php fetch column values from database and display in html table column - php

Question

I have a table in database name Accounts in which i have many rows and many columns, i want to show a column Account (all values) in my html table. I have tried many method to show a specific column values without using index in html using php and I am using MySql.
$storeArray = Array();
while($rowval = mysql_fetch_array($whole, MYSQL_ASSOC))
{
$storeArray[] = $rowval['Account'];
$status= $rowval['status'];
$ph1= $rowval['Phone1'];
$ph2= $rowval['Phone2'];
}
by using <?php echo $storeArray[0]; ?> and <?php echo $storeArray[1]; ?> in <td> i got the solution. My question is there any way, it automatically show all values without providing any index?

Answer 1

$conn=new mysqli("localhost","root","","your_db");
$rows=$conn->query("select username from User");
echo "<table border='1'>";
echo "<tr><th>Username</th></tr>";
while(list($username)=$rows->fetch_row()){
echo "<tr><td>$username</td></tr>";
}
echo "</table>";

Answer 2

This is a pretty elaborate question. I think the best I can do is point you in the right direction. There is a good tutorial for this on w3schools.com. You should at least read these:
PHP - Connect to MySQL
PHP - Select Data From MySQL
and maybe
PHP - Limit Data Selections From MySQL

Answer 3

**file user.php**
<?php
$conn=new mysqli("localhost","root","","your_db");
$rows=$conn->query("select id,username from User");
echo "<table border='1'>";
echo "<tr><th>Username</th></tr>";
while(list($id,$username)=$rows->fetch_row()){
echo "<tr>";
echo "<td>";
echo "<form action='user_details.php' target='_blank' method='post'>";
echo "<input type='hidden' name='txtId' value='$id' />";
echo "$id - $username";
echo "<input type='submit' name='btnView' value='View' />";
echo "</form>";
echo "</td>";
echo "</tr>";
}
echo "</table>";
?>
**file user_details.php**
<?php
if(isset($_POST["btnView"])){
$id=$_POST["txtId"];
$conn=new mysqli("localhost","root","","your_db");
$row=$conn->query("select id,username,email,phone from User where id='$id'");
list($id,$username,$email,$phone)=$row->fetch_row();
echo $id," ",$username," ",$email," ",$phone;
}
?>

Answer 4

if you want to fetch more than one database column in your html table column.
$conn=new mysqli("localhost","root","","your_db");
$rows=$conn->query("select col1,col2 from Tablename");
echo "<table border='1'>";
echo "<tr><th>col1</th><th>col2</th></tr>";
while(list($col1, $col2)=$rows->fetch_row())
{
echo "<tr><td>$col1</td><td>$col2</tr>";
}
echo "</table>";