Loop table to INSERT back to MySQL - php

Question

I have a PHP page that queries a database, and populates multiple tables with values. Those values need to be modified and placed in a separate table.
I know how to look through the database to show all the tables, but I can't find anything about how to loop through the html tables to reinsert the new values. I can't simply use an id and a ton of functions because there is an indeterminate number of rows.
Here is a list of the columns in the table I am accessing:
Here is a snippet of my code that I am using to access the database and populate the tables:
function tableAddData( $tableNum )
{
// Access Global Variables
global $noteId, $itemId, $quantityId, $costId, $laborHoursId, $totalHoursId, $materialCostId, $laborCostId, $totalCostId, $itemNumberId, $servername, $username, $password, $dbname, $quantityChangeId, $qtyRow;
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "select
`note` as `Note`,
`item` as `Item`,
`qty` as `Quantity`,
`cost` as `Cost`,
`hrsLabor` as `Labor Hours`,
`rate` as `Labor Rate`,
`qty` * `hrsLabor` as `Total Hours`,
FORMAT(`qty` * `cost`, 2) as `Material Cost`,
FORMAT(`qty` * `rate` * `hrsLabor`, 2) as `Labor Cost`,
FORMAT(( `qty` * `cost` ) + ( `qty` * `hrsLabor` * `rate` ), 2) as `Total Cost`,
`itemNo` as `Item Number`
from
`test_newtable`,
labor_rates
where
test_newtable.laborRate = labor_rates.id AND test_newtable.tableNo = " . $tableNum . ";";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
if ($row["Note"] != "" ) {
$noteHtml = '<td id="Note" class="text-center">
<span data-toggle="tooltip" data-placement="top" title="' . $row["Note"] . '">
<span class="glyphicon glyphicon-comment text-danger"></span>
</span>
</td>';
}
else {
$noteHtml = '<td></td>';
};
echo '
<tr>'
. $noteHtml . '
<td id="Item" >' . '<input class="text-left" value="' . $row["Item"] . '" disabled/></td>
<td id="Quantity">' . '<input class="text-center qty" id="qty-' . $qtyRow . '" value="' . $row["Quantity"] . '" /></td>
<td class="dollarRight" style="padding-left:0;padding-right:0; width:20px;">' . '<input class="text-center text-muted" value="$" disabled/></td>
<td id="Cost" class="dollarLeft">' . '<input class="text-right" id="cost-' . $qtyRow . '" value="' . $row["Cost"] . '" /></td>
<td id="Labor Hours">' . '<input class="text-right" id="laborHours-' . $qtyRow . '" value="' . $row["Labor Hours"] . '" /></td>
<td id="Total Hours">' . '<input class="text-right totalHours-' . $tableNum . '" id="totalHours-' . $qtyRow . '" value="' . $row["Total Hours"] . '" disabled/></td>
<td class="dollarRight" style="padding-left:0;padding-right:0; width:20px;">' . '<input class="text-center text-muted" value="$" disabled/></td>
<td id="Material Cost" class="dollarLeft">' . '<input class="text-right" id="materialCost-' . $qtyRow . '" value="' . $row["Material Cost"] . '" disabled/></td>
<td class="dollarRight" style="padding-left:0;padding-right:0; width:20px;">' . '<input class="text-center text-muted" value="$" disabled/></td>
<td id="Labor Cost" class="dollarLeft">' . '<input class="text-right" id="laborCost-' . $qtyRow . '" value="' . $row["Labor Cost"] . '" disabled/></td>
<td class="success dollarRight" width="1%" style="padding-left:0">' . '<input class="text-muted" value="$" disabled/></td>
<td id="Total Cost" class="success dollarLeft">' . '<input class="text-right totalCost-' . $tableNum . '" id="totalCost-' . $qtyRow . '" value="' . $row["Total Cost"] . '" disabled/></td>
<td id="Item Number">' . '<input class="text-left" value="' . $row["Item Number"] . '" disabled /></td>
</tr>
';
update($tableNum);
$qtyRow = $qtyRow + 1;
}
}
}
Here is an example of what the page looks like now:

Answer 1

You need to update the database with news values from a form in html?
you could use the name field in the input like name="tablename-columnname-rownumber", then in post php
foreach($_POST as $key=> $value){
$array = preg_split("/-/",$key);
if(count($array)==3) // if had 3 values
{
// update table $array[0] set $array[1] = $value where id = $array[2]
// update table (table name) set (column name) = (value from post) where id = (row number)
}
}
but is better if you put all in an array and just do one update by row
$arraytemp = array();
foreach($_POST as $key=> $value){
$array = preg_split("/-/",$key);
if(count($array)==3) // if had 3 values
{
$arraytemp[$array[0]][$array[2]][$array[1]]=$value;
}
}
foreach($arraytemp as $tablename => $tabledata){
$query = "update ".$tablename;
foreach($tabledata as $id => $columndata){
foreach($columndata as $columnname => $value){
$query .=' set '.$columnname'='.$value.';
}
$query.=' where id='.$id;
//exceute query
}
}
(i don't try it, just is what came to my mind, hope it works)