Creating multiple divs according to variable - php

Removed (by original poster) due to unclear formulation of question.
More accurate question: Create divs associated to objects

for ($i = 0; $i < $amountOfPersons; $i++)
{
?>
<div class="fixed-size-square">
<span><?php echo $someContentThatBelongsToPerson[$i]; ?></span>
</div>
<?php
}

Assuming you'll get your database results returned to you in an array, the common way of doing this would be this in PHP:
foreach( $persons as $person ){
echo '<div class="fixed-size-square">
<span>I\'m a 200 x 200 px square with centered content no matter how many lines it takes</span>
</div>';
}
You could do it with the $amountPersons variable too (although I don't know why you'd want that if you get a result set back from the database), like this:
for ( $i = 0, $i < $amountPersons, $i++ ){
echo '<div class="fixed-size-square">
<span>I\'m a 200 x 200 px square with centered content no matter how many lines it takes</span>
</div>';
}
edit:
By the way, re-reading your question I realized you want to eventually put names in your divs, presumably the names stored in your database. You can do that with the first example, like this (this assumes the column name is your database is personName and that your result set is an array of objects.):
foreach( $persons as $person ){
echo '<div class="fixed-size-square">
<span>Name: '.$person->name.'</span>
</div>';
}

Since you have not tagged this as JavaScript, I can only assume you want a PHP approach to this, when you build the page I can only assume that you are running a query to get the records from the DB (since no code is provided).
All you need to do is wrap your div inside a for loop like this.
<html>
<head>
<link rel="stylesheet" type="text/css" href="style.css">
</head>
<body>
<?php
for($i = 0; $i < $AmountPersons; $i++){
echo '
<div class="fixed-size-square">
<span>I\'m a 200 x 200 px square with centered content no matter how many lines it takes</span>
</div>
';
}
?>
</body>
</html>
Hope this helps!

Try this
for ($i = 0; $i < $amountOfPersons; $i++) { ?>
<div class="fixed-size-square">
<span><?php echo $someContentThatBelongsToPerson[$i]; ?></span>
</div>
<?php } ?>

Related

how to loop through items but display them in group of 6

I have an array of 34 logos. I would like to display them but I want to make a slider and have 6 logos on each slides.
I have difficulties to create the loop. My code is in Php but it's the logic who matters here I think. Here what I have done so far. I miss the loop in the middle.
$number_of_slides = round($logo_array, 0, PHP_ROUND_HALF_UP);
for($i ; $i < $number_of_slides ; $i++):
<div class="slide">
......
</div>
<?php endfor; ?>
Thanks for any help
If you already have your array split it into chunks:
$logo_array = [];
$chunks = array_chunk($logo_array, 6); // 6 is a size of chunk
foreach ($chunks as $chunk) {
// do dome stuff for each chunk, open some wrapper div or whatever
foreach ($chunk as $logo) {
// output current logo
}
// do dome stuff for each chunk, close some wrapper div or whatever
}
Or, if you want to do it in one loop, you could use some modulo logic:
$number_of_slides = 25;
$str='<div class="slide">';
for ($i=0 ; $i < $number_of_slides-1 ; $i++) {
$str.= $logo_array[$i].($i%6==5?"</div>\n<div class=\"slide\">":' ');
}
$str.=$logo_array[$i].'</div>';
echo $str; // output the whole string
A simplified demo can be found here: http://rextester.com/DVMPR99965
This not have any sense... your slider is in JS I presume? If it is, all logos would necessarily be into page and is your slider that will take care of the rest.
Some sliders have a specific verbose to separate the itens, others don't, just needing to set the max number of itens to be displayed into page.
What I would do? Well:
<div class="slide">
<?php
foreach($logo_array as logo){
echo "<img src='{$logo[src]}'>"; //or other tag pattern of your slider
}
?>
</div>

if last element echo'class="last"'

