PHP syntax error in function, don't know why - php

Question

I'm getting a syntax error and I can't figure out why. "Parse error: syntax error, unexpected '{' on line 6"
function ExtractCustomField($fieldName, $customFields) {
// $customFields might be an object, NULL, or an array.
$parsed = array();
if (is_array($customFields) == false && $customFields != null) {
$parsed = array($customFields);
} else (is_array($customFields)) {
$parsed = $customFields;
}
// loop through the fields and find the one we are looking for
$returnField = null;
foreach($field as $customFields) {
if ($field->Name == $fieldName) {
$returnField = $field;
break;
}
}
return $returnField
}

Answer 1

You forget to put semicolon after $returnField, also use elseif instead of else (else don't need any arguments). Use the code below
function ExtractCustomField($fieldName, $customFields) {
// $customFields might be an object, NULL, or an array.
$parsed = array();
if (is_array($customFields) == false && $customFields != null) {
$parsed = array($customFields);
} elseif (is_array($customFields)) {
$parsed = $customFields;
}
// loop through the fields and find the one we are looking for
$returnField = null;
foreach($field as $customFields) {
if ($field->Name == $fieldName) {
$returnField = $field;
break;
}
}
return $returnField;
}
Hope this helps you

Answer 2

else doesn't take any expression after it. Either remove the expression or use elseif instead.

Answer 3

You have missed semicolon in return
return $returnField;
}
Also Else condition else (is_array($customFields)) format is wrong....else dont take any condition after it...You can use Elseif instead

Answer 4

else (is_array($customFields)) {
Is invalid. Use either else if or remove the condition

Answer 5

function ExtractCustomField($fieldName, $customFields) {
// $customFields might be an object, NULL, or an array.
$parsed = array();
if (is_array($customFields) == true && $customFields != null) {
$parsed = array($customFields);
} else {
$parsed = $customFields;
}
// loop through the fields and find the one we are looking for
$returnField = null;
foreach($field as $customFields) {
if ($field->Name == $fieldName) {
$returnField = $field;
break;
}
}
return $returnField;
}

Answer 6

It should else if(is_array($customFields)) or elseif(is_array($customFields))

Answer 7

I have modified your function, i see there is supposed to be and elseif instead of else and in the foreach loop, the syntax in your code was wrong. I have also assumed that you will be using a single level associative array.
<?php
function ExtractCustomField($fieldName, $customFields) {
// $customFields might be an object, NULL, or an array.
$parsed = array();
if (is_array($customFields) == false && $customFields != null) {
$parsed = array($customFields);
} elseif (is_array($customFields)) {
$parsed = $customFields;
}
// loop through the fields and find the one we are looking for
$returnField = null;
foreach($customFields as $field) {
if ($field == $fieldName) {
$returnField = $field;
break;
}
}
return $returnField;
}
echo ExtractCustomField('name', array('name','emial','mobile','password'));
?>