breadcrumbs for multi-level url - php

I want to create multi-level breadcrumbs, like if user go to Home->Step1->step2->step3 page then goes to Step4 : i want to see my breadcrumbs Home:->step1->step2-step3->->step4.
Here is my code :
<?php
$path = parse_url($_SERVER['HTTP_REFERER'],PHP_URL_PATH);
$parts = explode('/',$path);
$stepname='Step'.$step->step_code;
if (count($parts) < 2)
{
echo("home");
}
else
{
for ($i = 2; $i < count($parts); $i++)
{
if (!strstr($parts[$i],"."))
{
echo("<a href=\"");
for ($j = 0; $j <= $i; $j++)
{
echo $parts[$j]."/";
};
echo("\">". str_replace('-', ' ', $parts[$i])."</a> » ");
}
};
};
?>
but its show only Home->step3>step4 ,its not show step2 and step3.
Actually I want multilevel breadcrumbs.


I recommend using Yii built in class CBreadcrumbs.
Besides that, you have logic error in your if statement. Home will show only if there are no other items.
Move if after echo home:
echo("home");
if (count($parts) > 2)
{
...


<?php
# Rewritten Ajmal PraveeN
$path = parse_url($_SERVER['HTTP_REFERER'],PHP_URL_PATH);
$parts = explode('/',$path);
$stepname='Step'.$step->step_code;
if (count($parts) < 2)
{
echo("home");
}
else
{
for ($i = 0; $i < count($parts); $i++)
{
if (!strstr($parts[$i],"."))
{
echo("<a href=\"");
for ($j = 0; $j <= $i; $j++)
{
echo $parts[$j]."/";
};
echo("\">". str_replace('-', ' ', $parts[$i])."</a> » ");
}
}
}
?>
The above code works fine with slash directories
ex: If php explodes a path is /home/website/public or Infinite path levels, the script generates what you are looking for ;)
Changes I made are $i = 2 to $i = 0
and A suggestion instead of str_replace use CSS styling for the »
Thank you..!

Related

how to display cycles in php added elements to each cycle in php?

I need your help to solve this problem, I am trying to write the necessary code so that the output is as follows:
PHP! PHP!! PHP!!! PHP!!!! PHP!!!!!
<?php
$y = ['!'];
for($i = 1; $i <= 5; $i++)
{
print "PHP!"."$y\t";
if($y+1 <5)
$y="!";
$y+'!';
}
?>
Until the second word, it adds one more exclamation point and in the rest of the repetitions it has the same number, that is two exclamation points.
How can I solve this problem?

Try this:
<?php
for ($i = 0; $i < 5; $i++) {
echo "PHP".str_repeat ("!", $i);
}
?>

You can try it:
<?php
for($i = 1; $i <= 5; $i++)
{
echo "PHP";
for($j = 1; $j <= $i; $j++){
echo "!";
}
}
?>
You can also use str_repeat():
<?php
for ($i = 1; $i <= 5; $i++) {
echo "PHP".str_repeat ("!", $i);
}
?>
Output will be: PHP!PHP!!PHP!!!PHP!!!!PHP!!!!!

Gaussian elimination has to give back multiple solutions php

I want to use gaussian elimination to solve the following matrix Matrix and this is the answer I'm expecting. I would like to get back an equation in the form as is displayed in answer but i can't figure out how to do it.
public function gauss($A, $x) {
# Just make a single matrix
for ($i=0; $i < count($A); $i++) {
$A[$i][] = $x[$i];
}
$n = count($A);
for ($i=0; $i < $n; $i++) {
# Search for maximum in this column
$maxEl = abs($A[$i][$i]);
$maxRow = $i;
for ($k=$i+1; $k < $n; $k++) {
if (abs($A[$k][$i]) > $maxEl) {
$maxEl = abs($A[$k][$i]);
$maxRow = $k;
}
}
# Swap maximum row with current row (column by column)
for ($k=$i; $k < $n+1; $k++) {
$tmp = $A[$maxRow][$k];
$A[$maxRow][$k] = $A[$i][$k];
$A[$i][$k] = $tmp;
}
# Make all rows below this one 0 in current column
for ($k=$i+1; $k < $n; $k++) {
$c = -$A[$k][$i]/$A[$i][$i];
for ($j=$i; $j < $n+1; $j++) {
if ($i==$j) {
$A[$k][$j] = 0;
} else {
$A[$k][$j] += $c * $A[$i][$j];
}
}
}
}
# Solve equation Ax=b for an upper triangular matrix $A
$x = array_fill(0, $n, 0);
for ($i=$n-1; $i > -1; $i--) {
$x[$i] = $A[$i][$n]/$A[$i][$i];
for ($k=$i-1; $k > -1; $k--) {
$A[$k][$n] -= $A[$k][$i] * $x[$i];
}
}
return $x;
}
I hope someone can help me to rewrite this code so it gives the solution i've provided or recommend a library which is capable of doing this.
I've searched for possible solutions on Google but haven't been able to find one yet.
Thanks in advance.

