I have a file with so many href attributes. I want to modify the path, just want to add absolute path with the existing.
e.g href="parentall_files/filelist.xml" , just needs to be changed to href="dir/parentall/parentall_files/filelist.xml" throughout the file.
I have written the following:
$contents = preg_replace('/<a href="(.*?)"/i', '<a href="dir\/parentall\/$"',$contents);
But alas! it is not changing the path.
Please help.
Why you don't just change it with str_replace()
$contents = str_replace('href="parentall_files/','href="dir/parentall/parentall_files/', $contents);
Try
preg_replace('/<a href="(.*?)"/', '<a href="dir\/parentall\/"',$contents)
You need to add the {1} after $ sign
$string = 'asdsadsad';
$new = preg_replace('/<a href="(.*?)"/i', '<a href="dir/parentall/${1}', $string);
Output is:
string '<a href="dir/parentall/parentall_files/filelist.xml>asdsadsad</a>' (length=65)
you can use str_replace.
$contents= str_replace('href="','href="dir/parentall/',$contents);
Related
I am working with an editor that works purely with internal relative links for files which is great for 99% of what I use it for.
However, I am also using it to insert links to files within an email body and relative links don't cut the mustard.
Instead of modifying the editor, I would like to search the string from the editor and replace the relative links with external links as shown below
Replace
files/something.pdf
With
https://www.someurl.com/files/something.pdf
I have come up with the following but I am wondering if there is a better / more efficient way to do it with PHP
<?php
$string = 'A link, some other text, A different link';
preg_match_all('/<a[^>]+href=([\'"])(?<href>.+?)\1[^>]*>/i', $string, $result);
if (!empty($result)) {
// Found a link.
$baseUrl = 'https://www.someurl.com';
$newUrls = array();
$newString = '';
foreach($result['href'] as $url) {
$newUrls[] = $baseUrl . '/' . $url;
}
$newString = str_replace($result['href'], $newUrls, $string);
echo $newString;
}
?>
Many thanks
Lee
You can simply use preg_replace to replace all the occurrences of files starting URLs inside double quotes:
$string = 'A link, some other text, A different link';
$string = preg_replace('/"(files.*?)"/', '"https://www.someurl.com/$1"', $string);
The result would be:
A link, some other text, A different link
You really should use DOMdocument for such job, but if you want to use a regex, this one does the job:
$string = '<a some_attribute href="files/something.pdf" class="abc">A link</a>, some other text, <a class="def" href="files/somethingelse.pdf" attr="xyz">A different link</a>';
$baseUrl = 'https://www.someurl.com';
$newString = preg_replace('/(<a[^>]+href=([\'"]))(.+?)\2/i', "$1$baseUrl/$3$2", $string);
echo $newString,"\n";
Output:
<a some_attribute href="https://www.someurl.comfiles/something.pdf" class="abc">A link</a>, some other text, <a class="def" href="https://www.someurl.com/files/somethingelse.pdf" attr="xyz">A different link</a>
I have a string that looks like this
$t="<b>vist</b>thank you for the follow.";
I am trying to remove the tag b and put an "#" instead of this tag.
I tried this
str_replace("<b></b>","#",$t);
but it doesn't replace the closing tag.
I don't know why it is not working may be there is something omitted in the code.
Try with
$search = array('<b>','</b>');
$replace = '#';
echo str_replace($search, $replace, $t);
To replace multiple words using str_replace() function,
You can Try this
$t="<b>vist</b> thank you for the follow";
$pattern=array();
$pattern[0]="<b>";
$pattern[1]="</b>";
$replacement=array();
$replacement[0]="#";
$replacement[1]="";
echo str_replace($pattern,$replacement,$t);
View the Demo
Try with -
$t="<b>vist</b>";
echo str_replace(array("<b>", "</b>"),"#",$t);
I have some HTML code like this:
<a href="http://mysite.com/documentos/Servicios/SUCRE/sucDoc19.pdf&sa=U&ei=sf0JUrmjIc3Nswb154CgDQ&ved=0CCkQFjAA&usg=AFQjCNGfXg_9x83U3pYr6JfkJcWuXv8X0Q">
I need to clean my code to get something like this
<a href="http://mysite.com/documentos/Servicios/SUCRE/sucDoc19.pdf">
using preg_replace.
My code is the following:
$serp = preg_replace('&sa=(.*)" ', '" ', $serp);
and it doesn't work.
BTW i need to restrict search with preg_replace until the FIRST entrance, i.e. i need to replace all html from &sa= to the FIRST ", but now it search from &sa= to the LAST "...
You're missing the regex delimiters.
$serp = preg_replace('/&sa=(.*)" /', '" ', $serp);
will give you this.
You missed the delimiter.
So your code looks like:
$serp = preg_replace('/&sa=(.*)" /', '" ', $serp);
okay, if you want to delete everything till the first quote then you can try the following instead of regex:
$temp = substr($serp,strpos($serp,'&sa='),strpos($serp,'"',strpos($serp,'&sa=')));
$serp = str_replace($temp,"",$serp);
Just another regex to do it :)
$text = '<a href="http://mysite.com/documentos/Servicios/SUCRE/sucDoc19.pdf&sa=U&ei=sf0JUrmjIc3Nswb154CgDQ&ved=0CCkQFjAA&usg=AFQjCNGfXg_9x83U3pYr6JfkJcWuXv8X0Q" target="_blank">';
$text = preg_replace('/(&sa=[^"]*)/', '', $text);
echo $text;
// Output:
<a href="http://mysite.com/documentos/Servicios/SUCRE/sucDoc19.pdf" target="_blank">
You can try it HERE (thks to hjpotter92 for this tool)
I have some text contain html tags, I would like to replace all links with other one, but I want to replace just local links, not they start with http://
example :
test link
==> test link
Video
==> Video
I try this preg_replace but not working :
$exclude = '<a href=\"http://.*?';
$pattern = '<a href=\".*?';
$content=preg_replace("~(($exclude)?($pattern))~i",'<a href="/action.php?url=$4',$content);
Thanks!
What about something like this:
$content = preg_replace('#<a href="([^:]*)">#i', '<a href="/action.php?url=$1">', $content);
I have a variable $link_item, it's used with echo and gives the strings like
<span class="name">Google</span>http://google.com
How to remove "<span class="name">Google</span>" from string?
It should give just "http://google.com".
Heard it can be done with regex(), please help.
Without regex:
echo substr($link_item, stripos($link_item, 'http:'))
But this only works if the first part (i.e. <span class="name">Google</span>) never contains http:. If you can assure this: here you go :)
Reference: substr, stripos
Update:
As #Gordon points out in his comment, my code is doing the same as strstr() already does. I just put it here in case one does not read the comments:
echo strstr($link_item, 'http://');
$string = '<span class="name">Google</span>http://google.com';
$pieces = explode("</span>",$string);
//In case there is more than one span before the URL
echo $pieces[count($pieces) -1];
Solved:
$contents = '<span class="name">Google</span>http://google.com';
$new_text = preg_replace('/<span[^>]*>([\s\S]*?)<\/span[^>]*>/', '', $contents);
echo $new_text;
// outputs -> http://google.com
Don't use a regex. Use a HTML parser to extract only the text you want from it.
Made myself
$link_item_url = preg_replace('#<span[^>]*?>.*?</span>#si', '', $link_item);
This will remove any <span + something + </span> from variable $link_item.
Thanks for all.