I have a little problem with the displayField in combination with virtualFields.
I have a File that belongsTo 2 different Users.
public $belongsTo = array(
'Creator' => array(
'className' => 'User',
'foreignKey' => 'creator_id',
),
'Editor' => array(
'className' => 'User',
'foreignKey' => 'editor_id',
)
);
As virtualField and displayField in the User Model. I use the following code:
public $virtualFields = array(
'full_name' => "CONCAT(first_name, ' ',last_name)"
);
public $displayField = 'full_name';
Creating a new File works fine, but if I want to view all my files I get the following error:
Error: SQLSTATE[23000]: Integrity constraint violation: 1052 Column 'first_name' in field list is ambiguous
I already read about it a little here:
http://book.cakephp.org/2.0/en/models/virtual-fields.html
At the end there are some limitations about virtualFields, so I tried to add this to the Controller:
$this->virtualFields += $this->Creator->virtualFields;
$this->virtualFields += $this->Editor->virtualFields;
But somehow this doesn't change anything.
Hope you can help me with this little problem.
Thanks in advance!
I guess you need 2 virtual fields:
$this->File->virtualFields = array(
'Creator__full_name' => "CONCAT(Creator.first_name, ' ',Creator.last_name)",
'Editor__full_name' => "CONCAT(Editor.first_name, ' ',Editor.last_name)"
);
Related
I have joined with two table by using model association. This two tables are films and movie_streams But there is some error
My Query:
$film = Film::model()->with('movie_streams')->find(array('select' => '*', 'condition' => 'user_id=:user_id, 'params' => array(':user_id' => $user_id)));
Film.php model:
public function relations() {
return array(
'movie_streams' => array(self::HAS_MANY, 'MovieStream','movie_id'),
);
}
Error Message:
CDbCommand failed to execute the SQL statement: SQLSTATE[23000]: Integrity constraint violation: 1052 Column 'user_id' in where clause is ambiguous
I saw by default taking alias name. For films table t and for movie_streams table t0
How to set manual alias what I want for my above two tables?
You can avoid the collision of tables aliases by specifying the alias property of the relation.
$comments = Comment::model()->with(array(
'author',
'post',
'post.author' => array('alias' => 'p_author'))
)->findAll();
use
model_name.feild_name
$film = Film::model()->with('movie_streams')->find(array('select' => '*', 'condition' => 'film.user_id=:user_id, 'params' => array(':user_id' => $user_id)));
or
avoid collision of table by using allias
$comments=Comment::model()->with(array(
'author',
'post',
'post.author'=>array('alias'=>'p_author')))->findAll(array(
'order'=>'author.name, p_author.name, post.title'
));
, more details here
I just cant get data from 2 tables in a HABTM relationship and I cant get the answer for these cakephp docs (again). Sorry for asking the question on something that should be explained in the docs.
This should be a simple but I keep getting undefined index and the relationship I set up seems in accordance with the docs. I have another post on a more complicated matter but this issue needs to be isolated .
I dont know how to get related data from the lessons table and the students table via this lessons-students HABTM table.
I want all the lessons a student does. I want the name of the student from the student table and lesson details from the lesson table which has lesson_id as the common link in this lessons-students table. Sounds simple but I cant do it.
public $hasAndBelongsToMany = array(
'Student' => array(
'className' => 'Student',
'joinTable' => 'lessons_students',
'foreignKey' => 'lesson_id',
'associationForeignKey' => 'student_id',
'unique' => 'keepExisting',
)
);
class LessonsController extends AppController {
....
$this->Lesson->recursive = -1;
$options['joins'] = array(
array('table' => 'lessons_students',
'alias' => 'LessonsStudent',
'type' => 'LEFT',
'conditions' => array(
'Lesson.id = LessonsStudent.lesson_id',
)
),
array('table' => 'students',
'alias' => 'Student',
'type' => 'LEFT',
'conditions' => array(
'LessonsStudent.student_id=Student.id',
)
),
);
$options['conditions'] = array('Student.id' => 2);
// $Item->find('all', $options);
$student=$this->set( 'student',$this->Lesson->find('all', $options));
In the view I get the error undefined index Student
<?php
// debug($student);
foreach ($student as $item2):
echo '<td>'. $item2['Lesson']['id'].'</td>';
echo '<td>'. $item2['Student']['id'].'</td>';
http://stackoverflow.com/questions/17250215/cant-get-all-user-data-from-habtm-in-cakephp
http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html#hasandbelongstomany-habtm
If you want to use model association you need to remove $this->Lesson->recursive = -1; because it disable any associations defined in model. And than you can remove $options['joins'].
