find / select specified ID in array php - php

Question

i have array with database, and have to select only this items what have "tid" = 1
array(3) {
[1]=>
array(4) {
["tid"]=> "1"
["title"]=> "Google"
["url"]=> "http://google.com/"
["description"]=> "A very efficient search engine."
}
[2]=>
array(4) {
["tid"]=> "2"
["title"]=> "Facebook"
["url"]=> "http://facebook.com/"
["description"]=> "Trade securities, currently supports nearly 1000 stocks and ETFs"
}
[3]=>
array(4) {
["tid"]=> "1"
["title"]=> "Yandex"
["url"]=> "http://yandex.ru/"
["description"]=> "Another efficient search engine popular in Russia"
}
}
how can i select only this items from array what have "tid" = 1?

Answer 1

<?php
$final_arr = array();
foreach($tid_arrs as $tid_arr){
if($tid_arr['tid'] == 1){
$final_arr[] = $tid_arr;
}
}
print_r($final_arr);
?>

Answer 2

$filteredArray = array();
for($i = 0, $end = count($array);$i < $end;i++)
{
if($array[$i]["tid"] === "1")
{
$filderedArray[] = $array[$i];
}
}
That way $filteredArray will contain solely the items with tid 1;

Answer 3

Try array_filter function: http://php.net/manual/en/function.array-filter.php this should help.
print_r(array_filter($array, "filter_function"));
function filter_function($element){
return (int)$element['tid'] === 1;
}

Answer 4

let's say you starting array is $arr.
$result = array();
foreach ($arr as $arrItem) {
if ((array_key_exists('tid', $arrItem)) && ($arrItem['tid'] == "1")){
$result[] = $arrItem;
}
}
$result should be what you are excepted.