Php Repeatable region - php

So i got this code, at the moment it is repeating everything , and i just wanted it to repeat the echo, so i get all usernames from it, if i leave it as it is it will also repeat the form when i press a username. Every time i tried to ajust it, it just gave me syntax errors
<?php do { ?>
<?php
$username = $row_mensagens['username'];
$user = $row_mensagens['id'];
if(isset($_GET['user']) && !empty($_GET['user'])){
?>
<form>
Introduz mensagem : <br>
<textarea name='message' rows='7' cols='60'></textarea>
<br><br>
<input type='submit' value="Send Message" />
</form>
<?php
} else {
echo "<p><a href='mensagens.php?user=$user'>$username</a></p>";
}
?>
<?php } while ($row_mensagens = mysql_fetch_assoc($mensagens)); ?>

that do { } while() will always repeat as many as the number of records come from database.
You can do it this way:
<?php
if(isset($_GET['user']) && !empty($_GET['user'])){
?>
<form>
<input type="hidden" name="user" value="<?php echo $_GET['user']; ?>" /> <!-- hidden field so you can process to who -->
Introduz mensagem : <br>
<textarea name='message' rows='7' cols='60'></textarea>
<br>
<br>
<input type='submit' value="Send Message" />
</form>
<?php
} else {
do {
$username = $row_mensagens['username'];
$user = $row_mensagens['id'];
echo "<p><a href='mensagens.php?user=$user'>$username</a></p>";
} while ($row_mensagens = mysql_fetch_assoc($mensagens));
}
?>
Move do { inside else and show the form only if you have a $_GET['user']
I have also added for you a hidden field, so you know who to send message.
Hope you understand how this works. Documentation on Control Structures: do-while
I also suggest to make that form a post form, as by default it is a get form, and since you have a textarea you are more likely to bump into errors if the message is too long.
LE: Another suggestion, try to move to PDO or mysqli_* functions since mysql_* functions are considered deprecated as of PHP 5.5 and have some good chances to be removed.

Related

php allow submit if variable is true

Newbie here, and self-taught in PHP. I have a questionnaire where each question has 2 answers, and users can add any combination of numbers to each, as long as they equal, i.e. 10. So far 2 questions (will be more) so each question's answers should equal 10, therefore total submitted values should equal 20. I can't find a way to only allow submit if these conditions are met. I would really appreciate any help.
Currently using this for testing purposes:
<input type="submit" value="Check!" name="check"/>
...at the bottom.
<?php
// Start the session
session_start();
?>
<!DOCTYPE html>
<html>
<?php
// Adding stuff
if(isset($_POST['check']))
{
$q1total=$realist[1]+$idealist[1];
$q2total=$realist[2]+$idealist[2];
$grandtotal=$q1total+$q2total;
}
?>
<body>
<form method="post">
Q1: <input type="text" name="realist[1]"/> <input type="text" name="idealist[1]"/>
<?php echo $q1total; ?>
<br>
Q2: <input type="text" name="realist[2]"/> <input type="text" name="idealist[2]"/>
<?php echo $q2total; ?>
<br>
<br><br>
Grand total: <?php echo $grandtotal; ?>
<br><br>
<input type="submit" value="Check!" name="check"/>
</form>
</body>
</html>
I'm also a self-taught PHP "newbie" as you describe it. I would honestly create a seperate PHP file that checks if the conditions are met.
Your form would be:
<form method="post" action="yourfile.php">
And in the php file:
$realist1 = $_POST["realist\[1\]"];
$idealist1 = $_POST["idealist\[1\]"];
$realist2 = $_POST["realist\[2\]"];
$idealist2 = $_POST["idealist\[2\]"];
if ($realist[1]+idealist[1]== 10 && $realist[2]+idealist[2] == 10)
{
echo "<button value='correct'/>";
}else{
echo "<button value='incorrect' disabled/>";
}
Obviously you have to adjust some stuff but hopefully this can help.

