php multiple image upload and display each image - php

Question

i'm struggle with some multiple image upload script.
what i implement to do is , upload multiple image then save each image saved path to variable
so i use later for display .
but when i run script i only can save first upload image path value.
<form action="" method="post" enctype="multipart/form-data">
<p>
<input type="file" name="pictures[]" /><br>
<input type="file" name="pictures[]" /><br>
<input type="file" name="pictures[]" /><br>
<input type="file" name="pictures[]" /><br>
<input type="submit" value="Send" />
</p>
</form>
<?php
foreach ($_FILES["pictures"]["error"] as $key => $error) {
if ($error == UPLOAD_ERR_OK) {
$tmp_name = $_FILES["pictures"]["tmp_name"][$key];
$name = $_FILES["pictures"]["name"][$key];
$ext = substr(strrchr($name, "."), 1);
$randName = md5(rand() * time());
$pathimg = "images/$randName.$ext";
move_uploaded_file($tmp_name, $pathimg );
echo '<img src="'.$pathimg.'"; >' ;
}
}
?>
this is upload path ''
for example if i upload 3 images then i want to save this 3 image uploaded path to variable each. so each variable will be $A, $B, $C
or if i upload 4 images i also want to this 4 image path to variable each then use for later
please enlighten me! thanks

Answer 1

Why do you expect errors while uploading.
Change
foreach ($_FILES["pictures"]["error"] as $key => $error) {
to
foreach ($_FILES["pictures"] as $key => $tempFile) {
Also, after successful upload, append the images into an array.
$arr = array();
foreach ($_FILES["pictures"] as $key => $tempFile) {
// YOUR CODE
$arr[] = '<img src="'.$pathimg.'"; >' ;
}
And print it in a loop.
if (! empty($arr)) {
foreach ($arr as $img) {
echo '<img src="'.$img.'"/>';
}
}