So I have a div that I want to convert to a success alert after a successful insertion into the database. The AJAX success function of course runs only on successful POST to the PHP page, so how would I go about getting feedback from my insert query? Nothing shows up in my network tab that relates to the query.
$.ajax({
type: "POST",
url: "follow.php",
data: {usrid: <?php echo "$sess_user_id1"; ?>, usrname: "<?php echo $sess_username; ?>", gender: <?php echo "$sess_gender"; ?>, markid: <?php echo "$markerid"; ?>, type: "<?php echo $type; ?>", usrhomelat: <?php echo "$sess_homelat"; ?>, usrhomelng: <?php echo "$sess_homelng"; ?>, blurb: ($("#textarea").val())},
success: function (data, msg) {
alert("Congratulations ");
$("#thanks").html(msg);
},
error: function () {
alert("At this time, you could not be added");
}
});
Then on my follow.php page, I have my query, which, I know shouldn't be in mySQL(I will convert before taking the site live):
$query = "INSERT INTO markerfollowing (userID, username, gender, markerID, type, usrhomelat, usrhomelng, blurb)
VALUES ('$user_id_follow', '$username2', '$gender', '$marker_id', '$type', '$usrhomelat', '$usrhomelng', '$blurb');";
$result = mysql_query($query);
if (!$result) {
die('Invalid query: ' . mysql_error());
}
As you can probably tell, I am an amateur, so any assistance is greatly appreciated. I don't even know what search terms to use to address this issue. Thanks!
Well, as far as I can see your ajax call looks ok. Your problem lies in the data you are sending back and how you handle it.
If you do it in your way you just get a simple string. You could go for a call expecting json data like this.
Php part returns an array in json form.
$return = array();
if (!$result) {
$return['success'] = 0;
$return['message'] = 'Invalid query '.mysql_error();
} else {
$return['success'] = 1;
$return['message'] = 'Successfully saved!';
}
echo json_encode($return);
The ajax call changes like this (we'll be expecting a json object so we tell the ajax call what to expect from the server in dataType):
dataType: "json",
success: function (data) {
if (data['success'] == 0) {
alert("Congratulations");
$("#thanks").html(data['message']);
} else {
alert("At this time, you could not be added");
// You could also use the data['message'] that got sent back here.
}
}
The error function should not be used for transporting data from the follow.php script because it gets called if there was a more basic transfer type of error.
I hope that helps you with your problem.
Related
I'm building a simple forum on which I have a user details page with two text fields, one for the user's biography and another for his interests.
When the user clicks on the save icon, a handler on the jquery is suposed to call an ajax call to update the database with the new value of the biography/interests but the ajax call isn't being called at all and I can't figure it out since I don't find any problems with the code and would apreciate if someone could take a look at it.
this is the textarea:
<textarea rows="4" cols="50" id="biography" readonly><?php if($info['bio'] == "") echo "Não existe informação para mostrar";
else echo $info['bio']; ?></textarea>
Here is the icon the user clicks on:
<li style="display:inline;" class="infoOps-li"><img class="info-icons" id="save1" src="assets/icons/save.png" alt=""></li>
this is the jequery with the ajax call:
$("#save1").click(function(){
var bio = $("#biography").val();
alert(bio); //this fires up
$.ajax({
url:"assets/phpScripts/userBioInterest.php", //the page containing php script
type: "post", //request type,
dataType: 'json',
data: {functionName: "bio", info:bio},
success:function(result){
alert(result.abc); //this doesn't fire
}
});
$("#biography").prop("readonly","true");
});
I know that the jquery handler is being called correctly because the first alert is executed. The alert of the ajax success function isn't, so I assume that the ajax call isn't being processed.
On the php file I have this:
function updateBio($bio)
{
$user = $_SESSION['userId'];
$bd = new database("localhost","root","","ips-connected");
$connection = $bd->getConnection();
if($bio == "")
{
echo json_encode(array("abc"=>'empty'));
exit();
}
if($stmt = mysqli_prepare($connection,"UPDATE users SET biografia = ? WHERE user_id = ?"))
{
mysqli_stmt_bind_param($stmt,'si',$bio,$user);
mysqli_stmt_execute($stmt);
mysqli_stmt_close($stmt);
echo json_encode(array("abc"=>'successfuly updated'));
}
$bd->closeConnection();
}
if(isset($_POST['functionName']))
{
$function = $_POST['functionName'];
echo $function;
if(isset($_POST['info']))
$info = $_POST['info'];
if($function == "bio")
{
updateBio($info);
}
else if($function == "interest")
{
updateInterests($info);
}
}
Can anyone shed some light on why isn't the ajax call being called?
Thank you
EDIT: changed "function" to "functionName" in json data object as suggested.