If you have defined many association in your Lesson model and don't want to fetch all of it use unbindModel() or use Containable behavior
$this->Lesson->Behaviors->load('Containable');
$this->Lesson->contain('Student');
If you need to do find many times in many actions it's better to enable Containable in model itself
class Lesson extends AppModel {
public $actsAs = array('Containable');
}
so you can avoid $this->Lesson->Behaviors->load('Containable'); line;
I have this:
$this->request->data['Person']['person_id'] = $this->Session->read('insertedPersonID');
$savedPerson = $this->Person->saveAll($this->request->data, array('validate'=>'first'));
which updates the selected person row fine however its related tables like PersonColor and PersonParts are not updating, instead inserting new rows.
I thought cake automatically updates the related tables as well as long as the id of the main table which is the foreign key for the other two tables are provided since doing this:
$savedPerson = $this->Person->saveAll($this->request->data, array('validate'=>'first'));
inserts to the Person table and the other two related two tables fine.
How do I make it update the other two tables as well?
Edit:
For the model relations:
Person Model:
public $hasMany = array(
'PersonParts' => array(
'className' => 'Part',
'foreignKey' => 'part_person_id'
),
'PersonColors' => array(
'className' => 'Color',
'foreignKey' => 'color_person_id'
)
);
Part Model:
public $belongsTo = array(
'PartPerson' => array(
'className' => 'Person',
'foreignKey' => 'part_person_id'
)
);
Color Model:
public $belongsTo = array(
'ColorPerson' => array(
'className' => 'Person',
'foreignKey' => 'color_person_id',
'conditions' => '',
'fields' => '',
'order' => ''
)
);
edit 2
var_dump of $this->request->data
array(3){
["Person"]=>array(4){
["person_user_id"]=>string(1)"3"
["person_name"]=>string(9)"Britney"
["person_category_id"]=>string(2)"16"
["visibility"]=>string(1)"1"
["person_id"]=>string(1)"71"
}
["PersonParts"]=>array(1){
[0]=>array(3){
["part_name"]=>string(4)"hands"
["quantity"]=>string(1)"2"
["part_part_type_id"]=>string(1)"1"
}
}
["PersonColors"]=>array(2){
[0]=>array(4){
["color_name"]=>string(3)"blue"
["test_field1"]=>string(1)"8"
["test_field2"]=>string(1)"9"
["position"]=>int(1)
}
[1]=>array(2){
["color_name"]=>string(5)"red"
["position"]=>int(2)
}
}
}
Note: This var_dump is only showing ["person_id"]=>string(1)"71" under Person array as the added field to make cake do an update, not insert... person_id is not showing under the PersonParts and PersonColors here since it's not working that way. What should I pass or How should I do an update on the other 2 related tables?
To make Cake do an update on the related tables, you do need to pass in the id of the related record, otherwise Cake won't know which record to update.
You can make this a hidden field in your form, which is how I do things.
The var dump for PersonParts should look like this (note the extra 'part_id' field):
["PersonParts"]=>array(1){
[0]=>array(3){
["part_id"]=>string(1)"7"
["part_name"]=>string(4)"hands"
["quantity"]=>string(1)"2"
["part_part_type_id"]=>string(1)"1"
}
}
If you don't pass the id, then (from memory) Cake will delete the existing related records, and add new ones.
I'm working on an already existing cakephp 1.3 project and I needed to add a new table to the database. I have this in my controller:
$conditions = array('ShootingPlacement.person_id' => $id, 'Email.person_id' => $id, 'Email.shooting_placement_id' => 'ShootingPlacement.id');
$shootingPlacements = $this->ShootingPlacement->find('all', compact('conditions'));
And it's giving me this error:
Warning (512): SQL Error: 1054: Unknown column 'Email.person_id' in 'where clause' [CORE/cake/libs/model/datasources/dbo_source.php, line 684]
And ths is the query it's trying to create:
SELECT `ShootingPlacement`.`id`, ... FROM `shooting_placements` AS `ShootingPlacement`
LEFT JOIN `people` AS `Person` ON (`ShootingPlacement`.`person_id` = `Person`.`id`)
LEFT JOIN `shootings` AS `Shooting` ON (`ShootingPlacement`.`shooting_id` = `Shooting`.`id`)
WHERE `ShootingPlacement`.`person_id` = 123688 AND `Email`.`person_id` = 123688 AND `Email`.`shooting_placement_id` = 'ShootingPlacement.id'
ORDER BY `lastname` ASC
Obviously my controller code is wrong, but I'm not sure how to relate the Email table to the ShootingPlacement one. I think my models are correct. So far if I have this:
$conditions = array('ShootingPlacement.person_id' => $id);
$shootingPlacements = $this->ShootingPlacement->find('all', compact('conditions'));
It will retrieve the rows from Shooting, ShootingPlacement and Person, I want Email to be there too. Email has 2 foreign keys: one from ShootinPlacement and one from Person.
