Call a class by string PHP - php

Question

I'm calling a class by a string variable passed on a function argument.
ApiTester.php
use MyApp\Sites\Site;
abstract class ApiTester extends TestCase() {
/**
* Make a new record in the DB
*
* #param $type
* #param array $fields
* #throws BadMethodCallException
*/
protected function make($type, array $fields = [])
{
while($this->times--)
{
$stub = array_merge($this->getStub(), $fields);
$type::create($stub);
}
}
SitesTester.php
class SitesTester extends ApiTester() {
/** #test */
public function it_fetches_a_single_site()
{
// arrange
$this->make('Site');
// act
$site = $this->getJson('api/v1/sites/1')->data;
// assertion
$this->assertResponseOk();
$this->assertObjectHasAttributes($site, 'name', 'address');
}
Site.php // Eloquent Model
namespace MyApp\Sites;
class Site extends \Eloquent {
}
But if I call the class that the string variable $type contains, for example; string variable $type contains 'Site', it says class 'Site' not found.
I tried to manually type Site::create($stub) and finally accepts it.
I also tried
call_user_func($type::create(), $stub);
and
$model = new $type;
$model->create($stub);
but unfortunately it says class 'Site' not found.
Any ideas?

Answer 1

You're almost there:
class X {
static function foo($arg) {
return 'hi ' . $arg;
}
};
$cls = 'X';
print call_user_func("$cls::foo", 'there');
If your php is very old (<5.3 I believe), you have to use an array instead:
print call_user_func(array($cls, "foo"), 'there');

Answer 2

You may want to replace that static class call with the following :
while( $this->times-- )
{
$stub = array_merge( $this->getStub(), $fields );
call_user_func( "$type::create", $stub );
}
Runnable code here : http://runnable.com/VIqy4CDePeY-AeMV/output