A possible problem is dued to a wrong parsing of the PHP output (for example due to a PHP error). You are reading the output as JSON, so if the output is not a JSON, success callback will not be triggered.
$("#save1").click(function(){
var bio = $("#biography").val();
alert(bio); //this fires up
$.ajax({
url:"assets/phpScripts/userBioInterest.php",
type: "post", //request type,
dataType: 'json',
data: {function: "bio", info:bio},
success:function(result){
alert(result.abc); //this doesn't fire
},
error: function(result){
alert("An error has occurred, check the console!");
console.log(result);
},
});
$("#biography").prop("readonly","true");
});
Try with this code, and check if an error is printed to the console.
You can use complete too, check here: http://api.jquery.com/jquery.ajax/
I really have never done this before and I am getting frustrated because I'm not sure how it fits together. I have a function that I want to call my php (one php file selects info from a database and the second inserts into the database)... I need to use ajax in the way my site is setup but I don't know how to pass data from and to the php files.
In first .js file:
q1LoadVar();
This is my ajax function in second .js file that I have so far (not working):
//ajax code has been edited here since original post:
function q1LoadVar() {
alert("called"); //works!
$.get( "q1LoadVar1.php", function( data ) {
console.log(data); //nothing happens!
// alert(data); //nothing happens!
}, "json" );
}
And here is the code I have in q1LoadVar1.php that I want to select data back from and be able to populate a text area in my html:
/*works when I type this file path directly into the url;
but the file is not communicating back to the ajax function on the
.js file that is calling it*/
<?php
$config = parse_ini_file('../config.ini');
$link = mysqli_connect('localhost',$config['username'],$config['password'],$config['dbname']);
if(mysqli_connect_errno()){
echo mysqli_connect_error();
}
echo '<script type="text/javascript">alert("working from php!");</script>';
$query = "SELECT * FROM Game1_RollarCoaster";
$result = mysqli_query($link, $query);
while ($row = mysqli_fetch_array($result)) {
$newRow[] = $row;
}
$json = json_encode($newRow);
echo $json; //works on php file directly!
/*while ($row = mysqli_fetch_array($result)) {
echo $row[Q1_AnswerChoosen];
}*/
mysqli_free_result($result);
mysqli_close($link);
?>
Can someone help me understand how to make this all work together? Thank you, Kristen
You can retrieve post data from ajax in php with
$_POST['action']
//in your case will return: test
To return data to ajax you need to use echo
If the success: callback function doesnt get called try to remove datatype: 'json'
I also think that you need to echo $newrow instead of $row.
If this still doesnt work you can catch the error with the error: callback function to see what is wrong.
Try to start with a simple request and work from there.
$(document).ready(function() {
$.ajax({
type: "POST",
url: "yourphp.php",
data: {simplestring: "hi"},
success: function(result){
alert(result);
}
});
});
and yourphp.php
<?php
$simplestring = $_POST['simplestring'];
echo $simplestring;
I am using ajax call to grab some data from my mysql database. This is my ajax call:
$.ajax({
type: "POST",
url: "fetch.php",
data: id,
success: function(msg) {
var record = JSON.parse(msg);
$("#name").val(record.name);
$("#description").val(record.description);
switch(record.category) {
case ("Residential"):
$("#category").val("residential");
break;
case ("Modernisation & Domestic Extensions"):
$("#category").val("modernisation");
break;
case ("Feasibility Layouts"):
$("#category").val("feasibility");
break;
case ("Master Planning"):
$("category").val("master");
break;
default:
$("category").val("");
};
switch(record.featured) {
case ("y"):
$("#featured").val("y");
break;
default:
$("featured").val("n");
};
}
})
and this is my php file:
<?php
$dbc = mysqli_connect('XX','XX','XX','XX');
$id = $_POST['id'];
if($dbc) {
$row = fetchDataFromRecordWithId($dbc,$id);
}
else {
echo 'Database error';
}
function fetchDataFromRecordWithId($dbc,$id) {
$q = "SELECT * FROM Projects WHERE id = ".$id;
$r = mysqli_query($dbc, $q);
$row = mysqli_fetch_array($r, MYSQLI_ASSOC);
mysqli_close($dbc);
return $row;
}
echo json_encode($row);
?>
Everything work flawless but soon when I try to add if statement in my php file to check if there is any POST data than my ajax call is not getting any response. I tried different methods :
<?php if(isset($_POST)) { .. my whole php code here .. } ?>
<?php if(!empty($_POST)) { ..my whole php code here .. } ?>
<?php if($_POST) { .. my whole php code here .. } ?>
<?php if($_POST['id']) { .. my whole php code here .. } ?>
but nothing work! Ajax call is not getting json data back when I will use any of these if statements listed above.