I am new to php and I am trying to create a simple bit of code that prints a "last" class at the start of the last element in a "while" loop. There are only two items in the loop (blog excerpts) hence why I have tried below with the if ($i == 1)... Thanks for any help.
Here is my code so far - which only returns the p
<?php
$i = 0;
if($i == 1) {
echo '<p class="last">';
}
else {
echo '<p>';
}
?>
EDIT:
Thanks for the help so far. Greatly appreciated - I have provided a bit more information below (I posted late at night, so I realise I haven't been all that clear).
This is the full piece of code I am trying to write. It is pulling blog excerpts from Wordpress - currently limited to 2 blog articles.
<?php
$posts = new WP_Query('showposts=2');
while ( $posts->have_posts() ) : $posts->the_post();
?>
<p><?php echo the_title(); ?><br/>
<?php echo substr(get_the_excerpt(), 0,200); ?>... Read More</p>
<?php endwhile; ?>
<?php wp_reset_query(); ?>
I am wanting to add the class "last" to the p at the start of line 5 - for the last blog except only.
Thanks again.
Nick's answer says almost all that needs to be said.
The only thing I might add is a slight variation to save duplication particularly if the the contents of your paragraph tags is more complicated.
This might be better done with the following tweak on Nick's code:
<style>
#contents p:last-child {
PUT CONTENTS OF CLASS HERE
}
</style>
<body>
<div id="#contents">
<?php
$numLoops = 2;
$ctext=""
for($i=0; $i<$numLoops; $i++) {
$info="whatever";
if($i == (numLoops-1)) {
$ctext=' class="last"';
}
echo "<p${ctext}>${info}</p>\n";
}
?>
</div>
</body>
Cheers
So you have two paragraphs, and you want to apply the class "last" to the last one? Sounds like this is better handled with CSS
<style>
#contents p:last-child {
PUT CONTENTS OF CLASS HERE
}
</style>
<body>
<div id="#contents">
<p> first info</p>
<p> last info </p>
</div>
</body>
OR if you want to learn about loops
<?php
$numLoops = 2;
for($i=0; $i<$numLoops; $i++) {
if($i == (numLoops-1)) {
echo '<p class="last">';
} else {
echo '<p>';
}
}
What we are doing here with the for loop is initially setting the variable $i=0; then setting a test that says keep looping as long as the variable is less than the number of loops we want do do. Next we are setting what to do each loop, in this case we increment our variable by one each time.
First loop
i=0, we see that 0 is < 2 so we continue
Second loop
We execute the $i++ so we increment $i by 1 from 0 to $i=1,
we test and see $i=1 is still less than 2 so we continue.
Third attempted loop
We increment $i by 1 and get $i=2.
We test to see if this is less than 2, but it is NOT so we do not execute code in the loop
The main issue is that you don't have a loop in your code, and if you did you aren't incrementing your variable $i

how can put value in two columns?