These are the models, the only one I created is Email, the rest where working correctly.
class Email extends AppModel
{
var $name = 'Email';
var $belongsTo = array
(
'Person' => array
(
'className' => 'Person',
'foreignKey' => 'person_id'
),
'ShootingPlacement' => array
(
'className' => 'ShootingPlacement',
'foreignKey' => 'shooting_placement_id'
)
);
}
class ShootingPlacement extends AppModel
{
var $name = 'ShootingPlacement';
var $belongsTo = array
(
'Person' => array
(
'className' => 'Person',
'foreignKey' => 'person_id',
'order' => 'lastname ASC'
),
'Shooting' => array
(
'className' => 'Shooting',
'foreignKey' => 'shooting_id'
)
);
}
class Person extends AppModel
{
var $name = 'Person';
var $belongsTo = array
(
'PersonOrigin' => array
(
'className' => 'PersonOrigin',
'foreignKey' => 'person_origin_id'
)
);
var $hasMany = array
(
'ShootingPlacement' => array
(
'className' => 'ShootingPlacement',
'foreignKey' => 'person_id',
'dependent' => false
)
);
}
class Shooting extends AppModel
{
var $name = 'Shooting';
var $belongsTo = array
(
'ShootingLocation' => array
(
'className' => 'ShootingLocation',
'foreignKey' => 'shooting_location_id'
),
'Emission' => array
(
'className' => 'Emission',
'foreignKey' => 'emission_id'
)
);
}
What I need on the view is to loop through the ShootingPlacement variable and I need it to contain the Email table data for that specific id of ShootingPlacement and Person (As you see in the query, Person and ShootingPlacement are in a relationship already, I only need there to be Email too)
You should be very careful with the relationship you're after. From a quick glance at some of these answers, they seem to suggest you simply add a join to the Email model into your Person model and rely on the conditions of your find to ensure your query doesn't ransack your server's memory.
I'm going to assume that first of all, you want this Email relationship to be implicit in all your queries on Person, otherwise you could simply specify the join on each query you wanted it for. In this case, you definitely want to link it using model relationships.
Your code shows that Shooting and ShootingPlacement (presume this is a model to model mapping relationship) both belong to two models. Incidentally, Shooting belongsTo Emission - which we haven't seen here yet. I assume this isn't applicable to the current scenario.
Now, let's assume off the bad that because your Email table has foreign keys, it will be a hasOne relationship, rather than a hasMany - so that's what you need to link it by. I'm going to link it to the ShootingPlacement model because this is the model you are querying, so it should be the central point at which models are joined around it. Structure wise, because everything seems to originate from your Person model, I would have to suggest you query that model instead. But the way it's set up so far will allow you to query from nearly anywhere and still retrieve mostly the same results bar a few model names and table aliases.
Purely because your foreign key between Email and ShootingPlacement has a different name, and CakePHP 1.3 doesn't handle this very well, I'm also going to suggest you don't use a foreign key, instead putting it into the relationship as conditions.
class ShootingPlacement extends AppModel
{
var $name = 'ShootingPlacement';
var $actsAs = array('Containable');
var $hasOne = array(
'Email' => array(
'className' => 'Email',
'foreignKey' => false,
'conditions' => array(
'Email.shooting_placement_id = ShootingPlacement.id',
'Email.person_id = ShootingPlacement.person_id'
)
)
);
var $belongsTo = array (
'Person' => array (
'className' => 'Person',
'foreignKey' => 'person_id',
'order' => 'lastname ASC'
),
'Shooting' => array (
'className' => 'Shooting',
'foreignKey' => 'shooting_id'
)
);
}
I've also added the containable behaviour in there. This allows you to control from each query which associated models you'd like to return with your primary model results. It will default to all, but can be handy when you only want something specific and/or for memory reasons (these kinds of queries can destroy your server memory pretty quickly if you don't limit them or specify only the field names you want to return).
Now when you create your Email model, I wouldn't suggest complicating this mess of entangled models any further by linking it back to ShootingPlacement again. As you've said, it also has a foreign key to the Person model. So you might want to do exactly the same thing as above for your Person model (changing the conditions to reflect the Person foreign key of course). This way your model is a little more flexible; it will still join to ShootingPlacement and Person, and will also allow you to query it seperately if required without the other associated models.
