Multiple while loop in two queries - php

Question

I have 2 queries.
and 2 while loops.
my problem is that When I call out the values. only one query and one loop is correct. the other loop is displaying duplicate values.
here is what I have :
$query1=mysql_query("SELECT * FROM table1");
$query2=mysql_query("SELECT * FROM table2");
while($row1=mysql_fetch_array($query1)){
while($row2=mysql_fetch_array($query2)){
echo $row1['nameofattribute'] ;
echo $row2['nameofattribute'] ;
}
}
the output of query 1 is correct. but the output of query 2 is duplicate values.
for example :
query 1= $row1=2 $row1=3 $row1=4
query 2= $row2=3 $row2=3 $row2=3
instead it should be
query 1= $row1=2 $row1=3 $row1=4
query 2= $row2=1 $row2=2 $row2=3
on top is my simple translation of the code. here is my real code :
$query1 = mysql_query("SELECT remarks FROM passed_deliverable WHERE user_id=$uid && deliverable_category_id=4");
$query2=mysql_query("SELECT
deliverable_id, deliverable_title, deliverable_desc, adviser_id ,deliverable_category_id
FROM deliverable d
WHERE d.deliverable_category_id=4
&& EXISTS (
SELECT 'X'
FROM passed_deliverable pd
WHERE pd.deliverable_id = d.deliverable_id && user_id='".$_GET['edit']."' && adviser_id='".$_SESSION['user_id']."' ) ");
while($x=mysql_fetch_array($query1)){
while($deliverable=mysql_fetch_assoc($query2)){
echo "
{$deliverable['deliverable_desc']}
{$x['remarks']}
";

Answer 1

try this :
other answer or loop from mr. hellcode
it shows that you can also use array values instead of just using array
$a1 = 0[];
$a2 = 0[];
while($x=mysql_fetch_array($query1)) {
$a1[] = $x['remarks'];
}
while($deliverable=mysql_fetch_assoc($query2)) {
$a2[] = $deliverable['deliverable_desc'];
}
for($i=0; $i < count($a1) and $i < count($a2); $i++) {
echo "\n\n".$a2[$i]."\n".$a1[$i];
}

Answer 2

Assuming that you just want to combine the resulting rows of both tables in their appearing order (ignoring results that exceed the other table):
$a1 = array();
$a2 = array();
while($x=mysql_fetch_array($query1)) {
$a1[] = $x['remarks'];
}
while($deliverable=mysql_fetch_assoc($query2)) {
$a2[] = $deliverable['deliverable_desc'];
}
for($i=0; $i < count($a1) and $i < count($a2); $i++) {
echo "\n\n".$a2[$i]."\n".$a1[$i];
}

Answer 3

Deprecation of mysql_ functions . Please avoid mysql_ function . Anyway your query seems to unusual. because we don't see any WHERE clause in your queries . That means it will return duplicate value. Table1 each row will be check all rows of Table2 .