how can a list of values that select of database, put in two columns together by PHP ?
EXAMPLE:
values select of database:
Internet
Game Notes
Internet
Pool
Coffee
Game Notes
i want like this:
Row-first order
<table>
<?php
$left = true;
foreach ($values as $value){
if ($left)
echo "<tr>";
echo "<td>$value</td>";
if (!$left)
echo "</tr>";
$left = !$left;
}
?>
</table>
With column-first order (as in your sample) you'll have to involve CSS and it's much complex. Something like
<div class='inline_div'>
<?php
$middle = count($values)/2+1;
$count = 0;
foreach ($values as $value){
if ($count==$middle)
echo "</div><div class='inline_div'>";
echo "$value<br/>";
++$count;
}
?>
</div>
inline_div is something like .inline_div {display:inline; float:left}. But that will definitely not work as expected, I'm no CSS master. IE does not support display:inline for sure.
If you want it exactly like you want in your example then you are going to have to read the whole table into memory, calculate the mid-point element and then build your table from that using a base point, an offset and a check to ensure that you've not repeated anything which involves a whole load of calculation.
A way around this would be to build two separate tables (each containing a single column) and then enclose them in a single table with two columns:
<?php
$list=array('a','b','c','d','e','f');
$midpoint=floor(count($list)/2);
$tableHeader='<table width="100%">';
$tableFooter='</table>';
$leftTable=$tableHeader;
$rightTable=$tableHeader;
for ($c=0; $c<$midpoint; $c++)
{
$leftTable.='<tr><td width="100%">'.$list[$c].'</td></tr>';
}
$leftTable.=$tableFooter;
for ($c=$midpoint; $c<count($list); $c++)
{
$rightTable.='<tr><td width="100%">'.$list[$c].'</td></tr>';
}
$rightTable.=$tableFooter;
$mainTable='<table><tr><td width="50%">'.$leftTable.'</td><td width="50%">'.$rightTable.'</td></tr></table>';
echo $mainTable;
?>
Or something along those lines. I haven't tested this code but it would be pretty close (may have to adjust the values in the "for" sections
The simple solution would be to use two divs. As a previous poster commented, you first need to count the elements. Suppose the items you want to display are in an array $items You can use this kind of code
<?php
$divItemCount = (count($items)%2) ? count($items)/2 + 1 : count($items)/2;
?>
<div id="leftdiv" style="width: 30%;">
<ul>
<?php
for($i=0; $i<$divItemCount; $i++) {
echo '<li>'. $items[$i] .'</li>';
}?>
</ul></div><div id="rightdiv" style="width: 30%; float:left"><ul>
<?php
for($j=$i; $j<count($items); $j++) {
echo '<li>'. $items[$j] .'</li>';
}?>
</ul></div>
I have not tested the code so there may be errors. You can use the border property in the divs to create a custom separator between the two lists.

problem in showing 3 images in a row

hey guys , i know this is a stupid question but i hanged in solving it
i wrote a block of php code to show images from mysql
echo "<table><tr> ";
while($cat = $db->sql_fetchrow($catinfo)) {
echo '
<td>
<ul id="three-col" class="press">
<li>
<div class="post-content">
<a class="zoom1" href="'.$galsettings[setImgDir].'/'.$cat[galCatLocation].'/'.$cat[galCatImg].'">
<img src="'.$galsettings[setImgDir].'/'.$cat[galCatLocation].'/'.$cat[galCatImg].'" alt="artistry (via powerbooktrance)" />
</a>
</div>';
for ($i=0; $i>2; $i++) {
echo "</tr><tr>";
}
}
echo "</li></ul></td></tr></table>";
but with this code everything goes wrong and it doesnt break after each 3 images in row
i even used
if ($i>2) {
echo "</td></tr><tr>";
}
but as u know it only breaks the tr after image number 3 not every row
im really sorry for my foolish question
Try this:
echo "<table><tr> ";
$counter = 0;
while($cat = $db->sql_fetchrow($catinfo)) {
$counter++;
echo '
<td>
<ul id="three-col" class="press">
<li>
<div class="post-content">
<a class="zoom1" href="'.$galsettings[setImgDir].'/'.$cat[galCatLocation].'/'.$cat[galCatImg].'">
<img src="'.$galsettings[setImgDir].'/'.$cat[galCatLocation].'/'.$cat[galCatImg].'" alt="artistry (via powerbooktrance)" />
</a>
</div>
';
if ( $counter == 3 ) {
echo '</tr><tr>';
$counter = 0;
}
}
echo "</li></ul></td></tr></table>";
First off, the
for ($i=0; $i>2; $i++) {
should probably be
for ($i=0; $i < 2; $i++) {
There may be additional logic issues (looking)...
Indeed the logic seems utterly flawed, for ex. there doesn't appear to be anything which detects the the third image etc...
==> I suggest you try the snippet from tambler's answer. No point in trying and fix this one... but if you must:
the for ($i=0; $i>2; $i++) { loop is unnecessary. Even when fixed to $i < 2 (or 3...) this doesn't do anything useful.
with each new image you output a <td>, this needs to be closed with a </td>
there need to be a counter (the $i) you hint at in your snippet isn't valid
the counter is to be systematically incremented with each image
a test is to be added towards the end of the loop:
If counter >= 3 (or 2, if you make it 0-based)
reset counter;
emit ""
Also the <ul> and <li> and their respective closing tags are misplaced.
Where's you're </td> tag?
All your TDs have to be inside the TRs. You have to close the UL and TD before your TR.

