String Replace after the right most character - php

Here is my character
/public/proj/index.php/home
/public/proj/index.php/test
/public/proj/home
/public/proj/test
I just need to replace the character after the right most '/' to login. So that it will be
/public/proj/index.php/login
/public/proj/index.php/login
/public/proj/login
/public/proj/login

Try this -
$str = "/public/proj/index.php/home";
$vals = explode('/', $str);
$vals[count($vals)-1] = 'login';
$str = implode('/', $vals);
var_dump($str);

This should work for you:
$str = "/public/proj/home";
echo $str = substr_replace($str, "login", -1*(strlen(basename($str))), strlen(basename($str)));
Output:
/public/proj/login

Related

How to remove anything character after the part of link from string?

I have make a try like this:
$string = "localhost/product/-/123456-Ebook-Guitar";
echo $string = substr($string, 0, strpos(strrev($string), "-/(0-9+)")-13);
and the output work :
localhost/product/-/123456 cause this just for above link with 13 character after /-/123456
How to remove all? i try
$string = "localhost/product/-/123456-Ebook-Guitar";
echo $string = substr($string, 0, strpos(strrev($string), "-/(0-9+)")-(.*));
not work and error sintax.
and i try
$string = "localhost/product/-/123456-Ebook-Guitar";
echo $string = substr($string, 0, strpos(strrev($string), "-/(0-9+)")-999);
the output is empty..
Assume there are no number after localhost/product/-/123456, then I will just trim it with below
$string = "localhost/product/-/123456-Ebook-Guitar";
echo rtrim($string, "a..zA..Z-"); // localhost/product/-/123456
Another non-regex version, but require 5.3.0+
$str = "localhost/product/-/123456-Ebook-Guitar-1-pdf/";
echo dirname($str) . "/" . strstr(basename($str), "-", true); //localhost/product/-/123456
Heres a more flexibility way but involve in regex
$string = "localhost/product/-/123456-Ebook-Guitar";
echo preg_replace("/^([^?]*-\/\d+)([^?]*)/", "$1", $string);
// localhost/product/-/123456
$string = "localhost/product/-/123456-Ebook-Guitar-1-pdf/";
echo preg_replace("/^([^?]*-\/\d+)([^?]*)/", "$1", $string);
// localhost/product/-/123456
This should match capture everything up to the number and remove everything afterward
regex101: localhost/product/-/123456-Ebook-Guitar
regex101: localhost/product/-/123456-Ebook-Guitar-1-pdf/
Not a one-liner, but this will do the trick:
$string = "localhost/product/-/123456-Ebook-Guitar";
// explode by "/"
$array1 = explode('/', $string);
// take the last element
$last = array_pop($array1);
// explode by "-"
$array2 = explode('-', $last);
// and finally, concatenate only what we want
$result = implode('/', $array1) . '/' . $array2[0];
// $result ---> "localhost/product/-/123456"

Regular expression for finding multiple patterns from a given string

I am using regular expression for getting multiple patterns from a given string.
Here, I will explain you clearly.
$string = "about us";
$newtag = preg_replace("/ /", "_", $string);
print_r($newtag);
The above is my code.
Here, i am finding the space in a word and replacing the space with the special character what ever i need, right??
Now, I need a regular expression that gives me patterns like
about_us, about-us, aboutus as output if i give about us as input.
Is this possible to do.
Please help me in that.
Thanks in advance!
And finally, my answer is
$string = "contact_us";
$a = array('-','_',' ');
foreach($a as $b){
if(strpos($string,$b)){
$separators = array('-','_','',' ');
$outputs = array();
foreach ($separators as $sep) {
$outputs[] = preg_replace("/".$b."/", $sep, $string);
}
print_r($outputs);
}
}
exit;
You need to do a loop to handle multiple possible outputs :
$separators = array('-','_','');
$string = "about us";
$outputs = array();
foreach ($separators as $sep) {
$outputs[] = preg_replace("/ /", $sep, $string);
}
print_r($outputs);
You can try without regex:
$string = 'about us';
$specialChar = '-'; // or any other
$newtag = implode($specialChar, explode(' ', $string));
If you put special characters into an array:
$specialChars = array('_', '-', '');
$newtags = array();
foreach ($specialChars as $specialChar) {
$newtags[] = implode($specialChar, explode(' ', $string));
}
Also you can use just str_replace()
foreach ($specialChars as $specialChar) {
$newtags[] = str_replace(' ', $specialChar, $string);
}
Not knowing exactly what you want to do I expect that you might want to replace any occurrence of a non-word (1 or more times) with a single dash.
e.g.
preg_replace('/\W+/', '-', $string);
If you just want to replace the space, use \s
<?php
$string = "about us";
$replacewith = "_";
$newtag = preg_replace("/\s/", $replacewith, $string);
print_r($newtag);
?>
I am not sure that regexes are the good tool for that. However you can simply define this kind of function:
function rep($str) {
return array( strtr($str, ' ', '_'),
strtr($str, ' ', '-'),
str_replace(' ', '', $str) );
}
$result = rep('about us');
print_r($result);
Matches any character that is not a word character
$string = "about us";
$newtag = preg_replace("/(\W)/g", "_", $string);
print_r($newtag);
in case its just that... you would get problems if it's a longer string :)

