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Want to divide random integer number into equal five parts. And insert those values into array. Can any one tell me the logic for that.
Eg. I have 15 as my number. After dividing. It should generate the array as below.
$myArray = array('3','6','9','12','15');
Thanks in advance.
function getParts($number, $parts)
{
return array_map('round', array_slice(range(0, $number, $number / $parts), 1));
}
print_r(getParts(15, 5));
Explanation: range() generates the array of values starting with 0, ending when it reaches $number and using the step $number/$parts. It will get $parts+1 floating point numbers. array_slice() removes the first item (which is always 0). array_map() applies the function round() to each element to get the nearest integer.
Divide and create a loop to fill the array...
$total = 15;
$divide = 5;
$base = $total / $divide;
$arr = array();
for($i = 1; $i <= $divide; $i++) {
$arr[] = round($i * $base);
}
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I want to filter how many level I will add with my standard deviation result.
These are steps that I need to do:
Calculate the standard deviation based on array value. (solve)
Find the average of the array value and add with the standard deviation result.
eg : average = -49.7
s.d = 3.37
So, i need to keep adding the value until I get a new list of number.
eg: -49.7, -46.33, -42.96, -39.59
After that, I need to filter only print the array value from -49.7 to -39.59 only.
Can anybody help me on this?
Here is the script from what I could understand the question.
If you need any explanation or the code is not what you want then let me know in the comment section.
<?php
$array = [2,4,6,8,10];
$resultList = "";
$resultList_rounded = "";
function standardDeviation($array){
//sum of all values
$sum = array_sum($array);
//sum of (square of values)
$sum_of_square = array_sum(array_map(function($value){return $value*$value;},$array));
//X Bar
$xBar = average($array);
//variance
$variance = ($sum_of_square/count($array))-pow($xBar,2);
//standard deviation
return sqrt($variance);
}
function average($array){
return (array_sum($array)/count($array));
}
function newList($array,$rounded=false,$round_digits = 4){
$newarray = [];
$sd = standardDeviation($array);
$avg = average($array);
for($i=1;$i<=count($array);$i++){
if(empty($newarray)){
array_push($newarray,$avg);
continue;
}
if(!$rounded){
array_push($newarray,$array[$i-1]+$sd);
}else{
array_push($newarray,number_format((float) ($array[$i-1]+$sd), $round_digits, '.', ''));
}
}
return implode(',',$newarray);
}
function getRange($array){
return $array[0]." to ".$array[count($array)-1];
}
//get new list
$resultList = newList($array,true,0);
/*In the line above this, replace false with true if you want the rounded version and false if you want non rounded version. 4 means the number of digits to round.
examples:
$resultList = newList($array,true,4); will print 6,6.8284,8.8284,10.8284,12.8284
$resultList = newList($array,false,4); will print 6,6.8284271247462,8.8284271247462,10.828427124746,12.828427124746
$resultList = newList($array,true,0); will print 6,7,9,11,13
$resultList = newList($array,true,1); will print 6,6.8,8.8,10.8,12.8
*/
//print the new result list
echo $resultList;
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I am trying to get a number between 1 to 6 with more chances to be close to 1.
i have tried this:
<li>{{Faker\Factory::create()->biasedNumberBetween($min = 10, $max = 20, $function = 'unbiased')}}</li>
What i am trying to do is to generate a number from 1 to 6 rand(1,6); but make the numbers be closer to one as the lower numbers will have more weight than the others.
Something like this ?
<?php
function weightedRand($min, $max, $weightedMax) {
$arr = array();
for($i = 0; $i < 10; $i++) {
$arr[] = rand($min, $weightedMax);
}
$arr[] = rand($min, $max);
return $arr[rand(0,10)];
}
echo weightedRand(1,6, 3);
?>
numbers below 4 will now be more likely than numbers above :)
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I have long decimal numbers that I'd like to make easier to read. There's many 0's involved and I would like to bold the end of the string from where the numbers stop being just 0's. The number will always have 8 decimal places, no more, no less. It's worth noting that I would like any trailing zeros to also be bold, I don't just want to avoid bolding 0 as a whole.
