I'm having trouble using PHP to execute a casperjs script:
<?php
putenv("PHANTOMJS_EXECUTABLE=/usr/local/bin/phantomjs");
var_dump(exec("echo \$PATH"));
exec("/usr/local/bin/casperjs hello.js website.com 2>&1",$output);
var_dump($output);
Which results in the following output:
string(43) "/usr/gnu/bin:/usr/local/bin:/bin:/usr/bin:."
array(1) {
[0]=>
string(36) "env: node: No such file or directory"
}
The only stackoverflow posts I could find hinted that there's a problem with my paths, and that maybe the PHP user can't access what it needs.
I have also tried the following: sudo ln -s /usr/bin/nodejs /usr/bin/node
Does anyone know what I would need to do or change for this error to resolve?
Thanks
My guess is you have something, somewhere, that assumes node is installed.
First, are you running php from the commandline? I.e. as php test.php in a bash shell. If so, you can run the commands, below, as they are. If through a web server the environment can be different. I'd start with making a phpinfo(); script, and then run the troubleshooting commands through shell_exec() commands. But, as that is a pain, I'd get it working from the commandline first, and only mess around with this if the behaviour is different when run through a web server. (BTW, if you are running from a cron job, again, the environment can be slightly different. But only worry about this if it works from commandline but does not work from cron.)
Troubleshoot hello.js
The easy one. Make sure your script does not refer to node anywhere. Also remember you cannot use node modules. So look for require() commands that should not be there.
Troubleshoot your bash shell
Run printenv | grep -i node to see if anything is there. But when PHP runs a shell command, some other files get run too. So check what is in /etc/profile and ~/.bash_profile . Also check /etc/profile.d/, /etc/bashrc and ~/.bashrc. You're basically looking for anything that mentions node.
Troubleshoot phantomjs/casperjs
How did you install phantomjs and casperjs? Are the actual binaries under /usr/local/bin, or symlinks, or are they bash scripts to the . E.g. on my machine:
cd /usr/local/bin
ls -l casperjs phantomjs
gives:
lrwxrwxrwx 1 darren darren 36 Apr 29 2014 casperjs -> /usr/local/src/casperjs/bin/casperjs
lrwxrwxrwx 1 darren darren 57 Apr 29 2014 phantomjs -> /usr/local/src/phantomjs-1.9.7-linux-x86_64/bin/phantomjs
And then to check each file:
head /usr/local/src/casperjs/bin/casperjs
head /usr/local/src/phantomjs-1.9.7-linux-x86_64/bin/phantomjs
The first tells me casper is actually a python script #!/usr/bin/env python, while the second fills the screen with junk, telling me it is a binary executable.
Related
I've been unable to run php scripts that I need to use to start and stop webcam services that run on the local machine with the scripts. I can find nothing in the logs to indicate why the script doesn't' work.
I confess to being severely handicapped regarding PHP, especially server-side scripting.
The environment is Debian Jesse running Nginx with all required SSH and PHP modules installed
I have added www-data to the sudoers file with:
www-data ALL=(ALL) NOPASSWD: /var/www/html/start_webcam.sh
Enabled the $PATH environment for www-data at:
/etc/php5/fpm/pool.d/www.conf
The shell script resides in the .../html directory and runs from the terminal with no issues.
This is the code for both the php and shell scripts:
start_webcam.php:
<?php
echo exec('sudo bash /var/www/html/aspirebox/start_webcam.sh 2>&1, $output');
print_r($output);
?>
The $output and print_r stuff is there because it was the last thing I tried based on a post I found out here somewhere.
start_webcam.sh
#!/bin/bash
service motion start
Thanks in advance to anyone out here that has a clue. After 2 days of wrestling with this, I am sure that I do not.
according to Passing Variables to shell_exec()? you should change your code like this:
<?php
$output = exec('/var/www/html/aspirebox/start_webcam.sh 2>&1 ');
print_r($output);
?>
and let your bash script execute as all (no need to sudo bash):
chmod a+x /var/www/html/aspirebox/start_webcam.sh
Thank you very much - that worked.
I worked through getting the path straight for the directory the shell script runs in, and the correct path to run "service".
All I have now is to figure out why I'm getting "Failed to start motion.service: Access denied"
I've given www-data permission to run the script without a password on sudoers, have to keep digging.
Thanks again!