confused about basic find and replace app

I am trying to do a find and replace applicaiton the problem is that after cliked submit button all the text fields gets clean nothing displays on the screen What am i doing wrong
<?php
$offset=0;
if(isset($_POST['text'] ) && isset($_POST['searchfor']) && isset($_POST['replacewith'])){
$text=$_POST['text'];
$search=$_POST['searchfor'];
$replace=$_POST['replacewith'];
$searchLength=strlen($search);
if(!empty($text) && !empty($search) &&!empty($replace)){
while ($strpos= strpos($text,$search,$offset)){
echo $offset=$strpos+$searchLength;
}
} else {
echo "<script>alert('errorrrr')</script>";
}
}
?>
<form action="#" method="post">
<textarea name="text" id="" cols="30" rows="10"></textarea><br>
Search For:<br>
<input type="text" name="searchfor"><br>
ReplaceWith<br>
<input type="text"name="replacewith"><br>
<input type="submit" value="Fr..."></>
</form>
Regarding your form, you decided to submit to the same page.
Doing this, the page is obviously fully reloaded when submitted. Hence it is normal that what you typed in has disappeared.
If you want to see it again, you have to display you variables in the HTML code.
For example:
<?php
$myVar = "";
if(isset($_POST['myVar']){
$myVar = $_POST['myVar'];
}
?>
<form>
<input type="text" value="<?php echo $myVar;?>"/>
</form>
NB: I encourage you to filter the user entry.
Regards
there is problems in your code :
1 - echo $offset=$strpos+$searchLength; the echo can't be used in this format. insted use echo $offset; in next line for seeing offset values.
2 - if the text be like 'amir love persepolis' and search for 'amir' to replace it with 'all men's' you will have another issue, because you will have while ( 0 ) situation. think about this too!

PHP $_POST function not recognizing HTML form input value

I can't seem to apply the $_POST function properly to retrieve the data from a simple HTML form. I'm new to PHP, so I may be overlooking something simple.
I have a form with action directing to the same page, but if the form is filled out, the value of $_POST['input_name'] will have changed, so I can trigger the php function using that condition. Is this the best way to structure this kind of action?
Here's my HTML code (thispage.php is the current/same page):
<form action="thispage.php" method="post">
Name: <input type="text" name="userName" id="userName" />
<input type="submit" />
</form>
Here's my PHP code from the same page:
if("" == trim($_POST['userName'])){
echo $_POST['userName'];
}
Thanks a lot in advance!!
First remove the action from form if your server side code is in the same page. And Use the empty() or isset() functions for checking the value.
For Example:
if(!empty(trim($_POST['userName']))){
echo $_POST['userName'];
}
if(isset(trim($_POST['userName']))){
echo $_POST['userName'];
}
if("" == trim($_POST['userName'])){
echo $_POST['userName'];
}
This is actually checking if the value is empty and echoes it if it is.
You probably want to use !empty($_POST['userName']) to check if it's not empty and then echo it if it is not.
try this:
HTML code
<form action="thispage.php" method="post">
Name: <input type="text" name="userName" id="userName" />
<input type="submit" name="submit" />
</form>
PHP code on the same page:
if(isset($_POST['submit']))
{
if(isset(trim($_POST['userName']))){
echo $_POST['userName'];
}
}
Try this...
if(trim($_POST['userName']) != ' '){
echo $_POST['userName'];
}
you can try it:
if(isset($_POST['userName'])){
$name = $_POST['userName'];
echo $name;
}

