I have my page as follows:
<form id="filterQuery" action="#" method="post">
...
<input type="submit">
</form>
<?php
// use $_POST to determine query restrictions and conditions
?>
Now my problem is with the action of the form, because if I make it "#" self, nothing happens when clicking submit.
I'm using a template which shows subpages as include in <div>s. In other words, my page is not a standard HTML page which contain <head> and <body> etc, but is in the following format: basic.php#!/my_sub_page.
Trying to make action "basic.php#!/my_sub_page" results in an empty _POST
I tried your example and everything works fine with /index.php#!/smth in action and post variables.
<form action="#!/something" method="post">
<input type="text" name="var1" value="123">
<input type="submit"></form>
<?php
print_r($_POST);
?>
This is how I check it.
Are you sure you didn't forget name attributes in inputs?
Do you see their values in url after ? if you change method to get?
Related
what I am trying to do is to create a from, and execute a php script after the submit has been pressed. the problem seems to be that the page of wprdpress with the form and the code gets executed all at once.
If I put the code below into a regular test.php file on my server, it does what it is supposed to do (echo "Form Submitted!") after I click submit. However if I put the same code in a page template or a wp page it spits it out all at once (the form, and the "form submitted).
<html>
<head>
<title>Notify on Submit</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
<label>Name: <input type="text" name="name" /></label>
<input type="submit" value="Submit" />
</form>
<?php if (count($_POST)>0) echo "Form Submitted!"; ?>
</body>
</html>
I have no idea why this is like that, and would really need some help on this.
What I have also done is to create two different wp pages(one goes to the other). It works, but will create a bit of a mess. I would like to do this in one page.
page 1
<form action="page2" method="POST">
Your form input.
<input type="submit" name="submit" />
</form>
Page 2
<?php
if (count($_POST)>0)
{
echo "Form Submitted!";
unset($_POST);
$_POST = array();
}
else echo "Form has been reset!";
?>
Probably there is another form on the Wordpress page using the POST method. Instead of checking for $_POST > 0 (which will only tell you that something was posted) add some identifier to your form, and check for that so you can tell if your form was posted.
A simple way to do this is with a hidden input:
<html>
<head>
<title>Notify on Submit</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
<label>Name: <input type="text" name="name" /></label>
<input type="hidden" name="whatform" value="myform" />
<input type="submit" value="Submit" />
</form>
<?php if (isset($_POST['whatform']) && $_POST['whatform'] == 'myform') echo "My Form Submitted!"; ?>
</body>
</html>
I think you just need to remove the php from your action. The action defaults to the current url on any form.
PHP_SELF refers to the file path - thats why it works when you do it on just a solo file. As part of the wordpress application, you can't run files directly - you have to reach that url.
Remember that WP uses actions and hooks, and so if you put code "in a WP page" or "in a template" it may fire at various times. You might get an echo statement that fires something to the screen before the content comes out. Consider putting all your output within filters, actions and hooks.
Your logic seems to depend on the post count. Consider using a unique name, i.e. the name of the submit button on your form. Check for if(isset($_POST['my-unique-submit-button'])). Is anything else in WP submitting via post? You might not know!
I've been working for several hours trying to get this to work properly. The page I have a form on is /index.php?action=pagename. I have a form that needs to get a variable from the following /index.php?action=pagename&thing=something. My HTML form going like this:
<form role="form" action="pagename" method="get">
<input type="text" name="thing">
</form>
This form is located on /index.php?action=pagename and I want to get &thing from that URL.
Any ideas?
The problem I'm having is that when the form is submitted, the URL redirects to index.php?thing instead of staying on index.php?action=pagename.
It looks like you might be having some trouble with <forms> in general and not just PHP so here is an overview:
<!-- the action is where you want to send the form data -->
<!-- assuming THIS code is the index.php file then we want to send the data to ourselves -->
<!-- the method is GET so it will be directly accessible from the URL later -->
<form action="index.php" method="GET">
<!-- add a hidden value for pagename -->
<input type="hidden" name="action" value="pagename">
<!-- the name called "thing" will be appended to the URL and it's value as well -->
<input type="text" name="thing" value="<?php echo (isset($_GET['thing']) ? $_GET['thing'] : ''); ?>">
<br>
<!-- click this button to submit the form to itself -->
<!-- once this has been submitted then you can retrieve the URL value with $_GET as you can see above -->
<input type="submit" value="submit" />
</form>
You can simply use the PHP-variable $_GET['thing'] to get the value.
The action attribute of the form element is the target script which will be called on submit. If blank it will be the current script which is showing the form. You also can only give url parameters beginning with ?.
