-03T16:52:24Z. How can I manipolate it to get for example "d M Y, H:i" ?
You should use the DateTime class.
$date = new DateTime($run['at']);
echo $date->format('d M Y, H:i');
You can use:
$time = strtotime($run['at']);
echo date("Y-m-d", $time);
But, where does $run['at'] come from?
I have dates currently in this format: yy-mm-dd (e.g. 2011-11-18)
I want them in this format: Friday 18 November 2011
I've tried reading through the PHP documentation manual, but I can't see how to manage dates in the format that I have. If the date needs to be in a different order I can arrange that, but I'm a bit stuck at the meoment.
Any help would be much appreciated.
Use PHP5s new date classes. Much cleaner:
$date = DateTime::createFromFormat('Y-m-d', '2011-11-18');
echo $date->format('l d F Y');
date('l j F Y', strtotime($date));
Just use starttime to change the the dates in many formats using this link.
echo date('l d F Y');
gives you the date format you want.
This was all in the manual you yourself linked.
just use strtotime to get back a timestamp and then use date() to format that:
$date = '2011-11-18'; // your date
$timestamp = strtotime($date); // convert to a timestamp
$new_date = date('l j F Y',$timestamp) // format timestamp
echo $new_date;
I am using $date = date("D M d, Y G:i");.
When I echo $date, it shows the correct date/time. Now I need this as an string.
I have tried string($date); but nothing happens here. And
$today = strtotime($date);
here I get weird numbers..
I need a string so I can put $today in a message.
What is the correct method for this?
The date() function already returns a string.
Doing this :
$date = date("D M d, Y G:i");
You'll have the current date in the $date variable, as a string -- no need for any additional operation.
If you like working with objects you can do this:
$date = new \DateTime('now');
echo $date->format('D M d, Y G:i');
Your $date variable is a string, there's no need for any conversion.
You can have a look at the documentation: http://ch.php.net/manual/en/function.date.php. The return value of the date() function is string.
The strange numbers you see when you call strtotime() is the Unix timestamp which represents the number of seconds elapsed since January 1 1970 00:00:00 UTC.
You're already getting a string. $date can be used like any string now.
strtotime() actually gives you the number of seconds in time like unix
$date = 'Today is '.date("D M d, Y G:i", time());
echo $date;
With regards to:
$today = strtotime($date);
Those numbers are the current timestamp (the number of seconds since January 1st 1970).
You can use this as a second parameter in the date function to change the date to whatever you want.
$newDate = date("D M d, Y G:i", $timeStamp);
I have date in format 2011-01-28 06:34:33 i.e. date("Y-m-d H:i:s"). I want to convert it into 28th January 2011.
How can I change it?
Supply the date function with your format, which can be found here. Pass the timestamp of your original date as the second parameter to date. You can obtain the timestamp by using strtotime.
date("dS F Y", strtotime("2011-01-28 06:34:33"));
Use
$dateStr = date("jS F Y", time());
The day value is without leading zero.
Try this echo date('jS F Y h:i:s A');