I could not check for POST data and leave it like it is but I want to do is in proper way.
It seems like if statement is not executed (but POST data must be there as I am able to fetch $_POST['id'] value when if statement not used).
I also tried to put echo json_encode($row) outside if statement but it didn't help either. Any ideas what is wrong?
$.ajax({
type: "POST",
url: "fetch.php",
data: id,
http://api.jquery.com/jQuery.ajax/:
data: [...] Object must be Key/Value pairs.
So make that line
data: { id : id },
instead, then it should work.
if ($_SERVER['REQUEST_METHOD'] != 'POST') {
die("Invalid request method: " . $_SERVER['REQUEST_METHOD']);
}
if (isset($_POST['id'])) {
... db code here ...
}
also note that your are WIDE open for SQL injection attacks.
you try follow testings on your code
check whether you have have the right request page for php .
see in google chromes right click inspect element then console tab any errors are showing
in your suceess:function(msg) add $("body").append(msg)
add function before success:function(result) {}
error:function(xhr,err){
alert("readyState: "+xhr.readyState+"\nstatus: "+xhr.status);
alert("responseText: "+xhr.responseText);
}
I've been trying to figure out what I have done wrong but when I use my JavaScript Console it shows me this error : Cannot read property 'success' of null.
JavaScript
<script>
$(document).ready(function() {
$("#submitBtn").click(function() {
loginToWebsite();
})
});
</script>
<script type="text/javascript">
function loginToWebsite(){
var username = $("username").serialize();
var password = $("password").serialize();
$.ajax({
type: 'POST', url: 'secure/check_login.php', dataType: "json", data: { username: username, password: password, },
datatype:"json",
success: function(result) {
if (result.success != true){
alert("ERROR");
}
else
{
alert("SUCCESS");
}
}
});
}
</script>
PHP
$session_id = rand();
loginCheck($username,$password);
function loginCheck($username,$password)
{
$password = encryptPassword($password);
if (getUser($username,$password) == 1)
{
refreshUID($session_id);
$data = array("success" => true);
echo json_encode($data);
}
else
{
$data = array("success" => false);
echo json_encode($data);
}
}
function refreshUID($session_id)
{
#Update User Session To Database
session_start($session_id);
}
function encryptPassword($password)
{
$password = $encyPass = md5($password);
return $password;
}
function getUser($username,$password)
{
$sql="SELECT * FROM webManager WHERE username='".$username."' and password='".$password."'";
$result= mysql_query($sql) or die(mysql_error());
$count=mysql_num_rows($result) or die(mysql_error());
if ($count = 1)
{
return 1;
}
else
{
return 0;;
}
}
?>
I'm attempting to create a login form which will provide the user with information telling him if his username and password are correct or not.
There are several critical syntax problems in your code causing invalid data to be sent to server. This means your php may not be responding with JSON if the empty fields cause problems in your php functions.
No data returned would mean result.success doesn't exist...which is likely the error you see.
First the selectors: $("username") & $("password") are invalid so your data params will be undefined. Assuming these are element ID's you are missing # prefix. EDIT: turns out these are not the ID's but selectors are invalid regardless
You don't want to use serialize() if you are creating a data object to have jQuery parse into formData. Use one or the other.
to make it simple try using var username = $("#inputUsername").val(). You can fix ID for password field accordingly
dataType is in your options object twice, one with a typo. Remove datatype:"json", which is not camelCase
Learn how to inspect an AJAX request in your browser console. You would have realized that the data params had no values in very short time. At that point a little debugging in console would have lead you to some immediate points to troubleshoot.
Also inspecting request you would likely see no json was returned
EDIT: Also seems you will need to do some validation in your php as input data is obviously causing a failure to return any response data
Try to add this in back-end process:
header("Cache-Control: no-cache, must-revalidate");
header('Content-type: application/json');
header('Content-type: text/json');
hope this help !
i testet on your page. You have other problems. Your postvaribales in your ajax call are missing, because your selectors are wrong!
You are trying to select the input's name attribute via ID selector. The ID of your input['name'] is "inputUsername"
So you have to select it this way
$('#inputUsername').val();
// or
$('input[name="username"]').val();
I tried it again. You PHP script is responsing nothing. Just a 200.
$.ajax({
type: 'POST',
url: 'secure/check_login.php',
dataType: "json",
data: 'username='+$("#inputUsername").val()+'&password='+$("#inputPassword").val(),
success: function(result) {
if (result.success != true){
alert("ERROR");
} else {
alert("HEHEHE");
}
}
});
Try to add following code on the top of your PHP script.
header("Content-type: appliation/json");
echo '{"success":true}';
exit;
You need to convert the string returned by the PHP script, (see this question) for this you need to use the $.parseJSON() (see more in the jQuery API).
