Render form within html table - php

Question

I'm trying to render an html form within a table. The problem is I load the page with AJAX and after that the button stops working (due to the tr and td placement).
Is there any way to manage this with html, javascript, php, or css?
This is what I'm trying to accomplish:
echo "<tr id=\"$I_ID\" class=\"toggleEdit\">";
echo "<form class=\"editRow\" name=\"editRow\" action=\"\" method=\"POST\">";
echo "<input type=\"hidden\" name=\"edit\">";
echo "<input type=\"hidden\" name=\"$thatTable\">";
echo "<input type=\"hidden\" value=\"$I_ID\" name=\"I_ID\">";
echo "<input type=\"hidden\" value=\"$row[1]\" name=\"$columns[1]\">";
echo "<td>$row[1]</td>";
for ($pointer = 2 ; $pointer < $countRows ; ++$pointer) {
echo "<td><input type=\"text\" value=\"$row[$pointer]\" name=\"$columns[$pointer]\"></td>";
}
echo "<td><input type=\"submit\" id=\"submitEdit\" value=\"submit edit\"></td>";
echo "</form>";
echo "</tr>";
And this is what works:
echo "<tr id=\"$I_ID\" class=\"toggleEdit\">";
echo "<td id=\"tdEditRow\">";
echo "<form class=\"editRow\" name=\"editRow\" action=\"\" method=\"POST\">";
echo "<input type=\"hidden\" name=\"edit\">";
echo "<input type=\"hidden\" name=\"$thatTable\">";
echo "<input type=\"hidden\" value=\"$I_ID\" name=\"I_ID\">";
echo "<input type=\"hidden\" value=\"$row[1]\" name=\"$columns[1]\">";
echo "$row[1]";
for ($pointer = 2 ; $pointer < $countRows ; ++$pointer) {
echo "<input type=\"text\" value=\"$row[$pointer]\" name=\"$columns[$pointer]\">";
}
echo "<input type=\"submit\" id=\"submitEdit\" value=\"submit edit\">";
echo "</form>";
echo "</td>";
echo "</tr>";