Check if string contains any value of an array? - php

Question

$search=array("<",">","!=","<=",">=")
$value="name >= vivek ";
I want to check if $value contains any of the values of the $search array. I can find out using foreach and the strpos function. Without resorting to using foreach, can I still find the answer? If so, kindly help me to solve this problem.

Answer 1

Explode $value and convert it into array and then use array_intersect() function in php to check if the string does not contain the value of the array.Use the code below
<?php
$search=array("<",">","!=","<=",">=");
$value='name >= vivek ';
$array = explode(" ",$value);
$p = array_intersect($search,$array);
$errors = array_filter($p);
//Check if the string is not empty
if(!empty($errors)){
echo "The string contains an value of array";
}
else
{
echo "The string does not containe the value of an array";
}
?>
Test the code here http://sandbox.onlinephpfunctions.com/code/7e65faf808de77036a83e185050d0895553d8211
Hope this helps you

Answer 2

Yes, but it will require you to re structure your code.
$search = array("<" => 0, ">" => 1,"!=" => 2,"<=" => 3,">=" => 4);
$value = "name => vivek ";
$value = explode(" ", $value);
foreach($value as $val) {
// search the array in O(1) time
if(isset($search[$val])) {
// found a match
}
}

Answer 3

Use array_map() and array_filter()
function cube($n)
{
$value="name => vivek ";
return strpos($value, $n);
//return($n * $n * $n);
}
$a = array("<",">","!=","<=",">=");
$value="name => vivek ";
$b = array_map("cube", $a);
print_r($b);
$b = array_filter($b);
print_r($b);

Answer 4

$search = array("<",">","!=","<=",">=");
$value="name => vivek ";
foreach($value as $searchval) {
if(strpos($value, $searchval) == false)
{
echo "match not found";
}
else
{
echo "match found";
}
}

Answer 5

Here's a solution using array_reduce:
<?PHP
function array_in_string_callback($carry, $item)
{
list($str, $found) = $carry;
echo $str . " - " . $found . " - " . $str . " - " . $item . "<br/>";
$found |= strpos($str, $item);
return array($str, (boolean) $found);
}
function array_in_string($haystack, $needle)
{
$retVal = array_reduce($needle, "array_in_string_callback", array($haystack, false));
return $retVal[1];
}
$search=array("<",">","!=","<=",">=");
$value="name >= vivek ";
var_dump(array_in_string($value, $search));
?>

Answer 6

My first inclination was to solve the problem with array_walk() and a callback, as follows:
<?php
$search=array("<",">","!=","<=",">=");
$value = "name >= vivek ";
function test($item, $key, $str)
{
if( strpos($str, $item) !== FALSE ) {
echo "$item found in \"$str\"\n";
}
}
array_walk($search, 'test', $value);
// output:
> found in "name >= vivek "
>= found in "name >= vivek "
Live demo: http://3v4l.org/6B0WX
While this solves the problem without a foreach loop, it answers the question with a "what" rather than a "yes/no" response. The following code directly answers the question and permits answering the "what" too, as follows:
<?php
function test($x)
{
$value="name >= vivek ";
return strpos($value, $x);
}
$search = array("<",">","!=","<=",">=");
$chars = array_filter( $search, "test" );
$count = count($chars);
echo "Are there any search chars? ", $answer = ($count > 0)? 'Yes, as follows: ' : 'No.';
echo join(" ",$chars);
// output:
Are there any search chars? Yes, as follows: > >=
Live demo: http://3v4l.org/WJQ5c
If the response had been negative, then the output is 'No.' followed by a blank space.
A key difference in this second solution compared to the first, is that in this case there is a return result that can be manipulated. If an element of the array matches a character in the string, then array_filter adds that element to $chars. The new array's element count answers the question and the array itself contains any matches, if one wishes to display them.