php script won't connect MySQL - php

Question

This is the code. and for some reason I can't find out why it is not working.
As you can see I've added a test query to see if it affects any changes on my db but nope :(
The funny thing is that in another php script I have succeeded to connect the db and even added some records to it thru the php script. Can't find the problem, Thanks from advance.
BTW. as you can see I have already defined the var "month" as string "hey" and echo it in the end of the php script to see if it changes. but nothing is happen!!
<form action="" name="form" id="form">
<label>
Select the month which you want to display its days.
<select name="month" form="form" required>
<option value="january">January</option>
<option value="february">February</option>
<option value="march">March</option>
<option value="april">April</option>
<option value="may">May</option>
<option value="june">June</option>
<option value="july">July</option>
<option value="august">August</option>
<option value="september">September</option>
<option value="october">October</option>
<option value="november">November</option>
<option value="december">December</option>
</select>
</label>
<input type="submit" name="update" value="Display" />
</form>
<?php
$month = "hey";
if(isset($_POST["update"]))
{
$month = $_POST["month"];
$query = "SELECT * FROM `days` WHERE `month`='{$month}';";
$conn = mysqli_connect("localhost","root","","db123");
$result = mysqli_query($conn,$query);
mysqli_query($conn,"INSERT INTO `days`(`month`,`day`) VALUES ('test','10');");
if($result)
{
die("Sorry!");
}
while($row = mysqli_fetch_row($result))
{
echo $month;
print_r($row);
}
mysqli_close($conn);
echo $month;
}
?

Answer 1

You didn't specified the method , its GET by default if.Change this line
if(isset($_POST["update"]))
to this
if(isset($_GET["update"]))
. Or if you want to use method as POST than just specify the method as POST
use the code below
<form action="" name="form" id="form" method="POST">
<label>
Select the month which you want to display its days.
<select name="month" form="form" required>
<option value="january">January</option>
<option value="february">February</option>
<option value="march">March</option>
<option value="april">April</option>
<option value="may">May</option>
<option value="june">June</option>
<option value="july">July</option>
<option value="august">August</option>
<option value="september">September</option>
<option value="october">October</option>
<option value="november">November</option>
<option value="december">December</option>
</select>
</label>
<input type="submit" name="update" value="Display" />
</form>
<?php
$month = "hey";
if(isset($_POST["update"]))
{
$month = $_POST["month"];
$query = "SELECT * FROM `days` WHERE `month`='{$month}';";
$conn = mysqli_connect("localhost","root","","db123");
$result = mysqli_query($conn,$query);
mysqli_query($conn,"INSERT INTO `days`(`month`,`day`) VALUES ('test','10');");
if($result)
{
die("Sorry!");
}
while($row = mysqli_fetch_row($result))
{
echo $month;
print_r($row);
}
mysqli_close($conn);
echo $month;
}
?>
Hope this helps you

Answer 2

<?php
$mysqli = new mysqli("localhost", "root", "", "db123");
if ($mysqli->connect_errno) {
echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
}
$month = "hey";
if(isset($_POST["update"]))
{
$month = $_POST["month"];
$res = $mysqli->query("SELECT * FROM `days` WHERE `month`='{$month}'");
mysqli_query($conn,"INSERT INTO `days`(`month`,`day`) VALUES ('test','10');");
while($row = $res->num_rows)
{
echo $month;
print_r($row);
}
mysqli_close($conn);
echo $month;
}
?>