Documentation
CakePHP 1.3 Model Associations
CakePHP 1.3 Containable Behaviour
See also
This article on Stack
In your model add containable behavior
class Email extends AppModel {
var $name = 'Email';
var $actsAs = array('Containable');
var $belongsTo = array
(
'Person' => array
(
'className' => 'Person',
'foreignKey' => 'person_id'
),
'ShootingPlacement' => array
(
'className' => 'ShootingPlacement',
'foreignKey' => 'shooting_placement_id'
)
);
}
Just write the below code in your controller.
$this->ShootingPlacement->recursive = 2;
$this->ShootingPlacement->contain = array(
'Shooting',
'Person' => array(
'Email'
)
);
$conditions = array(
'ShootingPlacement.person_id' => $id,
'Email.shooting_placement_id' => 'ShootingPlacement.id'
);
$shootingPlacements = $this->ShootingPlacement->find('all', compact('conditions'));
Hope this helps you.
Add a $hasOne relation to Person model with Email like below
var $hasOne = array(
'Email' => array(
'className' => 'Email',
'foreignKey' => 'person_id' // Column defined for person ids in Email table
)
);
Then add
$this->ShootingPlacement->recursive = 2;
OR
you can simply use joins in cakephp to join email model. Refer cakephp joining tables
You need to link your model ShootingPlacement with "Email" with which you call it.
class ShootingPlacement extends AppModel
var $name = 'Shooting';
var $hasMany= array
(
'Email' => array
(
'className' => 'Email',
'foreignKey' => 'yourfk'
),
);
}
And uses it s very powerful ContainableBehavior !
exemple :
$contain=array('Email'=>array('fields'=>array('id','...')));
$conditions=array('ShootingPlacement.id'=>$yourId);
$this->ShootingPlacement->attachBehaviros('Containable');
$this->ShootingPlacement->find('all',$conditions);// your will retrieve yoru SHootingItem + Emails linked
This would provide the required join:
$conditions = array('ShootingPlacement.person_id' => $id, 'Email.person_id' => $id, 'Email.shooting_placement_id' => 'ShootingPlacement.id');
$joins = array(
array(
'table' => 'emails',
'alias' => 'Email',
'type' => 'LEFT',
'conditions' => array('Email.shooting_placement_id = ShootingPlacement.id')
)
);
$shootingPlacements = $this->ShootingPlacement->find('all',
array(
'conditions' => $conditions,
'joins' => $joins
)
);
I have been fighting with this code:
function getNextActionFObyBalance($when) {
$theQuery = $this->find('first', array(
'fields' => array(
'Contract.id',
'Contract.start_balance'
),
'conditions' => array(
'AND' => array(
'Status.next_action_by' => 'frontoffice',
'Status.status_type' => 'active',
'Status.visibility' => 'frontoffice',
'OR' => array(
'Contract.next_action_on' => null,
'Contract.next_action_on <=' => $when
)
)),
'order' => 'Contract.start_balance DESC',
'recursive' => 0,
));
return $theQuery;
}
I have enabled logging on the MySQL server at this is what the server indicates that CakePHP is requesting:
SELECT `Contract`.`id`, `Contract`.`start_balance` FROM `contracts` AS `Contract` LEFT JOIN `statuses` AS `Status` ON (`Contract`.`status_id` = `Status`.`id`) LEFT JOIN `users` AS `User` ON (`Contract`.`user_id` = `User`.`id`) WHERE ((`Status`.`next_action_by` = 'frontoffice') AND (`Status`.`status_type` = 'active') AND (`Status`.`visibility` = 'frontoffice') AND (((`Contract`.`next_action_on` IS NULL) OR (`Contract`.`next_action_on` <= '2010-09-13 10:13:04')))) ORDER BY `Contract`.`start_balance` DESC LIMIT 1
if I use that in the phpmyadmin tool, I get exactly what I was expecting 1 record with two fields. BUT CakePHP just gives me an empty result set.
Can anyone enlighten me?
PS the code was working but I can figure out what changed!
The problem was with a stub to do some post processing afterFind. The problem is that I have completely forgotten to return $results;
I found the error by doing a step by step debugging down the find method in model.php. Found that the after find was called at some point and went to check my afterFind.
Took my about 4 hours for a simple error but I am learning!
Presumably this method is defined in models/contract.php?
The recursive = 0 statement looks a bit suspect to me. Are the models correctly related in their respective model files?
Have you tried loadModel in case the associations aren't working properly?
It would be useful to see the relationship definitions from the respective models.
--EDIT--
I've formatted the code from your comment here as I can't edit your OP
var $belongsTo = array(
'Status' => array(
'className' => 'Status',
'foreignKey' => 'status_id',
),
'User' => array(
'className' => 'User',
'foreignKey' => 'user_id',
)
);
var $hasMany = array(
'Transaction' => array(
'className' => 'Transaction',
'foreignKey' => 'contract_id',
'dependent' => false,
)
);