<form role="form" action="?action=pagename" method="get">
<input type="text" name="thing">
</form>
Exerpt from php.net: http://www.php.net/manual/de/tutorial.forms.php
One of the most powerful features of PHP is the way it handles HTML
forms. The basic concept that is important to understand is that any
form element will automatically be available to your PHP scripts.
Please read the manual section on Variables from external sources for
more information and examples on using forms with PHP. Here is an
example HTML form:
Example #1 A simple HTML form
<form action="action.php" method="post">
<p>Your name: <input type="text" name="name" /></p>
<p>Your age: <input type="text" name="age" /></p>
<p><input type="submit" /></p>
</form>
There is nothing special about this form. It is a straight HTML form
with no special tags of any kind. When the user fills in this form and
hits the submit button, the action.php page is called. In this file
you would write something like this:
Example #2 Printing data from our form
Hi <?php echo htmlspecialchars($_POST['name']); ?>.
You are <?php echo (int)$_POST['age']; ?> years old.
A sample output of this script may be:
Hi Joe. You are 22 years old.
Basic script I made to get the variables from the URL:
<?php
if (isset($_GET["action"]) && isset($_GET["thing"])) {
$action = $_GET["action"];
$thing = $_GET["thing"];
echo $action .PHP_EOL . $thing;
}
?>
This will output the following for the URL /index.php?action=pagename&thing=something
pagename
something
Though you should probably learn how to use forms properly first.
How do I link the PHP to the HTML form? I understand how to do the PHP and how to do the HTML, but how do I link the php to the html or is that automatic,
how does the HTML form know about the PHP?
In your form set the action attribute to the path of your php script eg:
<form action="/path/to/php/script.php" method="post">
...
</form>
You set your action="" in your form to point to your PHP script. When the user clicks the submit button in your form, the PHP script will be called and the formdata will be handed over to the PHP script.
The method you choose when making your form is how PHP will gather the values passed in.
As such:
<form action="handler.php" method="post">
<!-- OR -->
<form action="handler.php" method="get">
The action tells where the form values will be sent to and the method tells how the values of the items in the form will be passed back to the server. The post method will send the values back so they may be retrieved by the $_POST array (both post and get can be retrieved by the $_REQUEST array). For example:
<input type="text" name="myInput">
Will post back to the server and can be retrieved by
$var = $_POST['myInput'];
It's always best to test if there is actually an input, and the following can be used
if(isset($_POST['myInput'])) { /*do something if set*/}
else{ /*do something if not set*/}
If the form was submitted by the get method, the values of the form is passed back in the URL, like such:
http://www.domain.tld/handler.php?myInput=someValue
The value is then retrieved by using the $_GET array:
$var = $_GET['myInput'];
Once again, you should test that it exists.
For good examples and explanations, please read a PHP book or search for PHP and HTML forms. This is the very basics of PHP.
Try this in a php file
<form action="" method="post">
<input type="text" value="html form data" name="name" />
<input type="submit" name="submit" />
</form>
<?php
if(isset($_POST['submit']))
echo 'I am php. I know this value is from html - '. $_POST['name'];
?>
If you are talking about refilling your form with the php values: inside your input fields, just add the request variable.
<input type="text" name="input1" value="<?=$_REQUEST['var_name']?>" />
If you are talking about sending date to php, just point to a file using the form action.
<form action="file.php" method="post">
</form>
Then you process all the data in that php file.
How do I make a self-posting/self-submitting form, i.e. a form that submits the results to itself, instead of submitting to another form?
The proper way would be to use $_SERVER["PHP_SELF"] (in conjunction with htmlspecialchars to avoid possible exploits). You can also just skip the action= part empty, which is not W3C valid, but currently works in most (all?) browsers - the default is to submit to self if it's empty.
Here is an example form that takes a name and email, and then displays the values you have entered upon submit:
<?php if (!empty($_POST)): ?>
Welcome, <?php echo htmlspecialchars($_POST["name"]); ?>!<br>
Your email is <?php echo htmlspecialchars($_POST["email"]); ?>.<br>
<?php else: ?>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post">
Name: <input type="text" name="name"><br>
Email: <input type="text" name="email"><br>
<input type="submit">
</form>
<?php endif; ?>
I guess , you means $_SERVER['PHP_SELF']. And if so , you really shouldn't use it without sanitizing it first. This leaves you open to XSS attacks.
The if(isset($_POST['submit'])) condition should be above all the HTML output, and should contain a header() function with a redirect to current page again (only now , with some nice notice that "emails has been sent" .. or something ). For that you will have to use $_SESSION or $_COOKIE.
