How to display an option from a selectbox? - php

Question

I'm trying to create a table that shows the time and the task a user has to do.
All this is saved in a database. For each row and column there is a selectbox(Usernames) and an <input>(for comments).
Here is a screenshot: http://snag.gy/NYwsJ.jpg
The name of each selectbox is the id of the time and task
echo "<select name='" . $x['idTask'] . "-" . $y['idTime'] . "'>
(e.g: name="1_23")
The problem is when I load the page it is supposed to display all the records that are already saved in the database.
For the <select> I tried using this an if:
if ($x["fiUser"] == $z["idUser"]){echo "selected";}
And here is the table:
<?php
echo"<div class='dv_Table'><table><tr><th></th>";
foreach (SelectTime() as $r) {
echo "<th>" . $r['dtTime'] . "</th>";
}
echo "</tr>";
echo "<form method='post'>";
$userselect = "";
foreach (SelectCalTask() as $x) {
echo "<tr><td>" . $x['dtTask'] . "</td>";
foreach (SelectTime() as $y) {
echo "<td>";
echo "<select name='" . $x['idTask'] . "-" . $y['idTime'] . "'>
<option value='0'> -- None -- </option> ";
foreach (SelectUser_Name() as $z) {
echo "<option value='" . $z["idUser"] . "'";
if ($x["fiUser"] == $z["idUser"]) {
echo "selected";
} echo" >" . $z["dtFirstName"] . " " . $z["dtLastName"] . "</option> ";
}
echo " </select>
<input type='text' name='" . $x['idTask'] . "_" . $y['idTime'] . "' value='" . "_" . $y['idTime'] . "'></td>";
}
echo "</tr>";
}
echo "</table></div>";
echo "<input type='submit' name='updateCalendar' value='Update'></form>";
?>
Better, would be if could send an Update query right after the "onchange" or right after finishing the comment in the input.
Is that possible ?
Thank you in advance

Answer 1

*
Better, would be if could send an Update query right after the
"onchange" or right after finishing the comment in the input. Is that
possible ?
*
Why not?
$('.yourValue').on('change', function (e) {
$.ajax({
type: "POST",
url: "/path-to-update-query",
success: function (data) {
}
});
});