How to set object's function parameter optional in php oop - php

Question

I want something like this in a class structure:
$public $choice;
function __construct(){
$this->set_login($this->choice);
}
private function set_login($this->choice){
if($this->choice=='2'){
// don't set login credentials
}else{
// set login credentials
}
}
The above code requires $choice to be set every time before I initialize the class.
But I want to set $choice as optional parameter.
I want if in any page, I call like this:
$login = new login();
that class will set login credentials normally but if called like this:
$login = new login();
$login->choice = 2;
then login credentials will not be set.
I am not sure, whether the class will be executed in such way because as soon as I initialize the class, the __construct method will be called and the $choice to be set at that time. But if I set $choice after initialization, then will the code work?
How can I make a parameter optional in oop?

Answer 1

Just define you method set_login as:
public function set_login($choice = 1) {
if ($choice == 2) {
// don't set login credentials
} else {
// set login credentials
}
}
And use it like that:
$login = new login();
// Login.
$login->set_login();
// Doesn't login.
$login->set_login(2);
EDIT:
Another solution:
private $choice;
function __construct($choice = false) {
$this->set_login($choice);
// If you want to remember the choice, you can save it in a property:
$this->choice = $choice;
}
private function set_login($choice) {
if ($choice == 2) {
// don't set login credentials
} else {
// set login credentials
}
}
Note that the following code will never work as you expect because you change the value of choice after executing the method set_login in the constructor:
$login = new login();
$login->choice = 2;