Example:
Before - 0.00004320
After - 0.00004320
Any help or pointers in the right direction much appreciated.
Thanks.
You can do it using a loop and some string manipulation:
function doTheThing($number) {
$length = strlen($number);
$period = strpos($number, '.') + 1;
for ($i = $period; $i < $length; $i++) {
if ($number[$i] !== '0') {
$number = substr($number, 0, $i).'<b>'.substr($number, $i).'</b>';
break;
}
}
return $number;
}
echo doTheThing('0.00004320');
Or you can do it using a regular expression replacement:
function doTheThing($number) {
return preg_replace('/^(\d+\.0*)(\d+)$/', '$1<b>$2</b>', $number);
}
echo doTheThing('0.00004320');
echo doTheThing(sprintf('%.8f', 0.00004320)); // if your number is not a string
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I think the subject hits it better than I was expecting.
I need a function which returns random numbers which result in a given value (X) when they are summed up.
Something like this:
getRandomTo(10); // result for example: array(2,3,5)
getRandomTo(10); // result for example: array(4,3,3)
getRandomTo(12); // result for example: array(5,1,6)
I could not find a generic algorithm function for solving that requirement. Further more I cannot imagine a FAST and performant way to create something like this my self.
Please help me out
function getRandomTo($num)
{
$x = Array();
$i = 0;
do
{
$x[$i] = rand(1,$num);
$num = $num - $x[$i];
$i++;
}while($num > 0);
print_r($x);
}
Maybe do this:
create a random value between 0 and X; say this one is called r1. save this in your array.
create another random value between 0 and (X-r1), name it r2. save it also.
do these steps as often as you need it (or as long as r1+...+rn is lower than X)
Another solution:
function randomTo($numIn) {
$numOut = 0;
$numbers = array();
do {
$add = rand(1, $numIn);
if($numOut + $add > $numIn)
continue;
$numOut += $add;
$numbers[] = $add;
} while( $numOut != $numIn );
return $numbers;
}
$result = randomTo(15);
var_dump($result);
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I have a simple form and a submit button. After pressing the submit button, get the values (they will be numbers) and calculate the sum. And again calculate the sum of individual digits stored in sum.
A better explanation: 1+2+3+4=10 where 1,2,3 and 4 are user inputs from the form. And the sum 10 has to be split-ted and summed again as 1+0=1. And this would be my final result. So far I did the task where it gives me the first sum. I don't know what to do to display the second result which I want to be the finale.
<?php
$a='';
$sum='';
$total='';
if (!isset($_POST['submit'])) {
echo " ";
}
else {
$a = array($_POST['textfield'],$_POST['textfield1'],$_POST['textfield2'],$_POST['textfield3'],$_POST['textfield4'],$_POST['textfield5'],$_POST['textfield6'],$_POST['textfield7'],$_POST['textfield8'],$_POST['textfield9'],$_POST['textfield10'],$_POST['textfield11'],);
for ($i=0; $i<=12; $i++) {
$sum= array_sum($a);
$total= ;
}
}
echo "sbora e: $total ";
?>
$total = array_sum(str_split($sum));
Using Artefacto's method.
On another note,
$a = array($_POST['textfield'],$_POST['textfield1'],$_POST['textfield2'],$_POST['textfield3'],$_POST['textfield4'],$_POST['textfield5'],$_POST['textfield6'],$_POST['textfield7'],$_POST['textfield8'],$_POST['textfield9'],$_POST['textfield10'],$_POST['textfield11'],);
can be written as,
$a = array();
for ($i = 0; $i <= 11; $i++){
if (isset($_POST["textfield_$i"]))
array_push($a, $_POST["textfield_$i"]);
}
if the names of the fields are:
textfield_0, textfield_1, textfield_2...
So you want to build the cross sum of your first result:
$result2 = 0;
//cast integer to string
$strTotal = (string) $total;
//loop over "chars" and add them to your second result
for($i=0; $i < strlen($strTotal); $i++)
{
$result2 += $strTotal{$i};
}