This is my php file for uploading files, but i am getting an error like no such directory whats wrong with my code?
upload.php
<?php
$vdo=$_FILES['uf']['name']; $target_path = "/photo";
$target_path = $target_path . basename( $_FILES['uf']['name']);
$target_path . basename( $_FILES['uf']['name']);
if(move_uploaded_file($_FILES['uf']['tmp_name'], $target_path))
?>
upload.php file is in the same folder wher my Photo directory is any help is much appriciated!
You need to add / after the
$target_path
$target_path = "/photo/";
Due to this, the variable $target_path is getting folder name prepending to the
file name uploaded.
You are creating a path like this:
/photoTheFileName.ext
There are two problems with this:
First, you don't have a / between the directory name and the file name.
When you fix that:
$target_path = "/photo/";
Then the path is the filesystem path, and it will be from the root of the file system.
You said:
upload.php file is in the same folder wher my Photo directory is
So you want the target path to be something like:
$target_path = "/hosts/www.example.com/htdocs/photo/";
… making the appropriate adjustments for your file system.
The error is on line 3, you are adding a slash before the directry name, it must be placed after the path name $target_path="photo/";
<?php
$vdo=$_FILES['uf']['name']; $target_path = "photo/";
$target_path = $target_path . basename( $_FILES['uf']['name']);
$target_path . basename( $_FILES['uf']['name']);
if(move_uploaded_file($_FILES['uf']['tmp_name'], $target_path))
?>
Related
I am using the code bellow to upload a file using php and inserting file name into database. Actually I want to rename of file on uploading and want to insert new renamed name into database. I know how to insert name into database but I don't know how to rename uploaded file name. Please help.
I am using code bellow:
$target = "uploads/";
$target = $target . basename( $_FILES['uploaded']['name']);
move_uploaded_file($_FILES['uploaded']['tmp_name'], $target);
$add_file = $_FILES['uploaded']['name'];
Thank you so much..
Is this what you are looking for?
<?php
rename("/tmp/uploaded_file.txt", "/home/user/login/uploaded/67A7466B576.txt");
?>
So new code will be:
$target = "uploads/";
$target = $target . basename( $_FILES['uploaded']['name']);
rename($_FILES['uploaded']['tmp_name'], $target);
$add_file_to_db = $target;
This might be helpful for you:
$uploaded_file = time()."__".$_FILES['uploaded']['name'];
This simply adds time before the name of the file.
Example:
If I uploaded the AnalysisReport.doc file, then it simply becomes like 1354173106__AnalysisReport.doc
I am trying to do a php upload that will upload into a specific folder.
One would choose the file they wish to upload next to a dropdown box which is a folder list. This is because it organises files.
<?php
session_start();
if(!isset($_SESSION["USER"]["Admin"])){
header("Location: index.html?unath");
}
$folder = mysql_real_escape_string($_POST['loc']);
$target_path = "../../shared/docs/$folder";
$upload2 = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $upload2)) {
echo "The file ". basename( $_FILES['uploadedfile']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
?>
Currently the code uploads the file into the "docs" folder and not docs/folder. Instead it puts the folder name in front of the file. For example- if the folder is called "abc" and my file is called robs.docx it will upload it to the main Docs folder and call it abcrobs.docx
You have a missing slash
Replace this line:
$upload2 = $target_path . basename( $_FILES['uploadedfile']['name']);
with:
$upload2 = $target_path ."/". basename( $_FILES['uploadedfile']['name']);
OR:
Replace this line:
$target_path = "../../shared/docs/$folder";
with:
$target_path = "../../shared/docs/".$folder."/";
You do not need mysql_real_escape_string because there's no SQL involved here.
If no database connection is established, mysql_real_escape_string returns null. So you're probably throwing away the $_POST['loc'] value.
You should never ever use user supplied values for manipulating anything on the filesystem without really, really thorough inspection of what you're going to manipulate. See Security threats with uploads.
Use var_dump liberally to see what your values look like at various stages and do some debugging.
You are missing a slash after $target_path
Add a / on the end of your $target_path:
$target_path = "../../shared/docs/$folder/";
You should properly escape your variables:
$target_path = "../../shared/docs/". $folder ."/";
I'm having an issue where the path of my file upload isn't being assigned to the correct folder. It actually amends the file path to the file name of the file being uploaded. Weird right? Here's the code I'm working on...