Trying PHP IF Else Statements for the first time

I'm learning PHP and trying to understand the if .. else statements a little better, so I'm creating a little quiz. However, I have come across an issue and I don't seem to know what the issue is. My problem is that whenever I type in the age in the input area, it will give me the $yes variable every time even if I enter the wrong age.
Here is my code so far:
My html file:
<form action="questions.php" method="post">
<p>How old is Kenny?<input></input>
<input type="submit" name="age" value="Submit"/>
</p></form>
My php file:
<?php
$age = 25;
$yes = "Awesome! Congrats!";
$no = "haha try again";
if ($age == 25){
echo "$yes";
}else{
echo "$no";
}
?>
You catch the user input inside the $_POST superglobal var (because the method of your form is POST.
So
<?php
$age = 25;
should be
<?php
$age = $_POST['age'];
There is an error in HTML too. This
<input type="submit" name="age" value="Submit"/>
should be
<input type="text" name="age" value=""/>
<input type="submit" value="Click to submit"/>
Because you want one input and one button. So one html element for each element.
and <input></input> must be cleared because it's not valid syntax :-)
<form action="questions.php" method="post">
<p>How old is Kenny?</p><input type="text" name="age"></input>
<input type="submit" value="Submit"/>
</form>
$age = (int) $_POST["age"];
$yes = "Awesome! Congrats!";
$no = "haha try again";
if ($age == 25) {
echo $yes;
} else {
echo $no;
}
<?php
/* Test that the request is made via POST and that the age has been submitted too */
if( $_SERVER['REQUEST_METHOD']=='POST' && isset( $_POST['age'] ) ){
/*
ensure the age is an integer rather than a string ..
though for this not overly important
*/
$age=intval( $_POST['age'] );
if( $age==25 ) echo "Congratulations";
else echo "Bad luck!";
}
?>
<form action="questions.php" method="post">
<p>How old is Kenny?
<input type='text' name='age' placeholder='eg: 16' />
<input type="submit" value="Submit" />
</p>
</form>
A simple html form, note that the submit button does not carry the values you want to process, they are supplied via the input text element.
First of all, you need to echo the variable; echoing "$no" will keep it as a string. Remove the quotes from "$no" and "$yes" in your if then statement. Otherwise, your code seems sound!

Simple Php Echo

I am just starting to learn php, how would I initiate a echo statement after a submit button is pushed, or even a anchor tag.
Here is my code so far
form name="myform" method="get" actions="madlib01.php"
Name: <input type="text" name="name" /> <br />
<input type="submit" name="submit" />
form
<?php
$Name = $_GET['name'];
$hello .= "Hello $Name";
echo $hello //I would prefer the echo to happen after the submit button is hit
?>
the correct attribute for your form tag is "action", not "actions"
When the form is submitted, a new request is sent to the server (in your case, using GET).
So to do it all in one page:
form.php:
<form action="form.php" method="GET">
<input type="text" name="name"/>
<input type="submit">
</form>
<?PHP
if (! empty($_GET['name'])){
echo 'Hello, ' . $_GET['name'];
}
?>
You will first need to check if PHP has received your GET parameter using isset or array_key_exists:
if(isset($_GET['name']) && !empty($_GET['name'])) {
$Name = $_GET['name'];
echo "Hello $Name";
}
or:
if(array_key_exists('name', $_GET) && !empty($_GET['name'])) {
$Name = $_GET['name'];
echo "Hello $Name";
} else {
//example: default to something if nothing has been passed
echo "Hello Guest";
}
Also note, if you're submitting to the same page, you can omit the action attribute from your form tag altogether:
<form method="GET">
echo $hello
You've just gained an HTML-injection vulnerability. If someone sends your user to:
http://www.example.com/madlib01.php?name=<script>stealYourCookies()</script>
you've got problems.
Yes, this is a My First PHP Script. That doesn't make security optional. This is a mistake every tutorial makes: teaching bad practice from the start, treating correctness (and security, which is a subset of correctness) as an optional extra.
The result is that most PHP code out there is full of holes. But there's no need for yours to be! Every time you place a pure-text string into a surrounding HTML context, escape it properly:
echo htmlspecialchars($hello);
I tend to define a function with a shorter name than ‘htmlspecialchars’ to do that for me, as I'm lazy.
<?php
function h($text) {
echo(htmlspecialchars($text, ENT_QUOTES));
}
$name= '';
if (isset($_REQUEST['name']))
$name= trim($_REQUEST['name']);
?>
...
<?php if ($name!=='') { ?>
<p> Hello, <?php h($name); ?>! </p>
<?php } ?>
<form method="get" action="madlib01.php">
<p>
<label for="namefield">Name:</label>
<input id="namefield" type="text" name="name" />
</p>
<p>
<input type="submit" />
</p>
</form>
Now if you say your name is Mister <script>, the page will greet you exactly as such, angle brackets and all, instead of trying to run JavaScript. This is the correct output and thus also secure.

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