Include single lines of php in ordered list - php

Question

I am fairly new to php and not sure if it is possible to include php file content line by line.
Say I have an ordered list and a php file with three lines. I can include the whole content using
<?php include 'myfile.php' ?>
my question is, if it is possible to include single lines.
myfile.php
apples
bananas
oranges
index.php
<ol>
<li>???????</li>
<li>???????</li>
<li>???????</li>
</ol>
Thanks

Answer 1

There are more possibilities one of them is to put your content in a text file and load the content with file for example. Then you can iterate through every line with foreach.
The other way is to put your values in an array if your don't need it in a file.
$fruits = array(
'apples',
'bananas',
'oranges'
);
Then you can iterate with foreach over that array.
http://php.net/manual/en/language.types.array.php
Before you start you should read about that things and perhaps you start at the beginning of that documentation.

Answer 2

You can read in the file as an array:
$myFile = file('myfile.php', FILE_IGNORE_NEW_LINES); // FILE_IGNORE_NEW_LINES strips the new line characters from the array
now you can either print a single line:
echo $myFile[2]; // echo the third item
or output everything as a HTML list:
echo '<ol>';
foreach ($myFile as item) {
echo '<li>'. $item .'</li>';
}
echo '</ol>';

Answer 3

You can do in various ways:
declaring variables for each one:
myfile.php
<?php
$apples = "apples";
$bananas = "bananas";
$oranges = "oranges";
and print them in the list:
index.php
<ol>
<li><?php echo $apples; ?></li>
<li><?php echo $bananas; ?></li>
<li><?php echo $oranges; ?></li>
</ol>
OR declaring one array with all of them.
myfile.php
<?php
$fruits = array( 'apples', 'bananas', 'oranges' );
and print them in the list using a foreach:
index.php
<ol>
<?php
foreach ($fruits as $fruit){
echo '<li>'.$fruit.'</li>';
}
?>
</ol>
Good Luck!