And please. Stop using $_REQUEST. It too poses a security threat.
That will only work if register_globals is on, and it should never be on (unless of course you are defining that variable somewhere else).
Try setting the form's action attribute to ?...
<form method="post" action="?">
...
</form>
You can also set it to be blank (""), but older WebKit versions had a bug.
Try this
<form method="post" id="reg" name="reg" action="<?php echo htmlspecialchars($_SERVER['PHP_SELF']);?>"
Works well :)
Your submit button doesn't have a name. Add name="submit" to your submit button.
If you view source on the form in the browser, you'll see how it submits to self - the form's action attribute will contain the name of the current script - therefore when the form submits, it submits to itself. Edit for vanity sake!
change
<input type="submit" value="Submit" />
to
<input type="submit" value="Submit" name='submit'/>
change
<form method="post" action="<?php echo $PHP_SELF;?>">
to
<form method="post" action="">
It will perform the code in if only when it is submitted.
It will always show the form (html code).
what exactly is your question?
I was wondering if my code below is even correct, I've been having numerous errors with this, but am not sure if the problem really exists here. The code is below:
The user will click 'Exit Group'.
<p class="logout"><a id="exit" name="logout" href="#">Exit Group</a></p>
The code that should be execute when 'Exit Group' is clicked is below:
if(isset($_GET['logout'])){
//CODE TO BE EXECUTED
}
However, the code I am trying to execute when the user clicks 'Exit Group' is not even being executed. There is nothing wrong with the code within the braces, as numerous people have checked it. But I was wondering if my problem may lie in the code above? Thank you.
If you click the link, nothing happens because the URL only contains the fragment identifier #. Not even a GET request will be issued.
You use this kind of link normally to jump to an element inside the page (e.g. Top to jump to an element with ID top). This is completely handled in the browser.
And if you only put the fragment identifier there, just nothing will happen. This is very often used if the link should execute some JavaScript and should actually not link to something else.
You are testing the $_POST array at the server side. But this array only contains elements, if you initiate a POST request by a form. That means you need to create a form with a submit button, e.g.:
<form action="" method="POST">
<input type="submit" name="logout" value="Exit Group" />
</form>
Here comes the name attribute into play, which will be the key in the $_POST array. But assigning this on a normal link will have no effect.
You could do it also with the link, but with a GET request this way:
<a id="exit" href="?logout=1">Exit Group</a>
<!-- ^-- parameter must be part of the URL, name has no effect -->
and
if(isset($_GET['logout'])){
//CODE TO BE EXECUTED
}
Note that you have to pass a parameter logout it here.
It seems you have mixed up GET and POST requests. If you have a form, the name s of the form elements will be transmitted as parameters to the server. That means given this form:
<form method="POST">
<input type="text" name="foo" value="" />
<input type="text" name="bar" value="" />
<input type="submit" name="send" value="Send" />
</form>
if the user clicks on the submit button, the $_POST array at the server side will have the keys:
$_POST['foo']
$_POST['bar']
$_POST['send']
This does not work with links though. A click on a link will create a normal GET request, and here, the parameters must be part of the URL, appended after a question mark ? and separated by an ampersand &:
Link
will result in
$_GET['foo']
$_GET['bar']
$_GET['andMore']
You probably should read about the HTTP protocol.
a isnt a form control. it needs to be an input or select if it's within a form.
For manual linking, do href="/page?logout"
You're using a regular hyperlink, no form will get posted. you need a submit button of some kind in a form with method="post" to do that. regular links just result in GET requests and nothing will ever be posted that way.
edit: added simple example:
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01//EN">
<html>
<head>
<title>Form test</title>
</head>
<body>
<?if ($_SERVER['REQUEST_METHOD'] == 'POST'):?>
<pre><? print_r($_POST)?></pre>
<?endif;?>
<? // $_SERVER['REQUEST_URI'] holds the current URL, so we know that ?>
<? // we'll end up back in this file when the form is submitted. ?>
<form method="post" action="<?= $_SERVER['REQUEST_URI']; ?>">
<input type="text" name="textbox"
value="<?= isset($_POST['textbox'])?$_POST['textbox']:'Type something' ?>" />
<input type="submit" name="submitbutton" value="Submit" />
</form>
</body>
</html>
$_POST will only be filled if you use a form with method=post.
Yes. A POST and a GET are two different things ;)
if(isset($_GET['logout']))
This <a id="exit" name="logout" href="#"> should be <a id="exit" href="?logoff=true#">.
Then logoff will be in the $_GET array.