yii2:autofill on multiple condtions - php

Question

I have models/tables as follows:
table room_category
id room_category
1 Classic
2 Deluxe
table room_charges
id room_category room_name room_charges
1 1 c1 600
2 2 d1 800
table ipd_charges
id doctor room_category charges_cash charges_cashless
1 1 1 200 300
2 1 2 300 400
table patient_detail(patient_admission)
id patient_name tpa_name(if not null, equivalent to charges_cashless)
1 1 Null
2 2 1
table daily_ward_entry
id patient_name room_name(id) doctor_name(id) charges ( from ipd_charges)
1 1 1 1 200
2 2 2 1 400
Now there is a dropdown field in daily_ward_entry table for doctor. When I select the drop-down field the charges field needs to be autofilled.
I achieve this using Jason and ajax with the following code without taking into account the room_category. but the charges vary for room_category.(this is only working after saving the record, I prefer if there is someway to pull the charges before save.)
Here is my code in the controller:
public function actionChargesCash($id){
$model = \app\models\IpdCharges::findOne(['doctor'=>$id]);
return \yii\helpers\Json::encode(['visit_charges'=>$model->charges_cash]);
}
public function actionChargesCashLess($id){
$model= \app\models\IpdCharges::findOne(['doctor'=>$id]);
return \yii\helpers\Json::encode(['visit_charges'=>$model->charges_cashless]);
}
I have also tried this variaton:
public function actionChargesCash($id){
$model = \app\models\IpdCharges::find()
->where(['doctor'=>$id])
->andwhere(['room_category'=>'daily_ward_entry.room_name'])->one();
If I replace the 'daily_ward_entry.room_name' with room_name id like 3 or 6, I am getting the result, which means I am not using the correct syntax for referring the column from current table.
How can I include the condition for room_name in the above code?
Thanks in advance for your valuable help.

Answer 1

daily_ward_entry.room_name is meaningless without any relation or join or sub-query. Actually, the query does not know the daily_ward_entry.
Suggestions:
1- Create a relation and use with or Join With
2- Create a query with Join of daily_ward_entry and ipd_charges on room_name=room_category
3- Create a query with a sub-query, to find all|one IpdCharge(s) that have room_category in SELECT room_name FROM daily_ward_entry
All of above suggestions satisfy your requirements.
Another important note:
andWhere()/orWhere() are to apply where to the default condition.
where() is to ignore the default condition
I don't see any default condition (Overridden Find()), So, there is no need to use andWhere, Just:
where(['doctor'=>$id,'room_category'=>3,...])
Would be sufficient.