PHP String Replacement Not Working Properly

Here is my PHP code,
$string = 'https://www.mydomain.lk/';
$wordlist = array("http://", "www.", "https://", "/");
foreach ($wordlist as &$word) {
$word = '/\b' . preg_quote($word, '/') . '\b/';
}
echo $string2 = preg_replace($wordlist, '', $string);
I want to remove last "/" from $string.
so i add the "/" to $wordlist array, but its not working.
can somebody help me to fix this.
Thanks.
It seems that for the most part you wish to extract the hostname:
$host = parse_url($url, PHP_URL_HOST);
Removing the leading www. can then be done separately.
preg_replace('/^www\./', '', $host);
You want to only replace / at the end of the string, so you need a $, like /$, but preg_quote would end up escaping the $.
The best way to remove a trailing / is using rtrim, like Sudhir suggested. Alternatively you could remove the preg_quote loop and just use regular expressions in your $wordlist:
$string = 'https://www.mydomain.lk/';
$wordlist = array("#https?://#", "#www\.#", "#/$#");
echo $string2 = preg_replace($wordlist, '', $string);
you could use rtrim():
$string = 'https://www.mydomain.lk/';
echo rtrim($string, '/'); //gives --> https://www.mydomain.lk
Try this
$url= 'https://www.mydomain.lk/';
echo $newurl = rtrim($url,"/");
Output like this format
https://www.mydomain.lk
Please try this:
$string = 'https://www.mydomain.lk/';
$uri = parse_url($string);
$domain = str_replace("www.", "", strtolower($uri['host']));
echo $domain;

How to remove unwanted commas from a string?

How can i remove duplicate commas used in string.
String = ",a,b,c,,,d,,"
I tried rtrim and itrim functions and removed the unwanted commas from beginning and ending .How can i remove duplicate commas ?
Try this:
$str = preg_replace('/,{2,}/', ',', trim($str, ','));
The trim will remove starting and trailing commas, while the preg_replace will remove duplicate ones.
See it in action!
Also, as #Spudley suggested, the regex /,{2,}/ could be replaced with /,,+/ and it would work too.
EDIT:
If there are spaces between commas, you may try adding the following line after the one above:
$str = implode(',', array_map('trim', explode(',', $str)))
i think you can just explode your string and then create a new one getting only relevant data
$string = ",a,b,c,,,d,,";
$str = explode(",", $string);
$string_new = '';
foreach($str as $data)
{
if(!empty($data))
{
$string_new .= $data. ',';
}
}
echo substr_replace($string_new, '', -1);
This will output
a,b,c,d
Live Demo
EDITED
If you are having problems with blank spaces you can try use this code
$string = ",a,b,c, ,,d,,";
$str = explode(",", str_replace(' ', '', $string));
$string_new = '';
foreach($str as $data)
{
if(!empty($data))
{
$string_new .= $data. ',';
}
}
echo substr_replace($string_new, '', -1);
This should solve spaces issue
Probably not very fast, but a simple method may be:
$str = "a,b,c,,,d";
$str2 = "";
while($str <> $str2) {
$str2 = $str;
$str = str_replace(',,', ',', $str);
}
<?php
$str = ",a,b,c,,,d,,"
echo $str=str_replace(',,','',$str);
?>
Output:
,a,b,c,d
<?php
$str = ",a,b,c,,,d,,"
echo $str=trim(str_replace(',,','',$str),',');
?>
Output:
a,b,c,d

Reversion Strings and replace a character - RegEx with Php

I have a doubt again on RegEx in Php.
Assume that I have a line like this
716/52 ; 250/491.1; 356/398; 382/144
I want the output to be
Replace all semi-colon with comma. I think I can do this using
$myline= str_replace(";", ",", $myline);
Interchange the numbers and replace '/' with a comma. That is, 716/52 will become 52,716. This is where I get stuck.
So, the output should be
52,716 , 491.1,250, 398,356, 144,382
I know that using sed, I can achieve it as
1,$s/^classcode:[\t ]\+\([0-9]\+\)\/\([0-9]\+\)/classcode: \2\,\1/
But, how do I do it using preg_match in php?
$str = '716/52 ; 250/491.1; 356/398; 382/144';
$str = str_replace(';', ',', $str);
$res = preg_replace_callback('~[\d.]+/[\d.]+~', 'reverse', $str);
function reverse($matches)
{
$parts = explode('/', $matches[0]);
return $parts[1] . ',' . $parts[0];
}
var_dump($res);
And working sample: http://ideone.com/BeS9j
UPD: PHP 5.3 version with anonymous functions
$str = '716/52 ; 250/491.1; 356/398; 382/144';
$str = str_replace(';', ',', $str);
$res = preg_replace_callback('~[\d.]+/[\d.]+~', function ($matches) {
$parts = explode('/', $matches[0]);
return $parts[1] . ',' . $parts[0];
}, $str);
var_dump($res);
As an alternative to Regexen you could try this:
echo join(', ', array_map(
function ($s) { return join(',', array_reverse(explode('/', trim($s)))); },
explode(';', $string)));
$str = '716/52 ; 250/491.1; 356/398; 382/144';
$str = preg_replace('(\d+(?:\.\d+)?)\/(\d+(?:\.\d+)?)', '$2,$1', $str);
$str = str_replace(';', ',', $str);
Uses two capture groups, replacing them in reverse order. See it here.

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