Ignore blank empty fields from update using php mysql - php

Question

I need a little help to update mysql. I don't want blank/empty input fields to update but when i keep them blank or empty it automatically updates the fields
here is my code
$sql="UPDATE `tblsitesetup` SET
`site_name` = '".mysqli_real_escape_string($conn,$sitename_new)."',
`site_hometitle` = '".mysqli_real_escape_string($conn,$sitetitle_new)."',
`site_homedescrp` = '".mysqli_real_escape_string($conn,$final_description)."',
`site_homekeywords` = '".mysqli_real_escape_string($conn,$final_keywords)."',
`site_analytics` = '".mysqli_real_escape_string($conn,$final_analytics)."',
`site_ad1` = '".mysqli_real_escape_string($conn,$final_ad1)."',
`site_ad2` = '".mysqli_real_escape_string($conn,$final_ad2)."',
`site_ad3` = '".mysqli_real_escape_string($conn,$final_ad3)."'
WHERE `site_id` = '1'";
$result=mysqli_query($conn,$sql);

Answer 1

The correct way to do it is not to put those items in the query at
all:
$updates = array();
if (!empty($sitename_new))
$updates[] = 'sitename_new="'.mysql_real_escape_string($sitename_new).'"';
if (!empty($sitetitle_new))
$updates[] = 'sitetitle_new="'.mysql_real_escape_string($sitetitle_new).'"';
// .......
// ....... fill all cases here
$updates = implode(', ', $updates);
$sql = "UPDATE tblsitesetup` SET $updates WHERE `site_id` = '1'";
Obviously it would be cleaner to put the changes in an associative array or object, and then loop through them.
Reference: mysql update - skip blank fields?

Answer 2

$update=array('site_name'=>$sitename_new
'site_hometitle' => $sitetitle_new
/* etc ... */
'site_ad3' => $final_ad3 );
$sets=array();
foreach($update as $field => $value )
if( "$value" != "" )
$sets[]="`$field` = ". mysqli_real_escape_string($conn,$field);
if($sets)
{
$sql="UPDATE `tblsitesetup` SET \n".implode(",\n",$sets)."
WHERE `site_id` = '1'";
$result=mysqli_query($conn,$sql);
}
else
{
$result=NULL;
}

Answer 3

Build your SQL string using if statements:
$sql = 'UPDATE TABLE SET ';
If (trim($field)!='') $sql.=' FIELD=$field ';
And so on...
Be sure to have a valid SQL statement at the end.