Multi column dynamic PHP list

So what I'm trying to do is select all the distinct months from my database and then print them in a list. That, I can accomplish. The problem lies in the fact that I need my list to be two column. The way that I achieve this with CSS is by using 2 different div's "left" and "right" which are floated next to each other. This poses a problem with PHP because it needs to echo a div close and a new div open after it echoes the sixth month. Then it needs to start again from where it left off and finish. I can't just list all of the months in the HTML, either because I don't want it to list a month if I don't have any records in the DB for that month, yet. Any ideas? I hope I was clear enough!
Thanks!
-williamg
Something like this should work (the basic idea being to just keep a count of the months an increment it as you loop through them):
<div class="left">
<?php
$x = 1;
foreach($months as $month) {
# switch to the right div on the 7th month
if ($x == 7) {
echo '</div><div class="right">';
}
echo "<div class=\"row\">{$month}</div>";
# increment x for each row
$x++;
}
</div>
<?php
$numberOfMonths = count($months);
$halfwayPoint = ceil($numberOfMonths / 2);
echo "<div class=\"left\">";
for($i=0; $i<$halfwayPoint; $i++){
echo $months[$i] . "<br />";
}
echo "</div><div class=\"right\">";
for($i=$halfwayPoint; $i<$numberOfMonths; $i++){
echo $months[$i] . "<br />";
}
echo "</div>";
?>
Rant: on
When displaying tabular data, use table instead of floating div. It will make sense when viewing the page with css disabled. If you use floated div, then you data will displayed all way down. Not all table usage is bad. People often hate table so much, so using floated div. Table only bad when used for page layout.
Rant: off
When I need to have certain content displayed with some open, close, and in-between extra character, I will make use of implode. This is the example:
$data = array('column 1', 'column 2');
$output = '<div>'.implode('</div><div>', $data).'</div>';
//result: <div>column 1</div><div>column 2</div>
You can extends this to almost anything. Array and implode is the power that php have for many years. You will never needed any if to check if it last element, then insert the closing character, or check if it first element, then insert opening character, or print the additional character between elements.
Hope this help.
Update:
My bad for misread the main problems asked. Sorry for the rant ;)
Here is my code to make a data displayed in 2 column:
//for example, I use array. This should be a result from database
$data = array(1, 2, 3, 4, 5, 6, 7, 8, 9);
//should be 12 month, but this case there are only 9 of it
for ( $i = 0; $i <= 5; $i++)
{
//here I do a half loop, since there a fixed number of data and the item for first column
$output = '<div class="left">'.$data[$i].'</div>';
if ( isset($data[$i+6] )
{
$output = '<div class="right">'.$data[$i+6].'</div>';
}
echo $output."\n";
}
//the result should be
//<div class="left">1</div><div class="right">7</div>
//<div class="left">2</div><div class="right">8</div>
//<div class="left">3</div><div class="right">9</div>
//<div class="left">4</div>
//<div class="left">5</div>
//<div class="left">6</div>
Other solution is using CSS to format the output, so you just put the div top to down, then the css make the parent container only fit the 6 item vertically, and put the rest to the right of existing content. I don't know much about it, since it usually provided by fellow css designer or my client.
Example assumes you have an array of objects.
<div style="width:150px; float:left;">
<ul>
<?php
$c = count($categories);
$s = ($c / 3); // change 3 to the number of columns you want to have.
$i=1;
foreach($categories as $category)
{
echo '<li>' . $category->CategoryLabel . '</a></li>';
if($i != 0 && $i % $s == 0)
{
?>
</ul>
</div>
<div style="width:150px; float:left;">
<ul>
<?php
}
$i++;
}
?>
</ul>
</div>

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