json-decode two feed sources - php

Question

I am try to decode two different json feed urls and merge into one oject/output. I have tried the below, however, not really having much luck.
feed source 1: http://sourcesample.com/feed/posts
data: [
{
name: "Me",
url: "http://example.com/sample",
title: "Sample Title",
}
]
feed source 2: http://differentsource.com/feed/details
data: [
{
likes: "200",
shares: "300",
total: "1000",
}
]
$sources =array("http://sourcesample.com/feed/posts", "http://differentsource.com/feed/details");
$requests = file_get_contents($sources[0],$sources[1]);
$response = json_decode($requests);
foreach($response->data as $item){
echo'<li>'.$item->name.'</li><li>'.$item->shares.'</li>'
Printing the name works, but when trying to print the second object feed, nothing. Any ideas?

Answer 1

file_get_contents() won't return more than one URL's contents at a time. The second parameter is being treated as true, roughly, for the use_include_path parameter. For your purposes, it's irrelevant.
Anyway, only the first feed is read. It includes no "shares" data.
Even if both were read, the result would be:
'data: [
{
name: "Me",
url: "http://example.com/sample",
title: "Sample Title",
}
]
data: [
{
likes: "200",
shares: "300",
total: "1000",
}
]'
which is not a valid JSON string - it's two objects next to each other, not merged.
If you're really confident that both feeds are the same size, you can read them both (separately) then loop through them at once:
$names = json_decode( file_get_contents( $sources[0] ) );
$stats = json_decode( file_get_contents( $sources[1] ) );
for ( $i = 0; $i < count( $names->data ); ++$i )
{
$name = $names->data[$i];
$stat = $stats->data[$i];
echo '<li>' . htmlspecialchars($name->name) . '</li><li>' .
htmlspecialchars($stat->shares) . '</li>';
}