PHP/SQL Variable manipulation - php

I have the following variables:
$days_a = $array_total['days']; // This one display days
$hours_a = $array_total['hours']; // This one display hours
$minutes_a = $array_total['minutes']; // This one display minutes
$seconds_a = $array_total['seconds']; // This one display seconds
These variables give me the current session time, here all works.
Now the problem...
I have then these variables:
$days_f = $fetch_s['days'];
$hours_f = $fetch_s['hours'];
$minutes_f = $fetch_s['minutes'];
$seconds_f = $fetch_s['seconds'];
These display the time that the user entered in the website previously, they took the values from the database... I did this for add the current session variable values to the values in the MySQL Db:
$days_2 = $days_a + $days_f;
$hours_2 = $hours_a + $hours_f;
$minutes_2 = $minutes_a + $minutes_f;
$seconds_2 = $seconds_a + $seconds_f;
But I need that each 60 seconds it add 1 to $minutes_2 , each 60 minutes it add 1 to $hours_2 and each 24 hours it add 1 to $days_2
For example if I have 118 seconds I need that it adds 1 to $minutes_2 and set the variable $seconds_2 to 58 etc...
How can this be done?
I tried something like that:
$seconds = $seconds_2 % 60;
$minutes_3 = $seconds_2 / 60;
$minutes = $minutes_3 % 60;
$hours_3 = $minutes / 60;
$hours = $hours_3 % 24;
$days = $hours / 24;
$days = (int)$days_int;
But this won't work... Someone know how do that in a similar or different way?
Could someone give me the code? Please

In my experience it is easier to do these calculations by converting to UNIX seconds for a given time, adding the seconds, the converting back. That way the system does all the day, hour, minute and seconds book-keeping for you. Use e.g. mktime to convert to UNIX seconds (you can use your existing time parameters), and date, strftime to convert back to day, hour, minutes, seconds.

Related

PHP Get Time From X Percentage of Total Time

I don't know if this will make sense but I would like to get the time from percentage of a value, I have the following as an input example:
mypercentage = 50;
mytime = "00:59:59"
As you can see, my time is 60 minutes (1 hour) and 50% of that is 30 minutes therefore from the 2 above inputs I would like to get the following output
(50 % of an hour):
00:30:00
Explode the string into an array
Convert the 3 elements into numbers
Find the value in seconds. $array[0]*3600+$array[1]*60+$array[2]
Calculate the time from the value in step 3 and the percentage.
Use /3600 and /60 to find the hour and minutes and %60 to find the seconds.
put the values in an array and implode to a string, or just use
$hour.":".$minute.":".$second
Thank you all who responded, I found this solution to work:
$mypercentage = 50;
$mytime = '00:59:59';
$totaltime = date('H:i:s', strtotime($mytime));
$seconds = strtotime("1970-01-01 $totaltime UTC");
$per_seconds = ($mypercentage / 100) * $seconds;
$time_from_percentage = gmdate("H:i:s", $per_seconds);
echo $time_from_percentage;

