php foreach next month dates - php

Question

What I need is get listed next month days, every new day on new line.
Actually I want it look next:
date | username1 | username2
_________|___________|__________
| |
Mon - 01 | user5 | user2
| |
Tue - 02 | user3 | user2
....
and so on
Later i will be collect these dates and usernames to and update sql table (same type, like example here).
I have this code:
$workdays = array();
$type = CAL_GREGORIAN;
$month = date('n'); // Month ID, 1 through to 12.
$year = date('Y'); // Year in 4 digit 2009 format.
$day_count = cal_days_in_month($type, $month, $year); // Get the amount of days
//loop through all days
for ($i = 1; $i <= $day_count; $i++) {
$date = $year.'-'.$month.'-'.$i; //format date
$workdays[] = $i;
and with foreach echo i get days 1, 2, 3 ... and so on correctly, everyone on new line. But if i place inside foreach this:
<?php foreach($workdays as $value['date']): ?>
<tr>
<td><?php if ($value['date'] != 'dd'){
setlocale(LC_TIME, 'fi_FI.UTF-8');
echo ucfirst(strftime("%a - %d", strtotime($value['date'])));
} else {
echo 'wrong';
}?></td>
<td> </td>
</tr>
<?php endforeach ?>
I get on every new line Mon - 01.
What is wrong (after that, that i newbie on php)?

Answer 1

Try something like this.
<?php
$day_count = date('t',strtotime('+1 month'));
$month = date('m');
$year = date('Y');
if ($month == 12) { $month = 1; $year++; }
for($i = 1; $i<=$day_count; $i++) {
echo '<tr>';
echo '<td>'.date('D',strtotime("$month/$i/$year")).' '.$i."</td>";
echo '<td> </td>';
echo '</tr>';
}