So I have a pretty large dump file that I have to extract specific content from it.
The file has record each containing specific numbers enclosed by ". Bellow is a sample part of the file:
Ali Rabi (CustomerId=["3453456"]) // need to get: 3453456
Mohammad Reza Saberi (CustomerId=["12328"]) // need to get: 12328
Currently I read line by line and get the IDs as bellow. the code works fine and I get the result I want:
$cid = substr($row, strpos($row, '[') +2, strpos($row, ']')-strpos($row, '[')-2);
echo $cid;
But doesn't PHP have a function for this? getting the string enclosed by some delimiters?
If all your records look like the ones you've mentioned, I think it's the perfect place where you could use regular expressions.
Regular Expressions help you to create and find patterns in a given String.
For your case, you could probably use :
if (preg_match("/[0-9]+/", "Ali Rabi (CustomerId=[\"3453456\"])", $matches)) {
echo "Match was found <br />";
echo $matches[0];
}
The preg_match() function helps you to find the matches. The first param for this function is the pattern you're looking for. In your case you're looking for a set of continuous digits each of which can range from 0-9.
So, for a single digit we use [0-9]. Adding a + after [0-9] means that there needs to be atleast one digit in the match. Hence, [0-9]+ as the regular expression.
Read more about regular expressions in php : http://webcheatsheet.com/php/regular_expressions.php
Try:
<?php preg_match_all("/([1-9]+)/",$yourtext, $result, PREG_PATTERN_ORDER); ?>
$result contains all Matches.
Further Infomartion: http://php.net/manual/de/function.preg-match-all.php
I think you can use str_replace to remove the "
$cid = str_replace('"','',$row);
Related
I cant remember what to use to return only a specific part of a string.
I have a string like this:-
$str = "return(me or not?)";
I want to get the word which is after (. In this example me will be my result. How can I do this?
I dont think substr is what I am looking for. as substr returns value based on the index you provided. which in this case i dont know the index, it can vary. All I know is that I want to return whatever is after "(" and before the space " ". The index positions will always be different there for i cant use substr(..).
This regular expression should do the trick. Since you didn't provide general rules but only an example it might need further changes though.
preg_match('/\((\S+)/', $input, $matches);
$matches[1] contains "me" then.
<?php
// Your input string
$string = "return(me or not?)";
// Pattern explanation:
// \( -- Match opening parentheses
// ([^\s]+) -- Capture at least one character that is not whitespace.
if (preg_match('/\(([^\s]+)/', $string, $matches) === 1)
// preg_match() returns 1 on success.
echo "Substring: {$matches[1]}";
else
// No match found, or bad regular expression.
echo 'No match found';
Result of capture group will be your result using this regex and preg_match().
$regex = '/\((\w+)/';
Check preg_match() for the working reference.
I have a string that contains something like "LAB_FF, LAB_FF12" and I'm trying to use preg_replace to look for both patterns and replace them with different strings using a pattern match of;
/LAB_[0-9A-F]{2}|LAB_[0-9A-F]{4}/
So input would be
LAB_FF, LAB_FF12
and the output would need to be
DAB_FF, HAD_FF12
Problem is, for the second string, it interprets it as "LAB_FF" instead of "LAB_FF12" and so the output is
DAB_FF, DAB_FF
I've tried splitting the input line out using 2 different preg_match statements, the first looking for the {2} pattern and the second looking for the {4} pattern. This sort of works in that I can get the correct output into 2 separate strings but then can't combine the two strings to give the single amended output.
\b is word boundary. Meaning it will look at where the word ends and not only pattern match.
https://regex101.com/r/upY0gn/1
$pattern = "/\bLAB_[0-9A-F]{2}\b|\bLAB_[0-9A-F]{4}\b/";
Seeing the comment on the other answer about how to replace the string.
This is one way.
The pattern will create empty entries in the output array for each pattern that fails.
In this case one (the first).
Then it's just a matter of substr.
$re = '/(\bLAB_[0-9A-F]{2}\b)|(\bLAB_[0-9A-F]{4}\b)/';
$str = 'LAB_FF12';
preg_match($re, $str, $matches);
var_dump($matches);
$substitutes = ["", "DAB", "HAD"];
For($i=1; $i<count($matches); $i++){
If($matches[$i] != ""){
$result = $substitutes[$i] . substr($matches[$i],3);
Break;
}
}
Echo $result;
https://3v4l.org/gRvHv
You can specify exact amounts in one set of curly braces, e.g. `{2,4}.
Just tested this and seems to work:
/LAB_[0-9A-F]{2,4}/
LAB_FF, LAB_FFF, LAB_FFFF
EDIT: My mistake, that actually matches between 2 and 4. If you change the order of your selections it matches the first it comes to, e.g.
/LAB_([0-9A-F]{4}|[0-9A-F]{2})/
LAB_FF, LAB_FFFF
EDIT2: The following will match LAB_even_amount_of_characters:
/LAB_([0-9A-F]{2})+/
LAB_FF, LAB_FFFF, LAB_FFFFFF...
I try to make system that can detect date in some string, here is the code :
$string = "02/04/16 10:08:42";
$pattern = "/\<(0?[1-9]|[12][0-9]|3[01])\/\.- \/\.- \d{2}\>/";
$found = preg_match($pattern, $string);
if ($found) {
echo ('The pattern matches the string');
} else {
echo ('No match');
}
The result i found is "No Match", i don't think that i used correct regex for the pattern. Can somebody tell me what i must to do to fix this code
First of all, remove all gibberish from the pattern. This is the part you'll need to work on:
(/0?[1-9]|[12][0-9]|3[01]/)
(As you said, you need the date only, not the datetime).
