Symfony2 FormType entity field type - php

Question

I have three entity. Profile, Car and Trip. When user(Profile) create Trip, he can chose the Car(only his own) and assign it to the Trip. I know the field must be the entity type. But I dont know how I can set to chose list a cars of current user(Profile). Any ideas? Thanks.

Answer 1

Filter the cars by user, I think this example is what you need:
$builder->add('car', 'entity', array(
'class' => '/path/to/entity/Car',
'property' => 'title',
'empty_value' => 'Choose a car',
'query_builder' => function(EntityRepository $em) use ($userId) {
return $em->createQueryBuilder('c')
->join('c.user', 'u')
->where('u.id = :userId')
->setParameter('userId', $userId);
}
)
)
You can add $userId as one form option:
$form = $this->createForm(new MyFormType(), $object, array( 'userId' => $userId ));
And inside your form retrieve it:
/**
* #param OptionsResolverInterface $resolver
*/
public function setDefaultOptions(OptionsResolverInterface $resolver)
{
$resolver->setDefaults(array(
'userId' => function (Options $options, $value) {
return $options['userId'];
}
));
}
/**
* #param FormBuilderInterface $builder
* #param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
if($options['userId']){
$userId = $options['userId'];
}
}

Answer 2

How I mentioned. other solution, even personally I don't prefer it:
$form = $this->createForm(new MyFormType($userId), $object);
And in your form, store it in a protected variable to be used later in your query:
/**
* Class MyFormType
*/
class MyFormType extends AbstractType
{
protected $userId;
/**
* #param $userId
*/
public function __construct($userId) {
$this->userId = $userId;
}
}

Answer 3

Take a look at this Symfony cookbook entry:
http://symfony.com/doc/current/cookbook/form/dynamic_form_modification.html#how-to-dynamically-generate-forms-based-on-user-data