how to print this pattern in php?

I run this program, but I need the output within table. So would you please solve this?
<?php
$s="*";
for($b=1; $b<=5; $b++) {
for($c=5; $c>=$b-1; $c--) {
if($c>=$b) {
echo $s;
}
else if($b != 1) {
echo " ";
}
}
for($d=5; $d>=$b; $d--) {
echo $s;
}
echo "<br/>";
}
?>

If you're fine regardless of how the code was written (only results matter), you can use this:
print('<table>');
for ($i = 0; $i < 5; $i++)
{
print('<tr>');
for ($j = 1; $j <= 5; $j++)
{
print('<td>');
(5 - $i >= $j) ? print('*') : '';
print('</td>');
}
for ($j2 = 1; $j2 <= 5; $j2++)
{
print('<td>');
(1 + $i <= $j2) ? print('*') : '';
print('</td>');
}
print('</tr>');
}
print('</table>');
What I did there is I sliced table in half vertically and used 2 for loops to fill left and right halfs. You will get something like this:

incremented included php pages one by one

As you see I use this code to increment photos in a file, one by one :
<?php
for ($i = 1; $i <= $photonumber; $i++) {
if($i < 10){
echo '<div class="photos"><a target="_blank"><img src="../photosfile/' . $nom . '0' . $i . '.jpg"/></a></div>';
}
else
{
echo '<div class="photos"><a target="_blank"><img src="../photosfile/' . $nom . $i . '.jpg"/></a></div>';
}
}
?>
I would like to do the same but with php pages reading them from a specific directory like : ../phppages/
Any idea?
I tried but I missed something I guess and I would like to do it same way but with .php instead of .jpg.
Thank you very much.

Try this:
<?php
for ($i = $photonumber; $i >= 1; $i--) {
if($i < 10){
$i = "0".$i;
}
include("../phppages/page".$i.".php");
}
?>
Update: output by 3
<?php
$photonumber = 12;
for ($i = 0; $i < $photonumber; $i++) {
$j = $photonumber - $i;
if($j < 10){
$j = "0".$j;
}
if ($i % 3 === 0)
{
if ($i !== 0)
{
echo '</div>';
}
echo '<div>';
}
include("../phppages/page". $j.".php");
}
echo '</div>';
Update 2
To find the amount of files, that look like "page".$j.".php" in "../phppages" directory try this:
$files = glob("../phppages/page*.php");
$photonumber = count($files);

That would just be this:
for ($i = 1; $i <= $photonumber; $i++) {
include ('php-file-' . $i . '.php');
}

About having it 3 by 3, to be more precise, i want to create a fore each 3 .php file. Like
<?php
for ($i = 1; $i <= $photonumber; $i++) {
if($i < 10){
echo '<div>';
include("../phppages/page".$i.".php") x3;
echo '</div>';
}
?>
Then it become something like this :
div : 12.php + 11.php + 10.php , div : 09.php + 08.php + 07.php , div
:
06.php + 05.php + 04.php , div : 03.php + 02.php + 01.php

Hackerrank draw a staircase of length N in php

Draw a staircase of height N like this:
#
##
###
####
#####
######
Staircase of height 6, note the last line should have zero spaces.
My solution does not work correctly
function draw($size)
{
for ($i = 1; $i <=$size ; $i++)
{
$spaces = $size-$i;
while ($spaces)
{
echo " ";
$spaces--;
}
$stairs = 0;
while ($stairs < $i)
{
echo "#";
$stairs++;
}
echo "<br/>";
}
}
draw(6);
//output
#
##
###
####
#####
######
It is not printing the spaces, I tried \n, PHP.EOL still it didn't work. Any suggestions?