The main problem with the pattern, that you are using the logical OR operators (|) at the delimiters. If the delimiters are slashes, then you need to replace the tube characters with escaped slashes (/). Note that you need to escape them, because the parser will not take them as control characters. Like this: \/.
Now, you need to solve some logical tasks here, to match the numbers correctly and you're good to go.
(I'm not gonna solve the homework for you :) )
These articles will help you to solve the problem tough:
Character classes
Repetition opetors
Special characters
Pipe character (alternation operator)
Good luck!
In your comment you say you are looking for yyyy, but the example says yy.
I made a code for yy because that is what you gave us, you can easily change the 2 to a 4 and it's for yyyy.
preg_match("/((0|1|2|3)[0-9])\/\d{2}\/\d{2}/", $string, $output_array);
Echo $output_array[1]; // date
Edit:
If you use this pattern it will match the time too, thus make it harder to match wrong.
((0|1|2|3)[0-9])/\d{2}/\d{2}\s+\d{2}:\d{2}:\d{2}
http://www.phpliveregex.com/p/fjP
Edit2:
Also, you can skip one line of code.
You first preg_match to $found and then do an if $found.
This works too:
If(preg_match($pattern, $string, $found))}{
Echo $found[1];
}Else{
Echo "nothing found";
}
With pattern and string as refered to above.
As you can see the found variable is in the preg_match as the output, thus if there is a match the if will be true.
I'm trying to retrieve the followed by count on my instagram page. I can't seem to get the Regex right and would very much appreciate some help.
Here's what I'm looking for:
y":{"count":
That's the beginning of the string, and I want the 4 numbers after that.
$string = preg_replace("{y"\"count":([0-9]+)\}","",$code);
Someone suggested this ^ but I can't get the formatting right...
You haven't posted your strings so it is a guess to what the regex should be... so I'll answer on why your codes fail.
preg_replace('"followed_by":{"count":\d')
This is very far from the correct preg_replace usage. You need to give it the replacement string and the string to search on. See http://php.net/manual/en/function.preg-replace.php
Your second usage:
$string = preg_replace(/^y":{"count[0-9]/","",$code);
Is closer but preg_replace is global so this is searching your whole file (or it would if not for the anchor) and will replace the found value with nothing. What your really want (I think) is to use preg_match.
$string = preg_match('/y":\{"count(\d{4})/"', $code, $match);
$counted = $match[1];
This presumes your regex was kind of correct already.
Per your update:
Demo: https://regex101.com/r/aR2iU2/1
$code = 'y":{"count:1234';
$string = preg_match('/y":\{"count:(\d{4})/', $code, $match);
$counted = $match[1];
echo $counted;
PHP Demo: https://eval.in/489436
I removed the ^ which requires the regex starts at the start of your string, escaped the { and made the\d be 4 characters long. The () is a capture group and stores whatever is found inside of it, in this case the 4 numbers.
Also if this isn't just for learning you should be prepared for this to stop working at some point as the service provider may change the format. The API is a safer route to go.
This regexp should capture value you're looking for in the first group:
\{"count":([0-9]+)\}
Use it with preg_match_all function to easily capture what you want into array (you're using preg_replace which isn't for retrieving data but for... well replacing it).
Your regexp isn't working because you didn't escaped curly brackets. And also you didn't put count quantifier (plus sign in my example) so it would only capture first digit anyway.
I am having the dang-est time trying to write a regex that will extract the phone extension from a full phone number string. This should work on a number like this one: 777.777.7777 x 7302
It should also work using "ext", "EXT", "Ext", "eXt", "ext.", and "Ext ". Essentially just cover all the common ground use of it.
I just need the "x 7302" part. In fact I am just going to strip it down to just the extension number once I extract it.
Can anyone help me please? Regular expressions are something that I struggle with when they get more complex.
I am doing this in a PHP function (preg_match) if that will help anyone.
This probably helps to give you something to play with:
$phonenumber = '777.777.7777 x 7302';
$extension = preg_replace('(^.*(ext|x) ?([0-9]+)$)i', '$2', $phonenumber);
echo $extension;
Use the i modifier (at the end) to make the regex case insensitive so to match all combinations of ext. I used a group to offer both variant: ext or x: (ext|x).
The rest is looking for a number at the end, and a space is possible between EXT and the number.
try with regex:
/e?xt?\.?\s*\d+$/i
<?
echo "<pre>";
$phone = '777.777.7777 x 7302';
preg_match("/e?xt?\.?\s*\d+$/i", $phone, $matched);
print_r($matched);
?>
Output:
Array
(
[0] => x 7302
)
\w+\s*\d+$
It is an simpler regex assuming that the input is similar to what you have provided.
This should do it for you
/([\d\-\.]+)([ext\. ]+)(\d+)/i
The first set matches the numbers separated by dash or dot. The second set matches your extension string and the third set matches your extension number.
If you just want the last numbers of the string, you can use:
\D+(\d+)$
\D+ at least one non-digit followed by:
(\d+) at least one digit (captured using parenthesis)
$ at the end of the string.
I am a bit leery of regular expression, so I'm a bit biased when I say, is it possible to just split the string using the PHP function "explode()", using the 'x' character as your delimiter?
Here is a link to the PHP manual for that function if you are not familiar with it:
Explode()
Try this function:
$pn = "777.777.7777 x 7302";
function get_ext($pn)
{
$ext = preg_replace('/[\d\.\s]+[ext\s]+(\d{1,})/i', '$1', $pn);
return $ext;
}
echo get_ext($pn);
//7302