SELECT saleamount/(SELECT SUM(saleamount)
from user_pr where user_id=49) *100 as totalPercentage
from user_pr where user_id=49
i also want to join
select users.firstname from users where type=1
how can i combine both in one query
Take the two table names, put JOIN between then and ON and join condition after the second one.
SELECT saleamount/(SELECT SUM(saleamount)
from user_pr where user_id=49) *100 as totalPercentage,
users.firstname
from user_pr JOIN users ON user_pr.user_id = users.user_id
where user_pr.user_id = 49
and users.type = 1
Related
I am trying to execute two COUNT statements across 3 joins. The first Count shows the correct number but the second one seems to multiply the counts together for some reason? I checked the link which was marked as duplicate but that example doesn't have any JOINS in it.
SELECT
COUNT(DISTINCT `outlet_id`) AS `outlets`,
`prod_name`,
COUNT(`purchased`) AS `vouchersleft`
FROM
`prod_outlets` AS `po`
INNER JOIN `bb_products` AS `bbp` ON po.`product_id` = bbp.`prod_id`
INNER JOIN `vouchers` AS `v` ON v.`product_id` = bbp.`prod_id`
GROUP BY
bbp.`prod_id`;
What it should display is 3 branches and 5 vouchers. But it is outputting 3 branches and 15 vouchers. So, the second COUNT is multiplying by the first i.e.: 3 x 5 = 15
From the description what i understood is you are getting cross product that is why you are getting wrong number for vouchersleft, what i suggest you to calculate your count in a sun clause and then join this clause with your main query like
SELECT
COUNT(DISTINCT `outlet_id`) AS `outlets`,
`prod_name`,
v.vouchersleft
FROM
`prod_outlets` AS `po`
INNER JOIN `bb_products` AS `bbp` ON po.`product_id` = bbp.`prod_id`
INNER JOIN (
SELECT product_id, COUNT(*) vouchersleft
FROM vouchers
GROUP BY product_id
) AS `v` ON v.`product_id` = bbp.`prod_id`
GROUP BY
bbp.`prod_id`;
"SELECT COUNT(DISTINCT `outlet_id`) as `outlets`,
`prod_name`,
COUNT(distinct `purchased`) as `vouchersleft`
FROM `prod_outlets` as `po`
INNER JOIN `bb_products` as `bbp`
ON po.`product_id` = bbp.`prod_id`
INNER JOIN `vouchers` as `v`
ON v.`product_id` = bbp.`prod_id`
GROUP BY bbp.`prod_id`";
I have fours tables and I wanted to join all three tables with the one table.
I have listed my problem as follows:
Tables:
users
user_training
user_courses
user_certificates
I wanted to get the data from [2,3,4] tables that user_id field matches with the users table ID field.
When I try the INNER JOIN it gives me the result for users that are common in all the tables, But I just wanted to check the [2,3,4] tables with the table [1] Records.
My Query...
SELECT A.training_name AS 'training_name', C.course_name AS 'course_name', D.certificate_name AS 'certificate_name'
FROM user_training AS A INNER JOIN users AS B ON A.user_id=B.ID INNER JOIN user_courses AS C ON B.ID = C.user_id INNER JOIN user_certificates AS D ON B.ID = D.user_id;
Thanks in Advance.
use left join
select u.* from users u
left join user_training ut on ut.user_id=u.user_id
left join user_courses uc on uc.user_id=u.user_id
left join user_certificates uct on uct.user_id=u.user_id
With this one you are getting all users and their respective trainings:
SELECT *
FROM `users`
LEFT JOIN `user_training` ON `users`.`id` = `user_training`.`user_id`
Changing *_trainig to *_courses or *_certificates will return all users with respected courses or certificates.
If you need to get data in one query, try this one:
SELECT *
FROM `users`
LEFT JOIN `user_training` ON `users`.`id` = `user_training`.`user_id`
LEFT JOIN `user_courses` ON `users`.`id` = `user_courses`.`user_id`
LEFT JOIN `user_certificates` ON `users`.`id` = `user_certificates`.`user_id`
If user has no trainings, courses, certificates all remaining fields will be null-ed.
I have 4 tables called shops, users, review and rating.
I want to get all reviews for the corresponding shop with reviewed user details and also overall rating for that shop.
I have done almost with the single query. But the problem is if the shop has same rating for multiple times by same user its consider as single rating. But that rating count was correct.
i.e
from this table user_id 3 was rated shop_id 1 as 4 times. So the count is 4 and total_rating is 17.
My query is
select review.comments, users.username, count(distinct rating.id) as rating_count,
sum(distinct rating.rating) as total_rating from users
left join review on users.id = review.user_id and review.shop_id='1'
left join rating on users.id = rating.user_id and rating.shop_id='1'
where review.shop_id='1' or rating.shop_id='1'
group by users.id, review.user_id, rating.user_id, review.id
When I run this query I got
But I need total_rating 17 for user_id 3..
