Trouble inserting two array values into database - php

Question

Here is the code I am using for multiple image upload for every entry in the database; id, image, name, date. By using this code, the image name is inserting correctly but I have a problem with the name field. I want to insert the name using $product_name= $_POST['pro_name']; but it only inserts 'array' in name field.
<?php
include('../config.php');
if (isset($_POST['submit'])) {
$product_name = $_POST['pro_name'];
$j = 0; // Variable for indexing uploaded image.
$target_path = "uploads/"; // Declaring Path for uploaded images.
for ($i = 0; $i < count($_FILES['file']['name']) && $product_name < count($product_name); $i++) {
// Loop to get individual element from the array
$validextensions = array("jpeg", "jpg", "png"); // Extensions which are allowed.
$ext = explode('.', basename($_FILES['file']['name'][$i])); // Explode file name from dot(.)
$file_extension = end($ext); // Store extensions in the variable.
$target_path = $target_path . md5(uniqid()) . "." . $ext[count($ext) - 1]; // Set the target path with a new name of image.
$j = $j + 1; // Increment the number of uploaded images according to the files in array.
if (($_FILES["file"]["size"][$i] < 100000000) // Approx. 100kb files can be uploaded.
&& in_array($file_extension, $validextensions)) {
if (move_uploaded_file($_FILES['file']['tmp_name'][$i], $target_path)) {
$finel_name = explode('/', $target_path);
$image_name_final = $finel_name[1];
$jajsj = "insert into spec_product set image='$image_name_final', name='$product_name'";
$janson = mysql_query($jajsj) or die(mysql_error());
// If file moved to uploads folder.
echo $j . ').<span id="noerror">Image uploaded successfully!.</span><br/><br/>';
} else { // If File Was Not Moved.
echo $j . ').<span id="error">please try again!.</span><br/><br/>';
}
} else { // If File Size And File Type Was Incorrect.
echo $j . ').<span id="error">***Invalid file Size or Type***</span><br/><br/>';
}
}
}
?>

Answer 1

The value is inserting as array because the variable $product_name is not a string but an array. Whenever an array is used where a string was expected e.g.: concatenation of a string or in your case the query statment: insert into spec_product set image='$image_name_final', name='$product_name'"; PHP will automatically convert the array into its default string value "Array".
Make sure that $product_name is not an array but a string which contains name of the product you want to insert in the table.
Regards,
Nitin Thakur

Answer 2

replace in your code
for ($i = 0; $i < count($_FILES['file']['name']); $i++)
{
and add this before your query execute
$product_name_final= $product_name[$i];