Working with Yii framework 2.0 I tried to use the pagination feature and linkpager widget, following Yii documentation.
Below is my controller.
public function actionIndex()
{
$query = Country::find();
$pagination = new Pagination([
'defaultPageSize' => 5,
'totalCount' => $query->count(),
]);
$countries = $query->orderBy('name')
->offset($pagination->offset)
->limit($pagination->limit)
->all();
return $this->render('index', [
'countries' => $countries,
'pagination' => $pagination,
]);
}
In my index view, I use the following code.
<?= LinkPager::widget(['pagination' => $pagination]) ?>
Now I want to add one more pagination feature and LinkPager widget for another model City. In the actionIndex() method I follow the existing code, just create an object of City and an object of new Pagination and return it to the view. In the view I include LinkPager widget once again with another pagination variable $paginationCity. When I click on a pagination number I saw the query string page=xx in the URL. I notice that it is being used for both models Country and City. How can I use multiple pagination on one same page?
You can do it by changing pageParam property of Pagination class:
$cityPagination = new Pagination([
...
'pageParam' => 'city-page',
]);
Related
I would like to add pagination to my website, but I am very new to Yii and would like some advise.
This is the page that I am looking to add pagination: https://gocar2.com/newsproducts/center
As you can see I have numerous cells for each auto news, and now I am allowing only 18 news to show on the page. I would like to add pagination here so that I can browse more news.
And this is what I tried:
newscontroller.php
<?php
use yii\data\Pagination;
class NewsproductsController extends Controller
{
public function actionCentermore()
{
$criteria = new CDbCriteria;
$criteria->addCondition("approvedStatus = '1'");
$criteria->order = 'createdDate DESC';
$product = Newsproducts::model()->findAll($criteria);
$Pagination = new Pagination([
'defaultPageSize' => 15,
'totalCount' => $product->count(),
]);
$products = $product->offset($Pagination->offset)
->limit($Pagination->limit)
->all();
$this->renderPartial('centermore',compact('products', 'Pagination'));
}
}
newsview.php will render all the top menu and banners and it will render centermore.php
$this->renderPartial('centermore', compact('products', 'Pagination'));
centermore.php (view of the news cells), I then added the LinkPager widget at the bottom.
LinkPager::widget(['Pagination' => $Pagination])
And of course, there is an error, Class LinkPager cannot be found.
Can anyone give me some advise how to solve this/implement paging?
In Yii2 pagination is usually handled via DataProvider, have a look at the:
Yii2 Guide: Data Providers, especially ActiveDataProvider:
use yii\data\ActiveDataProvider;
$query = Post::find()->where(['status' => 1]);
$provider = new ActiveDataProvider([
'query' => $query,
'pagination' => [
'pageSize' => 10,
],
'sort' => [
'defaultOrder' => [
'created_at' => SORT_DESC,
'title' => SORT_ASC,
]
],
]);
// returns an array of Post objects
$posts = $provider->getModels();
I'm using CakePHP 3 and I want to paginate my users.
However when I click on the second page, the URL looks like /users?page=2 and I expect : /users/2.
I created this route in routes.php :
$routes->connect('/users/:page', ['controller' => 'users', 'action' => 'index'], ['page' => '[0-9]+']);
And in Users/index.ctp before the "prev" button I put :
<?php
$this->Paginator->options([
'url' => [
'controller' => 'users',
'action' => 'index'
]
]);
?>
Now when I click on page 2 for example, /users/2 opens and I got this error message (RuntimeException) :
Unable to locate an object compatible with paginate.
Did I miss something or where I made a mistake ?
Thanks for your help.
The PaginatorHelper has built in the url format, i.e. to use ?page=n. It will also do sorting such as users?page=2&sort=user_id&direction=asc. Your format of /users/{page} does not handle sorting.
If your REALLY want to stick to /users/{page} you'll have to override PaginatorHelper.
try this
in side your controller with paginator component . It works for me
$this->Paginator->paginate('Users')
for custom urlenter code here
u need to implement index action as
public function index($page = null){
$this->Paginator->settings = ['limit' => 15, 'page' => $page];
$this->set('users', $this->Paginator->paginate('Users'));
}
I am developing this yii application and in the index i am displaying a "preview" of these items and currently it is display 8 items then it will pageinate itself. I would like make it page every 4 items and i have searched online and found that i could use the CPagination. I have followed the example in the documentation http://www.yiiframework.com/doc/api/1.1/CPagination and it is working but i don't know how to display the model i have the following code in the index.
foreach($models as $model):
endforeach;
$this->widget('CLinkPager', array(
'pages' => $pages,
));
Also the data that i want to display is Title, Content, Image and id and can i use the _view since i have everying set from there regarding css.