Check this fiddle
You put DISTINCT IN sum( rating.rating) as total_rating, thats why the result(12=17-5), since it will include 5 only once while computing sum.
select review.comments, review.user_id, count(distinct rating.id) as rating_count,
sum( rating.rating) as total_rating from users
left join review on users.id = review.user_id and review.shop_id='1'
left join rating on users.id = rating.user_id and rating.shop_id='1'
where review.shop_id='1' or rating.shop_id='1'
group by users.id, review.user_id, rating.user_id, review.id
Here is SQLFiddle
Sample Output :
Hope this helps
Try this - Remove the distinct from sum(rating.rating). Since you gave sum(distinct rating.rating), it is ignoring one 5 that user 3 gave to store 1.
select review.comments, users.username, count(distinct rating.id) as rating_count,
sum(rating.rating) as total_rating from users
left join review on users.id = review.user_id and review.shop_id='1'
left join rating on users.id = rating.user_id and rating.shop_id='1'
where review.shop_id='1' or rating.shop_id='1'
group by users.id, review.user_id, rating.user_id, review.id
First of all: It makes no sense to outer-join records from a table and then remove them in the WHERE clause. With left join review ... you say: find a matching record in table review, and if you don't find any, then add nulls, so we keep the users record. Then with where review.shop_id='1' you say: keep only records where you actually found a record in review. So you are dismissing the records that you just took the pain to keep. Your WHERE clause renders your LEFT OUTER JOINS mere INNER JOINS.
As to your actual problem: That stems from joining all tables first and only then trying to get aggregates from the resulting records. Aggregate before joining instead:
select
rev.comments,
usr.username,
coalesce(rat.rating_count, 0) as rating_count,
rat.total_rating
from review rev
join users usr on users.id = review.user_id
left join
(
select user_id, shop_id, count(*) as rating_count, sum(rating) as total_rating
from rating
group by user_id, shop_id
) rat on rat.user_id = usr.id and rat.shop_id = rev.shop_id
where rev.shop_id = 1
group by rev.id;
I have the following table structure:
- table users -
user_id
user_name
- table groups -
group_id
group_name
- table group_members -
group_id
user_id
Let's also say I have this in the DB:
users:
1:administrator
groups:
1:administrators
2:superusers
3:normal users
group_members:
1:1 (user_id 1 is member of group_id 1)
1:2
1:3
Now, how do I go efficient with selecting all users, and with that, the groups they're member of? Do I have to execute 3 queries selecting all rows from all 3 tables, and fetch it with arrays in PHP, or is there a more effecient way to achieve this?
select u.*, g.group_name
from users u
inner join group_members gm on gm.user_id = u.user_id
inner join groups g on g.group_id = gm.group_id
where u.user_id = 123
This query should work if there are no null fields in group and group_members table
if there are null fields replace inner join with left join
select users.username, group.group_name
from users
inner join group_members on group_members.user_id = users.user_id
inner join groups on group.group_id = group_members.group_id
I have a query that selects data from 4 tables via joins, i want to also count the number rows in a fifth table containing a matching foreign key.
This is what my current query looks look like, and it doesnt work
"SELECT
ph.pheed_id,ph.user_id,ph.datetime,ph.repheeds,
ph.pheed,fav.id,fav.P_id,fav.datetime as stamp,
u.username,ava.avatar_small
COUNT(pheed_comments.comment_id) as comments
FROM favourite_pheeds fav
INNER JOIN pheeds ph ON ph.pheed_id=fav.P_id
INNER JOIN users u ON u.id=ph.user_id
INNER JOIN profiles pr ON pr.user_id=ph.user_id
LEFT JOIN user_avatars ava ON ava.avatar_id=pr.avatar
ORDER BY stamp DESC
LIMIT $offset,$limit";
How do i count the number rows in a fifth table containing a matching foreign key.
select ph.pheed_id,
ph.user_id,
ph.datetime,
ph.repheeds,
ph.pheed,
fav.id,
fav.P_id,
fav.datetime as stamp,
u.username,
ava.avatar_small,
coalesce(pcc.Count, 0) as comments_count
from favourite_pheeds fav
inner join pheeds ph on ph.pheed_id = fav.P_id
inner join users u on u.id = ph.user_id
inner join profiles pr on pr.user_id = ph.user_id
left join user_avatars ava on ava.avatar_id = pr.avatar
left outer join (
select pheed_id, count(*) as Count
from pheed_comments
group by pheed_id --took a guess at the column name here
) pcc on ph.pheed_id = pcc.pheed_id
order by stamp desc
LIMIT $offset, $limit