Get json object from it's position in the list - php

Question

Let's say this is my json(I wont be able to change this json file):
{"success":true,
"users":{
"1036344647":{"name":"joel", "age":18},
"1036344365":{"name":"klant", "age":24},
"1036344352":{"name":"grabben", "age":23}
}
}
I also have a php code that collect this json data and decodes it.
$data = json_decode(file_get_contents("http://example.com/users/json"));
As you can see in my json each user has a random generated id that will change everytime i collect the data from my json file. Basicly i don't know any of the user ids.
But i still want to be able to print out a users name depending on it's position in the list.
For example: echo $data->users->[THE SECOND ID(the id with a user named "klant")]->name;
So i know this could be done easy if the json file was written as a array, but it is not.
Is there any way i can print out a object in the json depending on it's position in the list?

Answer 1

Try this:
function findUser($id)
{
$data = json_decode(file_get_contents("http://example.com/users/json"));
return isset($data[0]->users->$id) ? $data[0]->users->$id : null;
}
$user = findUser(1036344365);
var_dump($user);
It will output
object(stdClass)#4 (2) { ["name"]=> string(5) "klant" ["age"]=> int(24) }

Answer 2

You can build a 2nd array by "throwing away" those unique IDs with array_values() like so:
$array = json_decode($yourJSON, true);
$justValues = array_values( $array["users"] );
print_r( $justValues );
Output:
Array
(
[0] => Array
(
[name] => joel
[age] => 18
)
[1] => Array
(
[name] => klant
[age] => 24
)
[2] => Array
(
[name] => grabben
[age] => 23
)
)
You can then access each person's data like so:
echo $justValues[1]["name"]; // klant

Answer 3

No, it's not possible. JavaScript objects by design are unaware of "position" of their key-value pairs. Behind the scenes, that's what makes them powerful.
The first step is to rethink why you need to work with the JSON according to position.