Multiple hour by a number

I have something like that for example: 01:06:22 this represents 1hour, 6minutes and 22seconds. I want to take that, and multiple it by 6 and add it to some other hour such as 04:23 which is 4AM and 23Minutes not 4hours and 23 minutes.
Basically, as a result I expect that:
01:06:22
* 6 = 6hours 38minutes canceling the remaining seconds which are 12 in this case
Now, I want to take that and append it to other hour, 04:23 in this case, so the result would be:
11:01.
I have no clue how to start and do it, unfortunately.
Any help is appriciated!
Clarifications
The time that I have to multiple by 6 will never exceed 2 hours.
All the times are in the same format.
With DateTime it is simple:
$time = '01:06:22';
$dateSeconds = new DateTime("1970-01-01 $time UTC");
$seconds = $dateSeconds->getTimestamp() * 6;
$interval = new DateInterval('PT'.$seconds.'S');
$date = new DateTime('1970-01-01 04:23:00 UTC');
$date->add($interval);
echo $date->format('H:i:s');
Other solution with strtotime and gmdate. (Similar to Suresh but working):
$date = strtotime('1970-01-01 01:06:22 UTC');
$add = strtotime('1970-01-01 04:23:00 UTC');
$date = (($date*6)+$add);
echo gmdate('H:i:s', $date);
This is a solution if you want to implement it yourself.
The thing about timecode is that it can become really heavy with the if the if conditions etc if you don't do it right.
The best Way I thought of to deal with this is to convert everything to second.
so 01:06:22 would become:
numberOfSecond = 22 + 06 * 60 + 01 * 60 * 60
How to get the 22, 06 etc from the String? You can use Regex.
What you will need:
a function to extract the different values (hours, minute, second)
a function to convert the timecode into second
a function to convert back into timecode
the functions to multiply, add etc...
You might want to create a class for it.
You can try like this:
$date = strtotime('01:06:22');
$add = strtotime('00:04:23');
$date = ($date*6)+$add;
echo date('H:i:s', $date);
Note: Code is not tested.
First of all you want to multiply a time span by a factor. The easiest way to do this is to convert the span to seconds and do a straight multiply:
$date =DateTime::createFromFormat('!H:i:s', '01:06:22', new DateTimeZone('UTC'));
$seconds = $date->getTimestamp();
This code works by pretending that the time is a moment during the Unix epoch start so that it can then get the number of seconds elapsed since the epoch (the timestamp). That number is equal to the duration of the time span in seconds. However, it is vitally important that the input is interpreted as UTC time and not as something in your local time zone.
An equivalent way of doing things (as long as the input is in the correct format) which is lower-tech but perhaps less prone to bugs would be
list($h, $m, $s) = explode(':', '01:06:22');
$seconds = $h * 3600 + $m * 60 + $s;
Now the multiplication:
$seconds = $seconds * 6;
If you want to only keep whole minutes from the time you can do so at this stage:
$seconds = $seconds - $seconds % 60;
The final step of adding the result to a given "time" is not clearly specified yet -- does the reference time contain date information? What happens if adding to it goes over 24 hours?
Self explanatory :
$initialTime = '01:06:22';
$timeToAdd = '04:23';
$initialTimeExploded = explode( ':' ,$initialTime );
$initialTimeInMintues = ( $initialTimeExploded[0] * 60 ) + $initialTimeExploded[1];
$initialTimeInMintuesMultipliedBySix = $initialTimeInMintues * 6;
$timeToAddExploded = explode( ':' ,$timeToAdd );
$timeToAddExplodedInMintues = ( $timeToAddExploded[0] * 60 ) + $timeToAddExploded[1];
$newTimeInMinutes = $initialTimeInMintuesMultipliedBySix + $timeToAddExplodedInMintues;
$newTime = floor( $newTimeInMinutes / 60 ) .':' .($newTimeInMinutes % 60);
echo $newTime;
Result :
10:59

How to find time difference between 2 time vars greater than 24 hours

I need to find how much time is between to time values (their difference) which are over 24:00:00.
For example: how can I calculate the difference between 42:00:00 and 37:30:00?
Using strtotime, strptotime, etc is useless since they cannot go over 23:59:59 ....
$a_split = explode(":", "42:00:00");
$b_split = explode(":", "37:30:00");
$a_stamp = mktime($a_split[0], $a_split[1], $a_split[2]);
$b_stamp = mktime($b_split[0], $b_split[1], $b_split[2]);
if($a_stamp > $b_stamp)
{
$diff = $a_stamp - $b_stamp;
}else{
$diff = $b_stamp - $a_stamp;
}
echo "difference in time (seconds): " . $diff;
then use date() to convert seconds to HH:MM:SS if you want.
Date/Time variables and functions are not appropriate here as you're not storing time, but instead a time span of (I assume) hours, minutes, and seconds.
Likely your best solution is going to be to split each time span into their integer components, convert to a single unit (for instance, seconds), subtract them from each other, then re-build an output time span that fits with your application.
I havent tested this, but this might do what you want:
function timediff($time1, $time2) {
list($h,$m,$s) = explode(":",$time1);
$t1 = $h * 3600 + $m * 60 + $s;
list($h2,$m2,$s2) = explode(":",$time2);
$seconds = ($h2 * 3600 + $m2 * 60 + $s2) - $t1;
return sprintf("%02d:%02d:%02d",floor($seconds/3600),floor($seconds/60)%60,$seconds % 60);
}

How to return the amount of years passed?