I tried this function from php with :
exec("gcc testC.c -o runner.out 2>&1",$output,$status);
but when I print $output I get this error :(:
gcc: error trying to exec 'cc1': execvp: No such file or directory\n
If I run
exec("/usr/bin/gcc testing/pruebaC.c -o testing/frommm.out 2>&1",$output,$status);
I get that
collect2: fatal error: cannot find 'ld'\n
My user :
groups vagrant
vagrant : vagrant root adm cdrom sudo dip www-data plugdev lpadmin sambashare
My gcc directory
/usr/bin$ ls -l gcc
lrwxrwxrwx 1 root vagrant 7 Apr 7 2014 gcc -> gcc-4.8
If I run from terminal all work, I can compile and execute but from PHP I cant :(
I'm not sure what happened in the comments, but I've figured out the root of the problem and I'm answering this just to clarify for any future readers.
#zneak is right. If you try and echo $_ENV["PATH"] and receive nothing in response, this means that PHP is executing gcc and any other executables without looking for them in a PATH variable. As a result, it sometimes can't find any of them. #Marco interpreted as echoing the PATH variable in bash, and executed echo $PATH instead. However, these two variables are separate, and often the PHP PATH is unset while the bash PATH is.
In order to fix this issue, you'll have to define PATH for PHP in its environment variables. If you're unsure what to put, refer to the PATH variable defined in bash. For example, my current Laravel project has the line
PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin
at the bottom of it's .env file, and now executing just gcc (without giving the full path /usr/bin/gcc) works correctly.
I've looked at how composer is set up to run a php script by calling composer without issuing php manually and I tried to do this myself but it isn't working. I know this is probably asked before but I can't formulate a question to find it.
I have my file
#!/usr/bin/php
<?php
echo 'teststring' . PHP_EOL;
when I issue test in the directory the file is located I get nothing, but if I do php test then I get "teststring" echoed out. The question is - how do I set it up so that I can execute the file directly?
I have given x permissions on the file.
Here is a sample output:
x#y:~/www/html/dev/Project$ ls
...
-rwxrwxr-x 1 www-data www-data 53 сеп 22 12:34 test
...
x#y:~/www/html/dev/Project$ test
x#y:~/www/html/dev/Project$ php test
teststring
x#y:~/www/html/dev/Project$ which php
/usr/bin/php
x#y:~/www/html/dev/Project$
You should try to locate php executable by using which instead of whereis like so
$ which php
... this command only searches for executables, while whereis tries to guess useful links, you can read more [here] (https://superuser.com/questions/40301/which-whereis-differences)
Then just run it like so
$ ./teststring
You can read more about executing shell scripts here
thegeekstuff
tldp.org
I'm trying to execute a command through PHP with shell_exec. The PHP file is hosted by Apache on my Ubuntu server.
When I run this:
echo shell_exec("ps ax | grep nginx");
Then I get to see data. But when I run another command, for example:
echo shell_exec("cat /usr/local/nginx/config/nginx.config");
Then it's not showing anything at all. But when I copy that command and paste it in my terminal, then it executes fine.
My Apache server is running as user www-data. So I edited sudoers and added this line:
www-data ALL=(ALL:ALL) ALL
I know this is a security risk, but I wanted to make sure (for now) that www-data is able to execute all commands. But, for some reason I'm still not able to execute all commands with my PHP script.
Anyone any idea what to do?
have you read http://php.net/manual/en/function.shell-exec.php
There is quite a discussion in comments section. Top comment is:
If you're trying to run a command such as "gunzip -t" in shell_exec and getting an empty result, you might need to add 2>&1 to the end of the command, eg:
Won't always work:
echo shell_exec("gunzip -c -t $path_to_backup_file");
Should work:
echo shell_exec("gunzip -c -t $path_to_backup_file 2>&1");
In the above example, a line break at the beginning of the gunzip output seemed to prevent shell_exec printing anything else. Hope this saves someone else an hour or two.
echo shell_exec("sudo cat /usr/local/nginx/config/nginx.config");
Try that.
I actually try to laucnh a gnome-term with a php script, seems i have some problems with the users www-data;
my script make only a ls -l command in a directory (is just for a test) and i run it with a php page in my local-web site.
here the gnome-terminal command in my bash script (he run perfectly when i double-click on him) :
gnome-terminal --working-directory=/opt/cuckoo -x bash -c "ls -l"
and here is the call on the php-page :
system("/my/path/to/the/script/script.sh");
i have some echo in my script and i see them in the php page after i try to run the script with the php.page.
i think www-data don't have the right to do so i give the ownership of the script with the chown command, and at last a try the sudo visudo command and make the script execute like the user www-data is root (with NO PASSWD arg)
But i can't open the terminal and make a ls at last, i try with exec too, and show the result with $ouput butthe result is the same as well.
At last my question is : Php can really run a terminal or maybe a fool myself^^? Thanks for taking time to rescure me ;)
PHP can run everything, but depends who spawns it. Forget just running X apps from a web server - you'll need more than just executing them (permissions, DISPLAY and Xauth settings). Read more about the X clients and architecture.
Probably the right place to ask this is at SuperUser, since the problem is not in the coding itself.