I have created a registration system that uses AJAX to process the form so that I can return false. The relevant js is the top block of code. I pass this data to join.php, which sends it to the database. I run a check in join.php to make sure that nobody with a duplicate email has already signed up. As you can see, if the email already exists, I want to insert a message using javascript. Instead of reading the script tags, it simply pastes them into my alert in plaintext...so my alert has the datastring and then actually says the code <script>...</script>. How can I get this js to process instead?
Javascript:
$(".submit").click(function() {
var dataString = {
school : $("#school").val(),
studentEmail : $("#studentEmail").val(),
studentPassword : $("#studentPassword").val(),
parentEmail : $("#parentEmail").val(),
parentPassword : $("#parentPassword").val(),
studentFirstName : $("#studentFirstName").val(),
studentLastName : $("#studentLastName").val(),
studentPhone : $("#studentPhone").val(),
parentFirstName : $("#parentFirstName").val(),
parentLastName : $("#parentLastName").val(),
parentPhone : $("#parentPhone").val()
};
$.ajax({
type: "POST",
url: "join.php",
data: dataString,
success: function(data) {
alert ("data sent: "+ data);
}
});
return false;
}
});
join.php
if($_POST) {
$school = mysql_real_escape_string($_POST['school']);
$studentEmail = mysql_real_escape_string($_POST['studentEmail']);
$parentEmail = mysql_real_escape_string($_POST['parentEmail']);
$studentFirstName = mysql_real_escape_string($_POST['studentFirstName']);
$studentLastName = mysql_real_escape_string($_POST['studentLastName']);
$studentPhone = mysql_real_escape_string($_POST['studentPhone']);
$parentFirstName = mysql_real_escape_string($_POST['parentFirstName']);
$parentLastName = mysql_real_escape_string($_POST['parentLastName']);
$parentPhone = mysql_real_escape_string($_POST['parentPhone']);
$check = mysql_query("SELECT studentEmail FROM clients WHERE studentEmail = '{$studentEmail}';");
$num = mysql_num_rows($check);
if (($num) == 0) {
$sql = "INSERT INTO clients ".
"(`studentEmail`, `studentPassword`, `parentEmail`, `parentPassword`, ".
"`studentFirstName`, `studentLastName`, `studentPhone`, `parentFirstName`, ".
"`parentLastName`, `parentPhone`, `school`) ".
" VALUES ('$studentEmail', '$studentPassword', '$parentEmail', ".
"'$parentPassword', '$studentFirstName', '$studentLastName', ".
"'$studentPhone', '$parentFirstName', '$parentLastName', '$parentPhone', '$school')";
$result = mysql_query($sql);
if ($result) {
echo "Database query successful!";
}
else {
die("Database query failed: " . mysql_error());
}
include "emails/signUp.php";
}
else {
echo 'FAIL
<script>
$(".formErrorMessage").html("Email already exists");
</script>';
}
}
The alert shows your script block because you've got this in your success handler:
alert ("data sent: "+ data);
Data is going to be whatever text you output in your PHP. If you want to have variable behavior based on whether your request was successful or not, I'd recommend that your PHP returns JSON containing a success flag and the message. Your JavaScript callback would then look like this:
function(data) {
if (data.success) {
alert ("data sent: "+ data.message);
} else {
$(".formErrorMessage").text(data.message);
}
}
Your PHP should then change your content-type to JSON:
header('Content-Type: application/json');
... and your echos would change to something like this:
echo '{"success": false, "message": "Email already exists."}';
Your server call shouldn't be returning raw HTML. Should return JSON that contains all the status information the server needs to handle things. i.e. in the usual case:
{'success': true}
or
{'success': false, 'emailAlreadyExists': true, 'msg': 'Email Already Exists'}
of
{'success': false, 'msg': 'Database query failed: blahblahMySqlError'}
Then your client JS should handle it...
$.ajax({
type: "POST",
url: "join.php",
data: dataString,
success: function(data) {
if(data.success) {
alert ("success!");
}
else{
alert("error: " + data.msg);
if(data.emailAlreadyExists){
$(".formErrorMessage").html("Email already exists");
}
}
}
});
from php, you have give formatted status responses
on success:
echo '{"status":"success", message:"Database query successful!"}';
if account already exists:
echo '{"status":"failed", message:"Email already exists"}';
So you will be able to identify this in JavaScript callback function
$.ajax({
type: "POST",
url: "join.php",
data: dataString,
success: function(data) {
if(status.error == "failed"){
$(".formErrorMessage").html(data.message);
}
}
});
This is the best way to do it. Or if you just want to execute a string received from php, you can use eval
success: function(data) {
eval(data);
}
In that case there is no need of script tags in response, only the Javascript statement that has to be executed.