My friend and I are working on a fairly basic uptime script for an IRC Bot.
Here's our code:
function Uptime()
{
global $uptimeStart;
$currentTime = time();
$uptime = $currentTime - $uptimeStart;
$this->sendIRC("PRIVMSG {$this->ircChannel} :Uptime: ".date("z",$uptime)." Day(s) - ".date("H:i:s",$uptime));
}
$uptimeStart is set immediately when the script runs, as time();
for some reason when I execute this function, it starts at 364 days and 19 hours. I can't figure out why.
Your $uptime is not a timestamp as should be used in date(), but a difference in time. You have an amount of seconds there, not a timestamp (that corresponds with an actual date.
just use something like this to cacluate (quick one, put some extra brain in for things like 1 day, 2 hours etc) ;)
$minutes = $uptime / 60;
$hours = $minuts/60 ;
$days = $hours / 24
etc
If you have 5.3 or above, use the DateTime and DateInterval classes:
$uptimeStart = new DateTime(); //at the beginning of your script
function Uptime() {
global $uptimeStart;
$end = new DateTime();
$diff = $uptimeStart->diff($end);
return $diff->format("%a days %H:%i:%s");
}
You won't get anything meaninful by calling date() on that time difference. You should take that time difference and progressively divide with years, months, days, hours, all measured in seconds. That way you'll get what the time difference in those terms.
$daySeconds = 86400 ;
$monthSeconds = 86400 * 30 ;
$yearSeconds = 86400 * 365 ;
$years = $uptime / $yearSeconds ;
$yearsRemaining = $uptime % $yearSeconds ;
$months = $yearsRemaining / $monthSeconds ;
$monthsRemaining = $yearsRemaining % $monthSeconds ;
$days = $monthsRemaining / $daySeconds ;
.. etc to get hours and minutes.
date() function with second argument set to 0 will actually return you (zero-date + (your time zone)), where "zero-date" is "00:00:00 1970-01-01". Looks like your timezone is UTC-5, so you get (365 days 24 hours) - (5 hours) = (364 days 19 hours)
Also, date() function is not the best way to show the difference between two dates. See other answers - there are are already posted good ways to calculate difference between years

Unix timestamp to seconds, minutes, hours

I need to somehow take a unix timestamp and output it like below
Can this be done with MySQL? Or php
Mike 7s ago
Jim 44s ago
John 59s ago
Amanda 1m ago
Ryan 1m ago
Sarah 1m ago
Tom 2m ago
Pamela 2m ago
Ruben 3m ago
Pamela 5h ago
As you can guess i only wanna print the minute, not minutes and seconds(1m 3s ago)
What should I look into?
Yes it can be done. See related post
$before // this is a UNIX timestamp from some time in the past, maybe loaded from mysql
$now = time()
$diff = $now - $before;
if( 1 > $diff ){
exit('Target Event Already Passed (or is passing this very instant)');
} else {
$w = $diff / 86400 / 7;
$d = $diff / 86400 % 7;
$h = $diff / 3600 % 24;
$m = $diff / 60 % 60;
$s = $diff % 60;
return "{$w} weeks, {$d} days, {$h} hours, {$m} minutes and {$s} secs away!"
}
PHP 5.3 and newer have DateTime objects that you can construct with data coming back from a database. These DateTime objects have a diff method to get the difference between two dates as a DateInterval object, which you can then format.
Edit: corrected sub to diff.
Edit 2:
Two catches with doing it this way:
DateTime's constructor doesn't appear to take a UNIX timestamp... unless prefixed with an #, like this: $startDate = new DateTime('#' . $timestamp);
You won't know what the largest unit is without manually checking them. To get an individual field, you still need to use format, but with just a single code... Something like $years = $dateDiff->format('y');
function sECONDS_TO_DHMS($seconds)
{
$days = floor($seconds/86400);
$hrs = floor($seconds / 3600);
$mins = intval(($seconds / 60) % 60);
$sec = intval($seconds % 60);
if($days>0){
//echo $days;exit;
$hrs = str_pad($hrs,2,'0',STR_PAD_LEFT);
$hours = $hrs-($days*24);
$return_days = $days." Days ";
$hrs = str_pad($hours,2,'0',STR_PAD_LEFT);
}else{
$return_days="";
$hrs = str_pad($hrs,2,'0',STR_PAD_LEFT);
}
$mins = str_pad($mins,2,'0',STR_PAD_LEFT);
$sec = str_pad($sec,2,'0',STR_PAD_LEFT);
return $return_days.$hrs.":".$mins.":".$sec;
}
echo sECONDS_TO_DHMS(2); // Output 00:00:02
echo sECONDS_TO_DHMS(96000); // Output 1 Days 02:40:00
PHP's date() function
as well as time() and some others that are linked in those docs
This can also be done in Mysql with date and time functions
You can try my Timeago suggestion here.
It can give outputs like this:
You opened this page less than a
minute ago. (This will update every
minute. Wait for it.)
This page was last modified 11 days
ago.
Ryan was born 31 years ago.
I dont have a mysql server at hand, but a combination of the following commands should get you something like what you want.
DATEDIFF
AND
DATEFORMAT

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