Yii function in layout file - php

Question

I'm using Yii and I'm new to it.
I have a default main.php layout file and i need to make some data extractions from DB and cookies.
I've written 2 functions:
public function getRegionId() {
if(isset(Yii::app()->request->cookies['region_id'])) {
$sk = Yii::app()->request->cookies['region_id']->value;
settype($sk,integer);
return $sk;
} else {
return 1;
}
}
public function regionId2region($id) {
if(empty($id) or gettype($id)!=='integer') {
return null;
} else {
$reg = Regions::model()->findAll(array(
'condition'=>"alive=1 AND id=".$id,
));
return $reg;
}
}
Now it is not working in any controller. My question is: is it possible to make functions in the layout file or is there a way to pass data to layout file (so that it displays in all controllers)?

Answer 1

Move methods into Regions model and make it static. Or Create Helper class? contains just static methods.
class RegionHelper {
public static function getRegionId() {
if(isset(Yii::app()->request->cookies['region_id'])) {
return (int)$Yii::app()->request->cookies['region_id']->value;
}
return 1;
}
public static function regionId2region($id) {
if(empty($id) or gettype($id)!=='integer') {
return null;
} else {
$reg = Regions::model()->findAll(array(
'condition'=>"alive=1 AND id=".$id,
));
return $reg;
}
}
}

Answer 2

You can use BeforeAction in your controller, like this:
protected function beforeAction($action) {
//Define your variable here:
public $yourVaribale;
//do your logic and assign any value to variable
}
Now, you can use this variable in the view file:
view:
<h1><?php echo $this->yourVariable; ?></h1>

Answer 3

If your functions are located in the controller that calls the view, you could use the $this reference to access the function. Note the public access of the function.
class UserController extends Controller
{
// :
// :
public function fullName($a,$b) {
return $a.' '.$b;
}
}
...and in your view ...
<h1>Test for <?php echo $this->fullName('Tom', 'Jones'); ?></h1>
If the function is in your model, there are a few choices.
class User extends Activerecord
{
// :
// :
public function fullName($a,$b) {
return $a.' '.$b;
}
}
You could pass the model through the render function,
class UserController extends Controller
{
// :
// :
public function actionDisplayView {
$userModel = User::model()->findByPK(1);
$this->render('user_view', array('model' => $model));
}
}
and directly call the function in the view.
< h1 >Test for <?php echo $model->fullName('Tom', 'Jones'); ?>< / h1 >
or, if you did not pass the function, you could call the function in the view (or helper classes). Watch the scope.
class User extends Activerecord
{
// :
// :
// NOTE: You won't have access to $this.
static public function fullName($a,$b) {
return $a.' '.$b;
}
}
and in the view
< h1 >Test for <?php echo User::fullName('Tom', 'Jones'); ?>< /h1 >