Although other solutions are all good , here is my code as well.
$max=5;
for ( $i =1 ; $i<=$max;$i++) {
for ( $space = 1; $space <= ($max-$i);$space++) {
echo " ";
}
for ( $hash = 1; $hash <= $i;$hash ++ ) {
echo "#";
}
echo "\n";
}

//PHP
$n = 6; // Number of rows.
for($i=1;$i<=$n;$i++){
echo str_repeat(' ', $n-$i) . str_repeat('#', $i);
echo '\n';
}

for(var i = 0; i < n; i++)
{
var s = "";
for(var j = 0; j < n; j++)
{
if(n - i - 2 < j)
{
s += "#";
}
else
{
s += " ";
}
}
console.log(s);
}

for ($i=0; $i<$n; $i++){
for ($j=0; $j<$n; $j++){
if($i+$j>$n-2){
echo "#";
} else {
echo " ";
}
if($j==$n-1 && $i+$j<$n*2-2){ //The second part is to dont break the last line
echo "\n";
}
}
}

Here's another solution:
$int = 7;
for($i = 1; $i<=$int; $i++){
printf('%1$s%2$s%3$s',str_repeat(" ",$int-$i),str_repeat("#",$i),"\n");
}
From official PHP documentation:
str_repeat

$n = 6;
for ($i = 0; $i < $n; $i++) {
$pad = 1;
for ($space = 0; $space < $n-$i-1; $space++) {
$pad++;
}
echo str_pad('#', $pad,' ',STR_PAD_LEFT);
for ($j = 0; $j < $i; $j++) {
echo '#';
}
echo '<br>';
}

Took me a while but finally I manage to do it following OFC (A. Sharma) Example.
<?php
$handle = fopen("php://stdin","r");
$n = intval(fgets($handle));
for ($rows = 0; $rows < $n; $rows++) {
for ($columns = 0; $columns < $n - $rows - 1; $columns++) {
echo " ";
}
for ($columns = 0; $columns < $rows + 1; $columns++) {
echo "#";
}
echo "\n";
}
?>

Use PHP functions range() and str_repeat() for an elegant solution:
function staircase($n){
foreach (range(1, $n) as $i)
print( str_repeat(' ',$n-$i).str_repeat('#',$i)."\n");
}
demo

Check if n is between 0 and 101 ( 0 < n <= 100)
Loop through each row
2.1 print spaces according to the last item position
2.2 print the items
Separate rows
The code below explains everything...
function staircase($n) {
// check if n is between 0 and 101 (0 < n <=100)
if( 0 < $n && $n > 100 ) {
} else {
// Loop through each row
for($i = 1; $i <= $n; $i++) {
// print spaces according to the last item position
$si = 1;
while( $si <= ($n - $i)){
print(" ");
$si++;
}
// print the items
for($j = 1; $j <= $i; $j++) {
print("#");
}
// separate rows
print("\n");
}
}
}
Output: For n = 6
#
##
###
####
#####
######

After playing around with the code and trying/failing couple of times I finally got it right. Notice how in order to print the space and new line I am using "\n". Previous "<br/>" and " " for space didn't work.
Break line will come out of the loop every row number. So if we have $n=4 then every 4 spaces after break line will be echoed.
I have made 2 loops to fill in all fields in the staircase.
The tricky part here is to have them right aligned. This is where if statement comes in place.
Reference link:
Hackerrank Challenge
// Complete the staircase function below.
function staircase($n) {
for($i=1; $i<=$n; $i++){
for($j=1; $j <= $n; $j++){
if( ($n - $i) < $j ){
echo "#";
}else{
echo " ";
}
}
echo "\n";
}
}

Try This
$n=6;
for($i=1;$i<=$n;$i++){
for($spaces=1;$spaces<=($n-$i);$spaces++){
echo " ";
}
for($staires=0;$staires<$i;$staires++){
echo "#";
}
echo "\n";
}

This worked for me
$n = 6;
function staircase($n) {
for($i=1; $i <= $n; $i++){
for($j=1; $j <= $n; $j++){
if($j > $n-$i){
echo "#";
}else{
echo " ";
}
}
echo "\n";
}
}

Use print(' '), if you want to go to next line put print(' ')."\n"

JavaScript:
Solution:
function StairCase(n){
let x = [];
for(let i = 0; i<n; i++){
while(x.length < n){
x.push(" ");
}
x.shift();
x.push("#");
console.log(x.join(''));
} } //StairCase(6)

Categories