PHP MYSQL CASE substitution in array [duplicate] - php

Question

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mysql_fetch_array()/mysql_fetch_assoc()/mysql_fetch_row()/mysql_num_rows etc... expects parameter 1 to be resource
(31 answers)
Closed 8 years ago.
Morning all, happy new year!
I am trying to select all records within a MYSQL database into an array where 1 column matches a list, and then replace the output of the cells when selected from that column.
It's a sports table, and I have the Positions as MF, DF, CF and want to replace them with Midfield, Defence, and Forward respectively.
I was hoping that the following would crack it, but get an error message, which lines up to the FROM line:
Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in /home/peterborough/www/www/wp-content/plugins/insert-php/insert_php.php(48) : eval()’d code on line 14
$result = mysql_query("SELECT *,
CASE Position
WHEN 'DF' THEN 'Defence'
WHEN 'MF' THEN 'Midfield'
WHEN 'CF' THEN 'Forward'
FROM People
WHERE
(Position='DF' or
Position='MF' or
Position='CF') and
Season = '2014'
ORDER BY Number");
while($row = mysql_fetch_assoc($result)){...}
Thanks guys

Answer 1

you have a syntax error in your SQL:
the CASE expression requires an END
SELECT *,
CASE Position
WHEN 'DF' THEN 'Defence'
WHEN 'MF' THEN 'Midfield'
WHEN 'CF' THEN 'Forward'
END AS position_long
FROM People
WHERE
(Position='DF' or
Position='MF' or
Position='CF') and
Season = '2014'
ORDER BY Number
Explanation:
when the syntax error hits, you get a FALSE from the mysql_query() call and
when that's passed into mysql_fetch_assoc() it complains about being given a boolean instead of a resource