<?php
$allowed_filetypes = array('.mp4','.gif','.bmp','.png','.html','.psd','.zip','.xml','.css','.js',);
$max_filesize = 5904288;
$upload_path = 'video';
$filename = $_FILES['userfile']['name'];
$ext = substr($filename, strpos($filename,'.'), strlen($filename)-1);
if(!in_array($ext,$allowed_filetypes))
die('Sorry, cannot take files over blankKB.');
if(filesize($_FILES['userfile']['tmp_name']) > $max_filesize)
die('Sorry, cannot take files over blankKB.');
if(!is_writable($upload_path))
die('We are very sorry, a problem is occurring with the CHMOD of this directory');
if(move_uploaded_file($_FILES['userfile']['tmp_name'],$upload_path . $filename))
echo ' Your file was uploaded successfully, view it here';
else
echo 'Sorry, but there was an error during the file upload. Please try again.';
?>
Here's what the file looks like after being uploaded,
videoHello.png
plus it doesn't upload the file to the directory I want it in, located at /video
When you write $upload_path . $filename you are only concatenating the two strings, which does indeed result in videoHello.png;
You should either concatenate your system's directory separator (On Unix based systems it's /)
$upload_path . '/' . $filename
or build the separator into your string $upload_path
$upload_path = 'video/';
Though my final advice would be to use Absolute Paths like this:
$upload_path = dirname(__FILE__) . '/video/';
Hi am sorry but I have difficulties solving the problem. What i want to do is to upload file and then pass the directory but its nbot working the way I expect. The upload goes to a server to a file called 'uploads' but I cannot pass the directory , cuz its what I need, in later decode function:
Here's the code for uploading file am using:
<?php
// Where the file is going to be placed
$target_path = "uploads/";
/* Add the original filename to our target path.
Result is "uploads/filename.extension" */
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path))
{
echo "The file ". basename( $_FILES['uploadedfile']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
?>
and then I want to pass directory to here just after $json = $api->decode ( ):it shld be between the brackets I put ($target_path . basename( $_FILES['uploadedfile']['name'])) but its not working and I dont know how to solve it. The case decode is supposed to get directory of the file which was just uploaded and then decode what is inside:
case "decode":
$json = $api->decode ($target_path . basename( $_FILES['uploadedfile'] ['name']));
$start='{"content":"';
$pos_start = strpos($json, $start);
$end='"}';
$pos_end = strpos($json, $end);
thanx for any advice, please help me out if you know how, thanx
The way you build your JSON looks flawed. Typically it's best to accumulate the data first, and do a json_encode as the very last step. This way your JSON is never accidentally mangled. It may still not be semantically valid but at least you can see why ;)
$data = array(
"content" => $target_path . basename( $_FILES['uploadedfile']['name'])
);
return json_encode($data);
I hope this helps:
$json = $api->decode ($target_path . basename( $_FILES['uploadedfile'] ['name']));
$o=json_decode($json);
echo $o->content;
if that doesn't work try:
$json = $api->decode ($target_path);
$o=json_decode($json);
echo $o->content;
Since you are using $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); above.
Hi I have a file upload field with name="file1" and code in a phpmailer script:
if (isset($_FILES['file1']))
{
$file1_path = $_FILES['file1']['tmp_name'];
$file1_name = $_FILES['file1']['name'];
$file1_type = $_FILES['file1']['type'];
$file1_error = $_FILES['file1']['error'];
$mail->AddAttachment($file1_path);
}
And for some reason, it attached like php45we34 (each time diff, seems that its the temp name path, not the actual file)
Any help?
Strip spaces from your filename!
Blue hills.jpg should be Blue_hills.jpg
do
$fileName = str_replace(' ', '_', $fileName);
I suggest you to use function move_uploaded_file before adding attachment.
This is sample code that will move file from temporary location somewhere at your server
$target_path = "uploads/";
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['uploadedfile']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
After that AddAttachment should work fine.
$mail->AddAttachment(basename($target_path . $_FILES['uploadedfile']['name']));
What you see is what should happen. You do not specify the attachment name, so phpMailer uses the name of the temporary file it's attaching.
If you want the file to have a different name, you have to specify it. The accepted answer works because it goes the other way round -- it changes the file name so that the file has the desired name.
The usual way to proceed would be to issue
$mail->AddAttachment($file1_path, $_FILES['file1']['name']);
to override the attachment name.