Also by defult the yii application display the index with a CListView is there a way where i can set the item limit there instead of using CPagination
If you want to just display 4 items on the index page, edit the index action like this:
public function actionIndex()
{
$dataProvider=new CActiveDataProvider('{Model}',
array(
'criteria' => array(
'select' => 'title_field,content_field,image_field',
'limit' => {Limit},
)
));
$this->render('index',array(
'dataProvider'=>$dataProvider,
));
}
This code will return {Limit} models from the database, if you want to sort them by any field you will need to add 'order' to the criteria array lik this:
'criteria' => array(
'select' => 'title_field,content_field,image_field',
'order' => 'download_id DESC',
'limit' => {Limit},
)
In your view, use foreach and render partial to render the _view.
foreach($models as $model):
$this->renderPartial('//{Model}/_view', $model);
endforeach;
Hope that helps.
In my project I want to change the link url because it does not look good.
The link is as example below:
http://www.example.com/product?Product[pagesize]=24&page=2
http://www.example.com/product?Product[brand_id][]=3
so I want to the url like this
http://www.example.com/product?pagesize=24&page=2
http://www.example.com/product?brd[]=3
I use Yii framewrok, so is it possible to change it?
Thank you!
I do not know why u use difficult url instead of dataprovider of yii for paging. here is code:
controller:
$pageSize=5;
$news = News::model()->findAll(); //returns AR objects
$count = count($news);
$dataProvider= new CArrayDataProvider($news, array(
'sort'=>array('attributes'=>array('title')), //you can sort here if objects not sorted
'pagination'=>array('pageSize'=>$pageSize),
));
$models = $dataProvider->getData();
$this->render('index', array(
'models' => $models,
'dataProvider' => $dataProvider,
'itemCount' => $count,
));
on view:
<?php
$this->widget('CLinkPager', array(
'pages'=>$dataProvider->pagination,
));
?>
I have a search form, which returns a bunch of images. Because their number can be high, I would prefer having the results displayed using pagination. However, I cannot seem to get it to work properly. I have moved everything to the view to keep things as simple as possible.
Here is my code snippet for the search and pagination:
$searchData = $model->search(); // this is the result of the search
$pages = new CPagination($searchData->itemCount);
$searchData->setPagination($pages);
$pages->applyLimit($searchData->criteria);
$pages->pageSize = 2;
Then, I display the results using a "foreach" statement:
foreach($searchData->getData() as $data)
{
// results displayed here
}
Finally, I have the CLinkPager widget:
$this->widget('CLinkPager', array(
'pages' => $pages,
'header' => 'Отиди на страница: ',
'nextPageLabel' => 'Следваща',
'prevPageLabel' => 'Предишна',
)); `
The problem is: there is not a relation between the widget and the displayed results.
For instance, if I get 4 results, the widget correctly shows that there are 2 pages. However, the results are not displayed in two pages, all are shown in one and clicking the CLinkPager links does nothing.
I have done pagination in the past successfully before, but for all the data using
model()->findAll().
How do I state the relation between the pagination widget and the search results... ?
Thank you for your time.
I think you are possibly overcomplicating the process. You could more easily use CListView widget to display your results with pagination.
Your controller may have this;
public function actionIndex(){
$model = new Model;
$this->render('index', array('model' => $model);
}
Your model needs to have a search method that returns an instance of CActiveDataProvider, for example
public function search() {
$criteria = new CDbCriteria;
$criteria->compare('id', $this->id, true);
$criteria->compare('title', $this->title, true);
$criteria->order = 'sortOrder';
return new CActiveDataProvider($this, array(
'criteria' => $criteria,
));
}
Then in your view file you can use this code;
$this->widget('widgets.CListView', array(
'dataProvider' => $model->search(),
'itemView' => '_list',
'template' => '{pager}{items}',
'pager' => array(
'nextPageLabel' => 'Следваща',
'prevPageLabel' => 'Предишна',
)
));
You can extend the CListView by putting this in your extensions folder, and change the page size there.
<?php
Yii::import('zii.widgets.CListView');
class CustomListView extends CListView {
public function init() {
if ($this->dataProvider !== null)
$this->dataProvider->pagination->pageSize = 30;
$this->dataProvider->pagination->nextPageLabel => 'Следваща';
$this->dataProvider->pagination->prevPageLabel => 'Предишна';
parent::init();
}
}
Then, use the CustomListView as follows:
<?php $this->widget('CustomListView', array(
'dataProvider'=>$dataProvider,
'itemView'=>'_view',
)); ?>
You do not need to use CLinkPager widget directly this way.